Equations balanced on the previous day | Equations balanced on the next day |
2 Na3CrO3 + 2 Ca(OH)2 + 3 Br2 = 2 CaCrO4 + 6 NaBr + 2 H2O
HI + KOH = H2OKI =>
HI + KOH = H2OKI
AgNO3 + K3[Fe(CN)6] = KNO3 + Ag3(Fe(CN)6) =>
3 AgNO3 + K3[Fe(CN)6] = 3 KNO3 + Ag3(Fe(CN)6)
KI + SnCl4 + HCl = I2 + H[SnCl3] + KCl =>
2 KI + SnCl4 + HCl = I2 + H[SnCl3] + 2 KCl
KC2H3O2 + CoSO4 = CoH3O2 + KC2SO4 =>
KC2H3O2 + CoSO4 = CoH3O2 + KC2SO4
K + OH + H2NO3 = KNO3 + H2OH =>
K + OH + H2NO3 = KNO3 + H2OH
KOH + PbCl2 = KCl + Pb(OH)2 =>
2 KOH + PbCl2 = 2 KCl + Pb(OH)2
ZnCrO4 + FeCO3 = ZnCO3 + FeCrO4 =>
ZnCrO4 + FeCO3 = ZnCO3 + FeCrO4
As2S3 + KNO3 + H2SO4 = NO2 + K2SO4 + K3AsO4 + H2O =>
As2S3 + 28 KNO3 + 8 H2SO4 = 28 NO2 + 11 K2SO4 + 2 K3AsO4 + 8 H2O
C2H5CHO + [Ag(NH3)2]OH = C2H5COOH + Ag + NH3 + H2O =>
C2H5CHO + 2[Ag(NH3)2]OH = C2H5COOH + 2 Ag + 4 NH3 + H2O
NaHCO3 + CH3CHOHCOOH = CH3CHOHCOONa + H2O + CO2 =>
NaHCO3 + CH3CHOHCOOH = CH3CHOHCOONa + H2O + CO2
KBrO3 + Na2S2O3 + KBr = Br2 + Na2SO4 + K2SO4 =>
5 KBrO3 + 3 Na2S2O3 + KBr = 3 Br2 + 3 Na2SO4 + 3 K2SO4
KIO3 + I2 + H2O = KIO4 + HI =>
KIO3 + I2 + H2O = KIO4 + 2 HI
NaHCO3 + CH3CHOHCOOH = CH3CHOHCOONa + H2O + CO2 =>
NaHCO3 + CH3CHOHCOOH = CH3CHOHCOONa + H2O + CO2
BeCl2 + K = KCl2 + Be =>
BeCl2 + K = KCl2 + Be
NaHCO3 + CH3CHOHCOOH = CH3CHOHCOONa + H2O + CO2 =>
NaHCO3 + CH3CHOHCOOH = CH3CHOHCOONa + H2O + CO2
NaHCO3 + CH3CHOHCOOH = CH3CHOHCOONa + H2O + CO2 =>
NaHCO3 + CH3CHOHCOOH = CH3CHOHCOONa + H2O + CO2
BeCl2 + K = KCl2 + Be =>
BeCl2 + K = KCl2 + Be
CuSO45H20 + Fe = FeSO45H20 + Cu =>
CuSO45H20 + Fe = FeSO45H20 + Cu
KBrO3 + Na2S2O3 + KBr = Br2 + Na2SO4 + K2SO4 =>
5 KBrO3 + 3 Na2S2O3 + KBr = 3 Br2 + 3 Na2SO4 + 3 K2SO4
Na3CrO4 + H2SO4 = Na2SO4 + Cr + Cr2O7 + H2O =>
14 Na3CrO4 + 21 H2SO4 = 21 Na2SO4 + 4 Cr + 5 Cr2O7 + 21 H2O
CH3OH3 + O2 = HCHO + H2O =>
CH3OH3 + O2 = HCHO + 2 H2O
NaHCO3 + CH3CHOHCOOH = CH3CHOHCOONa + H2O + CO2 =>
NaHCO3 + CH3CHOHCOOH = CH3CHOHCOONa + H2O + CO2
C3H5(OH)3 + C2HC3OOH = HCOOC3H5 + H2O =>
9 C3H5(OH)3 + C2HC3OOH = 8 HCOOC3H5 + 13 H2O
CH3OH3 + O2 = HCHO + H2O =>
CH3OH3 + O2 = HCHO + 2 H2O
HClO + CaH2O2 = H2O + CaCl2O2 =>
2 HClO + CaH2O2 = 2 H2O + CaCl2O2
H3(PO4) + (NH4)OH = HOH + NH4 + PO4 =>
H3(PO4) + 3(NH4)OH = 3 HOH + 3 NH4 + PO4
BeCl2 + K = KCl2 + Be =>
BeCl2 + K = KCl2 + Be
KBrO3 + Na2S2O3 + KBr = Br2 + Na2SO4 + K2SO4 =>
5 KBrO3 + 3 Na2S2O3 + KBr = 3 Br2 + 3 Na2SO4 + 3 K2SO4
Pb(OH)2 + HCOOH = Pb(COOH)2 + H2O =>
Pb(OH)2 + 2 HCOOH = Pb(COOH)2 + 2 H2O
CaCO3 + HNO3 = Ca(NO3)2 + CO2 + H2O =>
CaCO3 + 2 HNO3 = Ca(NO3)2 + CO2 + H2O
NaHCO3 + CH3CHOHCOOH = CH3CHOHCOONa + H2O + CO2 =>
NaHCO3 + CH3CHOHCOOH = CH3CHOHCOONa + H2O + CO2
Ga2(SO4)3 + NaOH = Na2SO4 + Ga(OH)3 =>
Ga2(SO4)3 + 6 NaOH = 3 Na2SO4 + 2 Ga(OH)3
CaSO4 + KPO = KSO4 + CaPO =>
CaSO4 + KPO = KSO4 + CaPO
CH3OH3 + O2 = HCHO + H2O =>
CH3OH3 + O2 = HCHO + 2 H2O
H2O + N4H4 = N4H5OH =>
H2O + N4H4 = N4H5OH
H2O + N4H4 = N4H5OH =>
H2O + N4H4 = N4H5OH
I{-} + Cr2O72{-} + H{+} = IO3{-} + Cr3{+} + H2O =>
427 I{-} + 18 Cr2O72{-} + 30 H{+} = 427 IO3{-} + 12 Cr3{+} + 15 H2O
(NH4)OH + AgNo3 = Ag(OH) + (NH4)No3 =>
(NH4)OH + AgNo3 = Ag(OH) + (NH4)No3
KMnO4 = K + Mn + O4 =>
KMnO4 = K + Mn + O4
CH3OH3 + O2 = HCHO + H2O =>
CH3OH3 + O2 = HCHO + 2 H2O
CH3OH3 + O2 = HCHO + H2O =>
CH3OH3 + O2 = HCHO + 2 H2O
Mg + HCl = MgCl2 + H2 =>
Mg + 2 HCl = MgCl2 + H2
BeCl2 + K = KCl2 + Be =>
BeCl2 + K = KCl2 + Be
H2SO4 + NH4C2H3O2 = H2H4C2H3O2 + NSO4 =>
H2SO4 + NH4C2H3O2 = H2H4C2H3O2 + NSO4
P4O10 + RbOH = Rb3PO4 + H2O =>
P4O10 + 12 RbOH = 4 Rb3PO4 + 6 H2O
Pd + NaCN + H2O + O2 = NaPd(CN)2 + NaOH =>
4 Pd + 8 NaCN + 2 H2O + O2 = 4 NaPd(CN)2 + 4 NaOH
Mg(NO3)2 + NH4NO3 + H3O = Mg + HNO3 =>
11 Mg(NO3)2 + 2 NH4NO3 + 6 H3O = 11 Mg + 26 HNO3
Pb + HNO3 = Pb(NO3)2 + NO + H2O =>
3 Pb + 8 HNO3 = 3 Pb(NO3)2 + 2 NO + 4 H2O
H3SO4 + H2O = H3O + SO4 =>
H3SO4 + 3 H2O = 3 H3O + SO4
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 01/05/24
Equations balanced on 02/04/23
Geben Sie uns Rückmeldungen zu Ihren Erfahrungen mit dem Programm zum Berechnen chemischer Reaktionsgleichungen.