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Chemische Gleichungen im Gleichgewicht auf02/04/24

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Mn2(CO)10 + Me5C5H = Me5C5Mn(CO)3 + H2 + CO =>
Mn2(CO)10 + 2 Me5C5H = 2 Me5C5Mn(CO)3 + H2 + 4 CO

(NH4)2S2O3 + CuSO4 = (NH4)2SO4 + CuS + SO2 =>
4(NH4)2S2O3 + 3 CuSO4 = 4(NH4)2SO4 + 3 CuS + 4 SO2

CaCO3(s) + HCl(l) = CaCl(s) + HCO3(l) =>
CaCO3(s) + HCl(l) = CaCl(s) + HCO3(l)

HBr + KClO3 = KCl + Br2 + H2O =>
6 HBr + KClO3 = KCl + 3 Br2 + 3 H2O

K2CrO4 + Hg2(NO3)2 = Hg2CrO4 + KNO3 =>
K2CrO4 + Hg2(NO3)2 = Hg2CrO4 + 2 KNO3

BaO + O = BaO2 =>
BaO + O = BaO2

K2Cr2O7 + KNO2 + H2SO4 = KNO3 + Cr2(SO4)2 + K2SO4 + H2O =>
K2Cr2O7 + 4 KNO2 + 3 H2SO4 = 4 KNO3 + Cr2(SO4)2 + K2SO4 + 3 H2O

Zn(OH)2 + AgNO3 = Zn3(NO3)2 + Ag(OH)3 =>
3 Zn(OH)2 + 2 AgNO3 = Zn3(NO3)2 + 2 Ag(OH)3

Br2Br6 + HNO3 = Br(NO3)3 + HBr =>
Br2Br6 + 6 HNO3 = 2 Br(NO3)3 + 6 HBr

Ca(NO3)2 + HCl2 = CaCl2 + H(NO3)2 =>
Ca(NO3)2 + HCl2 = CaCl2 + H(NO3)2

NaS + CuCl{2} = NaCl{2} + CuS =>
NaS + CuCl{2} = NaCl{2} + CuS

FeOHCl + HNO3 = Fe(NO3)2 + H2O + HCl =>
FeOHCl + 2 HNO3 = Fe(NO3)2 + H2O + HCl

NO2{-} + CrO4{2-} + H2O = NO3{-} + Cr{3+} + OH{-} =>
3 NO2{-} + 2 CrO4{2-} + 5 H2O = 3 NO3{-} + 2 Cr{3+} + 10 OH{-}

Br2Br6 + HNO3 = Br(NO3)3 + HBr =>
Br2Br6 + 6 HNO3 = 2 Br(NO3)3 + 6 HBr

NaCI = CI + Na =>
NaCI = CI + Na

Na(NO3) + Mg = Na + Mg(NO3)2 =>
2 Na(NO3) + Mg = 2 Na + Mg(NO3)2

FeOHCl + HNO3 = Fe(NO3)2 + H2O + HCl =>
FeOHCl + 2 HNO3 = Fe(NO3)2 + H2O + HCl

CH3COOH + Al(OH)3 = Al(CH3CO2)3 + H2O =>
3 CH3COOH + Al(OH)3 = Al(CH3CO2)3 + 3 H2O

Br2Br6 + HNO3 = Br(NO3)3 + HBr =>
Br2Br6 + 6 HNO3 = 2 Br(NO3)3 + 6 HBr

Ba(NO3)2 + Fe(NO3)3*9H2O = BaFe12O19 + HNO3 + H2O =>
Ba(NO3)2 + 12 Fe(NO3)3*9H2O = BaFe12O19 + 38 HNO3 + 89 H2O

KHO + Ba(NO3)2 = K(NO3)2 + BaHO =>
KHO + Ba(NO3)2 = K(NO3)2 + BaHO

SbOCl + H2S = Sb2S3 + HCl + H2O =>
2 SbOCl + 3 H2S = Sb2S3 + 2 HCl + 2 H2O

KOH + HCl = KCl + H2 + O =>
KOH + HCl = KCl + H2 + O

FeBO3 + C6H8O7 + NH4HCO3 = Fe(NH4)3(C6H5O7)2 + B2O3 + CO2 + H2O =>
2 FeBO3 + 4 C6H8O7 + 6 NH4HCO3 = 2 Fe(NH4)3(C6H5O7)2 + B2O3 + 6 CO2 + 9 H2O

P + Fe3O4 = P4O6 + Fe =>
8 P + 3 Fe3O4 = 2 P4O6 + 9 Fe

H{+} + U3O8 + NO3{-} = UO2{2+} + NO2 + H2O =>
8 H{+} + U3O8 + 2 NO3{-} = 3 UO2{2+} + 2 NO2 + 4 H2O

FeBO3 + C6H8O7 + NH4HCO3 = Fe(NH4)3(C6H5O7)2 + B2O3 + CO2 + H2O =>
2 FeBO3 + 4 C6H8O7 + 6 NH4HCO3 = 2 Fe(NH4)3(C6H5O7)2 + B2O3 + 6 CO2 + 9 H2O

Cl2(g) + NaBr(aq) = NaCl(aq) + Br2(s) =>
Cl2(g) + 2 NaBr(aq) = 2 NaCl(aq) + Br2(s)

ScO3 + Cl2 + S2Cl2 = ScCl3 + SOCl2 =>
2 ScO3 + 6 Cl2 + 3 S2Cl2 = 2 ScCl3 + 6 SOCl2

NH4Cl2 = NH3 + HCl2 =>
NH4Cl2 = NH3 + HCl2

[Cu(NH3)4]Cl2 + H2SO4 = CuCl2 + (NH4)2SO4 =>
[Cu(NH3)4]Cl2 + 2 H2SO4 = CuCl2 + 2(NH4)2SO4

MnS + Ba = Mn + BaS =>
MnS + Ba = Mn + BaS

CH2 + H = CH3 =>
CH2 + H = CH3

NaNO3 + Al2O3SiO2H4O2 + H2 = NaAlO2 + N2 + H2O + SiO2 =>
2 NaNO3 + Al2O3SiO2H4O2 + 5 H2 = 2 NaAlO2 + N2 + 7 H2O + SiO2

NaNO2 + H2SO4 + FeSO4 = Fe2(SO4)3 + N2O + Na2SO4 + H2O =>
2 NaNO2 + 3 H2SO4 + 4 FeSO4 = 2 Fe2(SO4)3 + N2O + Na2SO4 + 3 H2O

C21H2O6 + O2 = H2O + CO2 =>
2 C21H2O6 + 37 O2 = 2 H2O + 42 CO2

KOH + H3PO4 = PO4K + H3OH =>
KOH + H3PO4 = PO4K + H3OH

FeOHCl + HNO3 = Fe(NO3)2 + H2O + HCl =>
FeOHCl + 2 HNO3 = Fe(NO3)2 + H2O + HCl

Na2B4O7*10H2O + CH3OH + H2SO4 = B(OCH3)3 + Na2SO4 + H2O =>
Na2B4O7*10H2O + 12 CH3OH + H2SO4 = 4 B(OCH3)3 + Na2SO4 + 17 H2O

Ba(NO3)2 + (Na)2CrO4 = NaNO3 + (Ba)2(CrO4)2 =>
2 Ba(NO3)2 + 2(Na)2CrO4 = 4 NaNO3 + (Ba)2(CrO4)2

CaCO3 + HC2H3O2 = CO2 + H2O + CaH3C2O2 =>
8 CaCO3 + 9 HC2H3O2 = 10 CO2 + 6 H2O + 8 CaH3C2O2

(OH)2 + HClO3 = (ClO3)2 + H2O =>
(OH)2 + 2 HClO3 = (ClO3)2 + 2 H2O

Br2Br6 + HNO3 = Br(NO3)3 + HBr =>
Br2Br6 + 6 HNO3 = 2 Br(NO3)3 + 6 HBr

FeBO3 + C6H8O7 + NH4HCO3 = Fe(NH4)3(C6H5O7)2 + B2O3 + CO2 + H2O =>
2 FeBO3 + 4 C6H8O7 + 6 NH4HCO3 = 2 Fe(NH4)3(C6H5O7)2 + B2O3 + 6 CO2 + 9 H2O

K + Si = K4Si =>
4 K + Si = K4Si

K2CrO4 + H2O2 = K2CrO6 + H2O =>
K2CrO4 + 2 H2O2 = K2CrO6 + 2 H2O

CH4N2O + NaCl = CH4Cl + N2O + Na =>
CH4N2O + NaCl = CH4Cl + N2O + Na

CO2 + H2O = C6H12 + O6O2 =>
24 CO2 + 24 H2O = 4 C6H12 + 9 O6O2

CH3CH2CH2OH + O2 = CO2 + H2O =>
2 CH3CH2CH2OH + 9 O2 = 6 CO2 + 8 H2O

Fe2(SO4)3 + Ba(OH)2 = Fe(OH)3 + BaSO4 =>
Fe2(SO4)3 + 3 Ba(OH)2 = 2 Fe(OH)3 + 3 BaSO4

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