Equations balanced on the previous day | Equations balanced on the next day |
2 AuCl3 + 3 Na2S = 6 NaCl + Au2S3(s)
SO2 + Li2Se = SSe2 + Li2O =>
SO2 + 2 Li2Se = SSe2 + 2 Li2O
H2O + CO2 = OC6H12O6 + O2 =>
12 H2O + 12 CO2 = 2 OC6H12O6 + 11 O2
KOH + H3PO4 = K3PO4 + H2O =>
3 KOH + H3PO4 = K3PO4 + 3 H2O
KOH + NH4H2PO4 = K2HPO4 + NH3 + H2O =>
2 KOH + NH4H2PO4 = K2HPO4 + NH3 + 2 H2O
BaCrO4 + KOH = K2CrO4 + Ba(OH)2 =>
BaCrO4 + 2 KOH = K2CrO4 + Ba(OH)2
Ca2(CO3)2 + H3PO4 = Ca3(PO4)2 + CO2 + H2O =>
3 Ca2(CO3)2 + 4 H3PO4 = 2 Ca3(PO4)2 + 6 CO2 + 6 H2O
H3PO4 + NaOH = NaH2PO4 + H2O =>
H3PO4 + NaOH = NaH2PO4 + H2O
Na2B4O7*10H2O + HCl = NaCl + H3BO3 + H2O =>
Na2B4O7*10H2O + 2 HCl = 2 NaCl + 4 H3BO3 + 5 H2O
Na2B4O7*10H2O + HCl = NaCl + H3BO3 + H2O =>
Na2B4O7*10H2O + 2 HCl = 2 NaCl + 4 H3BO3 + 5 H2O
NaOH + H3(NO3)3 = Na(NO3) + H2O =>
3 NaOH + H3(NO3)3 = 3 Na(NO3) + 3 H2O
AlBr34 + Cl = AlCl + Br =>
AlBr34 + Cl = AlCl + 34 Br
BaCrO4 + KOH = K2CrO4 + Ba(OH)2 =>
BaCrO4 + 2 KOH = K2CrO4 + Ba(OH)2
Cl2O3 + NaOH = NaClO2 + H2O =>
Cl2O3 + 2 NaOH = 2 NaClO2 + H2O
C3H6 + O2 = CO2 + H2O =>
2 C3H6 + 9 O2 = 6 CO2 + 6 H2O
Co2O3 + S2 = Co3S4 + SO2 =>
12 Co2O3 + 25 S2 = 8 Co3S4 + 18 SO2
Na2B4O7*10H2O + HCl = NaCl + H3BO3 + H2O =>
Na2B4O7*10H2O + 2 HCl = 2 NaCl + 4 H3BO3 + 5 H2O
BaCrO4 + KOH = K2CrO4 + Ba(OH)2 =>
BaCrO4 + 2 KOH = K2CrO4 + Ba(OH)2
BaCrO4 + KOH = K2CrO4 + Ba(OH)2 =>
BaCrO4 + 2 KOH = K2CrO4 + Ba(OH)2
BaCrO4 + KOH = K2CrO4 + Ba(OH)2 =>
BaCrO4 + 2 KOH = K2CrO4 + Ba(OH)2
Zn + NiCl2 = Zn(Cl2) + Ni =>
Zn + NiCl2 = Zn(Cl2) + Ni
Na2B4O7*10H2O + HCl = NaCl + H3BO3 + H2O =>
Na2B4O7*10H2O + 2 HCl = 2 NaCl + 4 H3BO3 + 5 H2O
Al(ClO4)3 = Al3 + (ClO4) =>
3 Al(ClO4)3 = Al3 + 9(ClO4)
Li2CO3 + CrBr3 = LiBr + Cr2(CO3)3 =>
3 Li2CO3 + 2 CrBr3 = 6 LiBr + Cr2(CO3)3
Na2B4O7*10H2O + HCl = NaCl + H3BO3 + H2O =>
Na2B4O7*10H2O + 2 HCl = 2 NaCl + 4 H3BO3 + 5 H2O
Na2B4O7*10H2O + HCl = B(OH)3 + NaCl + H2O =>
Na2B4O7*10H2O + 2 HCl = 4 B(OH)3 + 2 NaCl + 5 H2O
Bi(OH)3 + KCN = BiCN + K(OH)3 =>
Bi(OH)3 + KCN = BiCN + K(OH)3
Na2B4O7*10H2O + HCl = NaCl + H3BO3 + H2O =>
Na2B4O7*10H2O + 2 HCl = 2 NaCl + 4 H3BO3 + 5 H2O
C3H7BrMg + CO2 = C4H7O2MgBr =>
C3H7BrMg + CO2 = C4H7O2MgBr
FeS + HCl = FeCl2 + H2S =>
FeS + 2 HCl = FeCl2 + H2S
NH3 + CaOH = NH2{-} + Ca{+} + H2O =>
NH3 + CaOH = NH2{-} + Ca{+} + H2O
Na2B4O7*10H2O + HCl = NaCl + H3BO3 + H2O =>
Na2B4O7*10H2O + 2 HCl = 2 NaCl + 4 H3BO3 + 5 H2O
KClO3 + HCl + FeCl2 = FeCl3 + KCl + H2O =>
KClO3 + 6 HCl + 6 FeCl2 = 6 FeCl3 + KCl + 3 H2O
P + {2} = P{4}0{10} =>
P + 2{2} = P{4}0{10}
AlNaOH2O = NaAlO2H2 =>
AlNaOH2O = NaAlO2H2
SO2 + Li2Se = SSe2 + Li2O =>
SO2 + 2 Li2Se = SSe2 + 2 Li2O
Fe2O3 + C = Fe + CO2 =>
2 Fe2O3 + 3 C = 4 Fe + 3 CO2
K2SO4 + MnSO4 + H2O + Cl2 = KCl + H2SO4 + MnO2 =>
K2SO4 + MnSO4 + 2 H2O + Cl2 = 2 KCl + 2 H2SO4 + MnO2
C2H4 + O2 = CO2 + H2O =>
C2H4 + 3 O2 = 2 CO2 + 2 H2O
K2Cr2O7 + H2SO4 + NaNO2 = Cr2(SO4)3 + H2O + K2SO4 + NaNO3 =>
K2Cr2O7 + 4 H2SO4 + 3 NaNO2 = Cr2(SO4)3 + 4 H2O + K2SO4 + 3 NaNO3
C3H8 + O2 = CO2 + H2O =>
C3H8 + 5 O2 = 3 CO2 + 4 H2O
HClO4 + P4O10 = H3PO4 + Cl2O7 =>
12 HClO4 + P4O10 = 4 H3PO4 + 6 Cl2O7
N2 + H2 = NH3 =>
N2 + 3 H2 = 2 NH3
Na2B4O7*10H2O + HCl = NaCl + H3BO3 + H2O =>
Na2B4O7*10H2O + 2 HCl = 2 NaCl + 4 H3BO3 + 5 H2O
Hydrochloricacid + bariumhydroxide = bariumchloride + water =>
2 HCl + Ba(OH)2 = BaCl2 + 2 H2O
CaCO3(s) + HC2H3O2(aq) = CO2(g) + H2O(l) + Ca(C3H2O2)2 =>
4 CaCO3(s) + 11 HC2H3O2(aq) = 2 CO2(g) + 14 H2O(l) + 4 Ca(C3H2O2)2
Al2(SO4)3(aq) + NH4OH(aq) = Al(OH)3(aq) + (NH4)2SO4(aq) =>
Al2(SO4)3(aq) + 6 NH4OH(aq) = 2 Al(OH)3(aq) + 3(NH4)2SO4(aq)
MnO2 + K2CO3 + KNO3 = CO2 + K2MnO4 + N2 =>
5 MnO2 + 4 K2CO3 + 2 KNO3 = 4 CO2 + 5 K2MnO4 + N2
BaCrO4 + KOH = K2CrO4 + Ba(OH)2 =>
BaCrO4 + 2 KOH = K2CrO4 + Ba(OH)2
N2 + H2 = NH3 =>
N2 + 3 H2 = 2 NH3
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 01/05/24
Equations balanced on 02/04/23
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