Equations balanced on the previous day | Equations balanced on the next day |
Zr + 4 CuO = ZrO2 + 2 Cu2O
HCl(aq) + NaCH3COO(aq) = CH3COOH(aq) + NaCl(aq) =>
HCl(aq) + NaCH3COO(aq) = CH3COOH(aq) + NaCl(aq)
NH3(g) + O2(g) = N2(g) + H2O(g) =>
4 NH3(g) + 3 O2(g) = 2 N2(g) + 6 H2O(g)
H2SiO3 + Fe(OH)3 = Fe(OH)SiO3 + H2O =>
H2SiO3 + Fe(OH)3 = Fe(OH)SiO3 + 2 H2O
As(OH)3 + (H)2SO4 = (As)2(SO4)3 + H2O =>
2 As(OH)3 + 3(H)2SO4 = (As)2(SO4)3 + 6 H2O
K2Cr2O7 + HCl = KCl + CrCl3 + H2O + Cl2 =>
K2Cr2O7 + 14 HCl = 2 KCl + 2 CrCl3 + 7 H2O + 3 Cl2
K2Cr2O7 + HCl = KCl + CrCl3 + H2O + Cl2 =>
K2Cr2O7 + 14 HCl = 2 KCl + 2 CrCl3 + 7 H2O + 3 Cl2
C5H10 + O2 = CO2 + H2 =>
C5H10 + 5 O2 = 5 CO2 + 5 H2
[Ag(NH3)2]OH + C5H6(OH)5CHO = Ag + C5H6(OH)5COONH4 + NH3 + H2O =>
2[Ag(NH3)2]OH + C5H6(OH)5CHO = 2 Ag + C5H6(OH)5COONH4 + 3 NH3 + H2O
SrNO2 = Sr + NO2 =>
SrNO2 = Sr + NO2
VO3{-} + Zn + H{+} = V2 + Zn{+2} + H2O =>
2 VO3{-} + 5 Zn + 12 H{+} = V2 + 5 Zn{+2} + 6 H2O
FeI3 + Br2 = FeBr + I2 =>
2 FeI3 + Br2 = 2 FeBr + 3 I2
C5H8 + Br2 = C5H8Br4 =>
C5H8 + 2 Br2 = C5H8Br4
Ba + NaOH = BaOH + Na =>
Ba + NaOH = BaOH + Na
Fe(NO3)3 + Li(OH) = Fe(OH)3 + LiNO3 =>
Fe(NO3)3 + 3 Li(OH) = Fe(OH)3 + 3 LiNO3
Pb(NO3)2 + H2SO4 = (PbSO4) + (HNO3) =>
Pb(NO3)2 + H2SO4 = (PbSO4) + 2(HNO3)
C18H34O2 + HNO3 = CO2 + H2O + N =>
5 C18H34O2 + 102 HNO3 = 90 CO2 + 136 H2O + 102 N
KMnO4 + H2SO4 + CH3CH2OH = MnSO4 + K2SO4 + H2O + CH3COOH =>
4 KMnO4 + 6 H2SO4 + 5 CH3CH2OH = 4 MnSO4 + 2 K2SO4 + 11 H2O + 5 CH3COOH
NaCl + AlCl3 = NaAl + Cl2 =>
NaCl + AlCl3 = NaAl + 2 Cl2
C18H34O2 + HNO3 = CO2 + H2O + N =>
5 C18H34O2 + 102 HNO3 = 90 CO2 + 136 H2O + 102 N
Ca + HCl = CaCl2 + H2 =>
Ca + 2 HCl = CaCl2 + H2
C18H34O2 + HNO3 = CO2 + H2O + N =>
5 C18H34O2 + 102 HNO3 = 90 CO2 + 136 H2O + 102 N
C18H34O2 + HNO3 = CO2 + H2O + N =>
5 C18H34O2 + 102 HNO3 = 90 CO2 + 136 H2O + 102 N
K2Cr2O7 + H2SO4 + K2C2O4 = K2SO4 + CrSO4 + H2O + CO2 =>
K2Cr2O7 + 7 H2SO4 + 4 K2C2O4 = 5 K2SO4 + 2 CrSO4 + 7 H2O + 8 CO2
H3PO4 + K2CO3 = KH2PO4 + H2O + CO2 =>
2 H3PO4 + K2CO3 = 2 KH2PO4 + H2O + CO2
Mg(Br)2 + KOH = KBr + Mg(OH)2 =>
Mg(Br)2 + 2 KOH = 2 KBr + Mg(OH)2
Au + CN{-} + O2 + H2O = Au(CN)4{-} + OH{-} =>
4 Au + 16 CN{-} + 3 O2 + 6 H2O = 4 Au(CN)4{-} + 12 OH{-}
Ca + Hg(OH)2 = Hg + Ca(OH)2 =>
Ca + Hg(OH)2 = Hg + Ca(OH)2
S + H2O = SO4 + SH2 =>
5 S + 4 H2O = SO4 + 4 SH2
BaO2 + HCl = BaCl2 + H2O2 =>
BaO2 + 2 HCl = BaCl2 + H2O2
BaO2 + HCl = BaCl2 + H2O2 =>
BaO2 + 2 HCl = BaCl2 + H2O2
NaOH + H2O = NaOH2{+} + OH{-} =>
NaOH + H2O = NaOH2{+} + OH{-}
A12O3 + C = A1 + CO2 =>
2 A12O3 + 3 C = 24 A1 + 3 CO2
Au + CN{-} + O2 + H2O = Au(CN)4{-} + OH{-} =>
4 Au + 16 CN{-} + 3 O2 + 6 H2O = 4 Au(CN)4{-} + 12 OH{-}
NH3 + K2CO3 + C = KCN + H2O =>
2 NH3 + K2CO3 + C = 2 KCN + 3 H2O
*C20H42 + O2 = CO2 + H2O =>
2*C20H42 + 61 O2 = 40 CO2 + 42 H2O
K3P + BeI2 = KI + P2Be3 =>
2 K3P + 3 BeI2 = 6 KI + P2Be3
CH3CH3 + KAl(SO4)2*12(H2O) = CH3CH3*HOH + KAl(SO4)2 =>
12 CH3CH3 + KAl(SO4)2*12(H2O) = 12 CH3CH3*HOH + KAl(SO4)2
Sr + HNO3 = Sr(NO3)2 + H2O + N2O =>
4 Sr + 10 HNO3 = 4 Sr(NO3)2 + 5 H2O + N2O
C100H203 + O = CO + H2O =>
2 C100H203 + 403 O = 200 CO + 203 H2O
C18H34O2 + HNO3 = CO2 + H2O + N =>
5 C18H34O2 + 102 HNO3 = 90 CO2 + 136 H2O + 102 N
Pb3(PO4)2 + H3O = H2O + HPO4 + Pb =>
Pb3(PO4)2 + 2 H3O = 2 H2O + 2 HPO4 + 3 Pb
C18H34O2 + HNO3 = CO2 + H2O + N =>
5 C18H34O2 + 102 HNO3 = 90 CO2 + 136 H2O + 102 N
F + KI = KF + I2 =>
2 F + 2 KI = 2 KF + I2
H2SO4 + Na(OH)2 = Na2(SO4)2 + H2O =>
2 H2SO4 + 2 Na(OH)2 = Na2(SO4)2 + 4 H2O
HCl + sodiumhydroxide = sodiumchloride + water =>
HCl + NaOH = NaCl + H2O
KI + I2 = KII2 = K{+} + I3{-} =>
KI + I2 = KII2
Ba(CIO3)2 + H2SO4 = BaSO4 + H2(CIO3)2 =>
Ba(CIO3)2 + H2SO4 = BaSO4 + H2(CIO3)2
C18H34O2 + HNO3 = CO2 + H2O + N =>
5 C18H34O2 + 102 HNO3 = 90 CO2 + 136 H2O + 102 N
ZnS + HNO3 = H2O + NO + ZnSO3 =>
ZnS + 2 HNO3 = H2O + 2 NO + ZnSO3
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 01/05/24
Equations balanced on 02/04/23
Geben Sie uns Rückmeldungen zu Ihren Erfahrungen mit dem Programm zum Berechnen chemischer Reaktionsgleichungen.