Equations balanced on the previous day | Equations balanced on the next day |
2 KN3 = 2 K + 3 N2
BeCl2 + Na2CO3 + H2O = Be(OH)2 + CO2 + NaCl =>
BeCl2 + Na2CO3 + H2O = Be(OH)2 + CO2 + 2 NaCl
HI + FeCO3 = FeI + HCO3 =>
HI + FeCO3 = FeI + HCO3
Ag2S + H3PO4 = Ag3PO4 + H2S =>
3 Ag2S + 2 H3PO4 = 2 Ag3PO4 + 3 H2S
BeCl2 + Na2CO3 + H2O = (BeOH)2CO3 + NaCl + NaHCO3 =>
2 BeCl2 + 3 Na2CO3 + 2 H2O = (BeOH)2CO3 + 4 NaCl + 2 NaHCO3
C3H6O + H2 = C3H7OH =>
C3H6O + H2 = C3H7OH
Ba + O2 = BaO =>
2 Ba + O2 = 2 BaO
FeCl3 + KSCN = Fe(SCN)3 + KCl =>
FeCl3 + 3 KSCN = Fe(SCN)3 + 3 KCl
ClOOCl = Cl + O =>
ClOOCl = 2 Cl + 2 O
XAgNO3 + XNa2SO4 = XNaNO3 + XAg2SO4 =>
2 XAgNO3 + XNa2SO4 = 2 XNaNO3 + XAg2SO4
Cl(aq) + Ag(aq) = AgCl2(s) =>
2 Cl(aq) + Ag(aq) = AgCl2(s)
CH3CH3 + KMnO4 + H2SO4 = CH3COOH + K2SO4 + MnSO4 + H2O =>
5 CH3CH3 + 6 KMnO4 + 9 H2SO4 = 5 CH3COOH + 3 K2SO4 + 6 MnSO4 + 14 H2O
As2O3 + NO3 = AsO4 + N2O3 =>
3 As2O3 + 10 NO3 = 6 AsO4 + 5 N2O3
C2H5NO2 + O2 = NH3 + CO2 + H2O =>
2 C2H5NO2 + 3 O2 = 2 NH3 + 4 CO2 + 2 H2O
Li3N + H2O = NH3 + LiOH =>
Li3N + 3 H2O = NH3 + 3 LiOH
Ba + O2 = BaO2 =>
Ba + O2 = BaO2
CO2 + C2H6 = C2H4 + H2O =>
2 CO2 + 6 C2H6 = 7 C2H4 + 4 H2O
SO2 + IO3{-} = SO4 + I{-} =>
3 SO2 + 2 IO3{-} = 3 SO4 + 2 I{-}
Pb(NO3)2(aq) + KOH(aq) = KNO3 + Pb(OH)2 =>
Pb(NO3)2(aq) + 2 KOH(aq) = 2 KNO3 + Pb(OH)2
K2Cr2O7(s) + NaCl(s) + H2SO4(aq) = Cl2(g) + H2O(l) + KSO4(aq) + Na2SO4(aq) + CrSO4(aq) =>
K2Cr2O7(s) + 6 NaCl(s) + 7 H2SO4(aq) = 3 Cl2(g) + 7 H2O(l) + 2 KSO4(aq) + 3 Na2SO4(aq) + 2 CrSO4(aq)
S + O2 = SO2 =>
S + O2 = SO2
Cu(CH3COO)2 + Na3PO4 = Na(CH3COO) + Cu3(PO4)2 =>
3 Cu(CH3COO)2 + 2 Na3PO4 = 6 Na(CH3COO) + Cu3(PO4)2
TeF6 + H2O = HF + TeO3 =>
TeF6 + 3 H2O = 6 HF + TeO3
CaS5 + HCl = H2S + Ca + Cl2 =>
CaS5 + 10 HCl = 5 H2S + Ca + 5 Cl2
Na[Al(OH)4] + SO2 = Na2SO3 + Al(OH)3 + H2O =>
2 Na[Al(OH)4] + SO2 = Na2SO3 + 2 Al(OH)3 + H2O
KOH + Fe = K + FeOH =>
KOH + Fe = K + FeOH
Cu(CH3COO)2 + Na3PO4 = Na(CH3COO) + Cu3(PO4)2 =>
3 Cu(CH3COO)2 + 2 Na3PO4 = 6 Na(CH3COO) + Cu3(PO4)2
CoBr + NaS = CoNa + BrS =>
CoBr + NaS = CoNa + BrS
Na2CO3 + H3O{+}{+} = H2CO3 + H2O + Na{+} =>
Na2CO3 + 2 H3O{+}{+} = H2CO3 + 2 H2O + 2 Na{+}
Zn + HNO3 = Zn(NO3)2 + H2 =>
Zn + 2 HNO3 = Zn(NO3)2 + H2
C12H22O11 + KMnO4 = CO2 + K2CO3 + MnO2 + H2O =>
C12H22O11 + 16 KMnO4 = 4 CO2 + 8 K2CO3 + 16 MnO2 + 11 H2O
H2 + Au = HAu =>
H2 + 2 Au = 2 HAu
MgSO3(s) + HCl(aq) = MgCl2(aq) + H2O(l) + SO2(g) =>
MgSO3(s) + 2 HCl(aq) = MgCl2(aq) + H2O(l) + SO2(g)
NH3 + P2O5 + H2O = (NH4)3PO4 =>
6 NH3 + P2O5 + 3 H2O = 2(NH4)3PO4
NaMnO4 + H2SO4 = Na2SO4 + MnSO4 + O + H2O =>
2 NaMnO4 + 3 H2SO4 = Na2SO4 + 2 MnSO4 + 5 O + 3 H2O
H{+} + Cr2O7{2-} + SO2 = SO4{2-} + Cr{3+} + H2O =>
2 H{+} + Cr2O7{2-} + 3 SO2 = 3 SO4{2-} + 2 Cr{3+} + H2O
HNO3 + CaCO3 = CO2 + H2O + CaN2O6 =>
2 HNO3 + CaCO3 = CO2 + H2O + CaN2O6
Cu(CH3COO)2 + Na3PO4 = Na(CH3COO) + Cu3(PO4)2 =>
3 Cu(CH3COO)2 + 2 Na3PO4 = 6 Na(CH3COO) + Cu3(PO4)2
[Cr(H2O)6] + NaOH = Na + Cr(OH)3 + H2O =>
[Cr(H2O)6] + 3 NaOH = 3 Na + Cr(OH)3 + 6 H2O
BeSO4 + (NH4)2CO3 + H2O = (BeOH)2CO3 + (NH4)2SO4 + SO3 =>
2 BeSO4 + (NH4)2CO3 + H2O = (BeOH)2CO3 + (NH4)2SO4 + SO3
Na2O2 + H2 = NaOH =>
Na2O2 + H2 = 2 NaOH
Cu2O + FeS = Cu2S + FeO =>
Cu2O + FeS = Cu2S + FeO
K + SO2 = K2SO3 + K2S2O3 =>
4 K + 3 SO2 = K2SO3 + K2S2O3
Cu(CH3COO)2 + Na3PO4 = CuPO4 + Na3(CH3COO)2 =>
Cu(CH3COO)2 + Na3PO4 = CuPO4 + Na3(CH3COO)2
C8H10 + O2 = C8H6O4 + H2O =>
C8H10 + 3 O2 = C8H6O4 + 2 H2O
LiHCO3 + HC2H3O2 = LiC2H3O2 + H2CO3 =>
LiHCO3 + HC2H3O2 = LiC2H3O2 + H2CO3
NH2OH = H3N + N2 + H2O =>
3 NH2OH = H3N + N2 + 3 H2O
Cu(CH3COO)2 + Na3PO4 = Na(CH3COO) + Cu3(PO4)2 =>
3 Cu(CH3COO)2 + 2 Na3PO4 = 6 Na(CH3COO) + Cu3(PO4)2
Cu(CH3COO)2 + Na3PO4 = Na(CH3COO) + Cu3(PO4)2 =>
3 Cu(CH3COO)2 + 2 Na3PO4 = 6 Na(CH3COO) + Cu3(PO4)2
Al(NO3)3 + Na2PO4 = Al2(PO4)3 + NaNO3 =>
2 Al(NO3)3 + 3 Na2PO4 = Al2(PO4)3 + 6 NaNO3
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 12/22/23
Equations balanced on 01/21/23
Geben Sie uns Rückmeldungen zu Ihren Erfahrungen mit dem Programm zum Berechnen chemischer Reaktionsgleichungen.