Equations balanced on the previous day | Equations balanced on the next day |
2 C17H35CO2Na + CaSO4 = (C17H35CO2)2Ca + Na2SO4
NaOH + H3PO4 = Na3PO4 + HOH1 =>
3 NaOH + H3PO4 = Na3PO4 + 3 HOH1
Al2(SO4)3 + Ca(OH)2 = Al(OH)2 + Ca2(SO4)3 =>
Al2(SO4)3 + 2 Ca(OH)2 = 2 Al(OH)2 + Ca2(SO4)3
CH3CH2OH + K2Cr2O7 + H2SO4 = Cr2(SO4)3 + K2SO4 + CH3CH2CH2COH + H2O =>
6 CH3CH2OH + K2Cr2O7 + 4 H2SO4 = Cr2(SO4)3 + K2SO4 + 3 CH3CH2CH2COH + 10 H2O
CaCl2 = Ca + Cl2 = NaHCO =>
CaCl2 = Ca + Cl2
HVO3 + Zn + HCl = VCl2 + ZnCl2 + H2O =>
2 HVO3 + 3 Zn + 10 HCl = 2 VCl2 + 3 ZnCl2 + 6 H2O
NH4Cl + Hg2(NO3)2 = Hg2Cl + NH4(NO3)2 =>
NH4Cl + Hg2(NO3)2 = Hg2Cl + NH4(NO3)2
K + H2O = H3O + KOH =>
K + 2 H2O = H3O + KOH
MgO + H2O2 = Mg(OH)2 + O =>
MgO + H2O2 = Mg(OH)2 + O
Al2(SO4)3 = Al + S + O4 =>
Al2(SO4)3 = 2 Al + 3 S + 3 O4
NH4NO3 + Mg(OH)2 = Mg(NO3)2 + NH4OH =>
2 NH4NO3 + Mg(OH)2 = Mg(NO3)2 + 2 NH4OH
CO2 + Pb2O3 = PbCO3 + O2 =>
4 CO2 + 2 Pb2O3 = 4 PbCO3 + O2
CH20(l) + O2(g) = H20(l) + CO2(g) =>
CH20(l) + O2(g) = H20(l) + CO2(g)
NH4CO3 + Ba(OH)2 = NH3 + H2O + Ba(CO3)2 =>
2 NH4CO3 + Ba(OH)2 = 2 NH3 + 2 H2O + Ba(CO3)2
(NH4)2S + PB(NO3)2 = NH4NO3 + PBS =>
(NH4)2S + PB(NO3)2 = 2 NH4NO3 + PBS
[Cr(N2H4CO)6]4[Cr(CN)6]3 + KMnO4 + H2SO4 = K2Cr2O7 + CO2 + KNO3 + MnSO4 + K2SO4 + H2O =>
10[Cr(N2H4CO)6]4[Cr(CN)6]3 + 1176 KMnO4 + 1399 H2SO4 = 35 K2Cr2O7 + 420 CO2 + 660 KNO3 + 1176 MnSO4 + 223 K2SO4 + 1879 H2O
Ta + HF + HNO3 = H2[TaF5] + NO + H2O =>
Ta + 5 HF + HNO3 = H2[TaF5] + NO + 2 H2O
[Co(H2O)6]Cl2 + NaN3 + NH4Cl + NH3 = [Co(NH3)5N3]Cl2 + NaCl + H2O = [Co(H2O)6]Cl2 + NaN3 + NH4Cl + NH3 + [Co(NH3)5N3]Cl2 + NaCl + H2O =>
8[Co(H2O)6]Cl2 + 9 NaN3 + 9 NH4Cl + 28 NH3 = 8[Co(NH3)5N3]Cl2 + 9 NaCl + 48 H2O
FeCl + KI = KCl + FeI =>
FeCl + KI = KCl + FeI
AlCl3 + NH4Fl = AlFl3 + NH4Cl =>
AlCl3 + 3 NH4Fl = AlFl3 + 3 NH4Cl
CaH + H3PO4 = CaPO2 + H2O =>
CaH + H3PO4 = CaPO2 + 2 H2O
NH4Cl + CH2O = CH3NH2HCl + H2O + CO2 =>
2 NH4Cl + 3 CH2O = 2 CH3NH2HCl + H2O + CO2
Zn + Pb(NO2)2 = Zn2(NO2)2 + Pb =>
2 Zn + Pb(NO2)2 = Zn2(NO2)2 + Pb
(NH4)2SO4 + CaCl2 = NH4Cl + CaSO4 =>
(NH4)2SO4 + CaCl2 = 2 NH4Cl + CaSO4
LiOH + CaCO3 = Ca(OH)2 + Li2CO3 =>
2 LiOH + CaCO3 = Ca(OH)2 + Li2CO3
N2(g) + O2 + H2O = HNO3 =>
2 N2(g) + 5 O2 + 2 H2O = 4 HNO3
HCl2 + F3 = FCl3 + H2 =>
18 HCl2 + 4 F3 = 12 FCl3 + 9 H2
Co(ClO4)2 + Mg = Mg(ClO4)2 + Co =>
Co(ClO4)2 + Mg = Mg(ClO4)2 + Co
FeO + H2SO4 = Fe2SO43 + SO2 + H2O =>
2 FeO + 39 H2SO4 = Fe2SO43 + 38 SO2 + 39 H2O
K + Cl = KCl =>
K + Cl = KCl
K + Cl = KCl =>
K + Cl = KCl
H2NCO2NH4 = CO2 + NH3 =>
H2NCO2NH4 = CO2 + 2 NH3
H{+} + (Cr(NH2CONH2)6)4(Cr(CN)6)3 + MnO4{-} = Cr2O7{-} + CO2 + NO3{-} + Mn{+2} + H2O =>
2854 H{+} + 10(Cr(NH2CONH2)6)4(Cr(CN)6)3 + 1183 MnO4{-} = 35 Cr2O7{-} + 420 CO2 + 660 NO3{-} + 1183 Mn{+2} + 1907 H2O
H2O = H9 + O2999999999 =>
26999999991 H2O = 5999999998 H9 + 9 O2999999999
Co(s) + Br2(s) = CoBr2(s) =>
Co(s) + Br2(s) = CoBr2(s)
KBr + MnO2 + H2SO4 = K2SO4 + MnSO4 + Br2 + H2O =>
2 KBr + MnO2 + 2 H2SO4 = K2SO4 + MnSO4 + Br2 + 2 H2O
K + Cl = KCl =>
K + Cl = KCl
C6H14 + O2 = CO2 + H2O =>
2 C6H14 + 19 O2 = 12 CO2 + 14 H2O
H2CO3 + KOH = (K)2CO3 + H2O =>
H2CO3 + 2 KOH = (K)2CO3 + 2 H2O
SiCl4 + H2O = H4SiO4 + HCl =>
SiCl4 + 4 H2O = H4SiO4 + 4 HCl
FeS2 = SFe2S3 =>
2 FeS2 = SFe2S3
Fe3CO3 + CO = Fe + CO2 =>
Fe3CO3 + CO = 3 Fe + 2 CO2
AgNO3 + Mn(NO3)2 + NH4OH = Mn(OH)4 + Ag + NH4NO3 =>
2 AgNO3 + Mn(NO3)2 + 4 NH4OH = Mn(OH)4 + 2 Ag + 4 NH4NO3
NH3 + O2 = NO + H2O(l) =>
4 NH3 + 5 O2 = 4 NO + 6 H2O(l)
KOH + H2CrO4 = K2CrO4 + H2O =>
2 KOH + H2CrO4 = K2CrO4 + 2 H2O
PbO2(s) + Sb(s) + NaOH(aq) = PbO(s) + NaSbO2(aq) + H2O(l) =>
3 PbO2(s) + 2 Sb(s) + 2 NaOH(aq) = 3 PbO(s) + 2 NaSbO2(aq) + H2O(l)
H4As4 + Ca(OH)2 = CaH4OAs4 + H2O =>
H4As4 + Ca(OH)2 = CaH4OAs4 + H2O
Da2 + H2 = DaH =>
Da2 + H2 = 2 DaH
C4H10 + O2 = CO2 + H2O2 =>
C4H10 + 9 O2 = 4 CO2 + 5 H2O2
KMnO4 + NaOH + FeSO4 = Na2SO4 + Fe(OH)3 + K2MnO4 + Na2MnO4 =>
2 KMnO4 + 6 NaOH + 2 FeSO4 = 2 Na2SO4 + 2 Fe(OH)3 + K2MnO4 + Na2MnO4
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 12/22/23
Equations balanced on 01/21/23
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