| Am Vortag ausgeglichene Gleichungen | Am nächsten Tag ausgeglichene Gleichungen |
SnCl2H2O + K2Cr2O7 = Sn + Cr2O7 + 2 KCl + H2O
Y2O3 + CuO + BaCO3 + O2 = Ba2YCu3O9 + CO3 =>
2 Y2O3 + 12 CuO + 8 BaCO3 + 9 O2 = 4 Ba2YCu3O9 + 8 CO3
AgNO3 + H2O = HNO3 + O2 + Ag =>
4 AgNO3 + 2 H2O = 4 HNO3 + O2 + 4 Ag
C22H42O2 + CH3OH = C3H8O3 + C17H35COOH3 =>
8 C22H42O2 + 25 CH3OH = 7 C3H8O3 + 10 C17H35COOH3
CsI(aq) + LiOH(aq) = LiI() + CsOH() =>
CsI(aq) + LiOH(aq) = LiI() + CsOH()
Al + KOH + H2O + H2SO4 = H2 + KAl(SO4)2(H2O)12 =>
2 Al + 2 KOH + 22 H2O + 4 H2SO4 = 3 H2 + 2 KAl(SO4)2(H2O)12
HBr + B(OH)3 = BBr3 + H2O =>
3 HBr + B(OH)3 = BBr3 + 3 H2O
NO2 + H2O = HNO3 + HNO2 =>
2 NO2 + H2O = HNO3 + HNO2
Mg(s) + NaCl(aq) = Na + MgCl2 =>
Mg(s) + 2 NaCl(aq) = 2 Na + MgCl2
HCl(aq) + NaHCO3(aq) = H2CO3(aq) + NaCl(aq) =>
HCl(aq) + NaHCO3(aq) = H2CO3(aq) + NaCl(aq)
H3PO4 + Li2 + O = Li3PO4 + H2O =>
2 H3PO4 + 3 Li2 + 3 O = 2 Li3PO4 + 3 H2O
K[Cr(OH)4] = Cr(OH)3 + KOH =>
K[Cr(OH)4] = Cr(OH)3 + KOH
Cr(OH)3 + KOH = K(Cr(OH)4) =>
Cr(OH)3 + KOH = K(Cr(OH)4)
C12H22O11 + HNO3 = C2H2O4 + H2O + NO2 =>
C12H22O11 + 36 HNO3 = 6 C2H2O4 + 23 H2O + 36 NO2
CaCl2 + (NH4)2CO3 = (NH4)4Cl2 + Ca(CO3)2 =>
CaCl2 + 2(NH4)2CO3 = (NH4)4Cl2 + Ca(CO3)2
B(ClO3)3 = BCl3 + O2 =>
2 B(ClO3)3 = 2 BCl3 + 9 O2
NaO2{-2} = NaO{-2} + O2 =>
2 NaO2{-2} = 2 NaO{-2} + O2
K2MnO4 + H2SO4 = KMnO4 + MnO2 + K2SO4H2O =>
3 K2MnO4 + 2 H2SO4 = 2 KMnO4 + MnO2 + 2 K2SO4H2O
C2H5O2 + O2 = H2O + CO2 =>
4 C2H5O2 + 9 O2 = 10 H2O + 8 CO2
Mg + Pb3(CO3)4 = Pb + Mg(CO3) =>
4 Mg + Pb3(CO3)4 = 3 Pb + 4 Mg(CO3)
FeS + O = Fe203 + SO2 =>
203 FeS + 406 O = Fe203 + 203 SO2
H3BO3(s) = B2O3(s) + H2O =>
2 H3BO3(s) = B2O3(s) + 3 H2O
S8 + AsF5 = S16(AsF6)2 + AsF3 =>
2 S8 + 3 AsF5 = S16(AsF6)2 + AsF3
N2Cl4CH4 = N6H12Cl12C3 =>
3 N2Cl4CH4 = N6H12Cl12C3
Fe(NO3)3 + Mg2S = Fe2S3 + MgNO3 =>
2 Fe(NO3)3 + 3 Mg2S = Fe2S3 + 6 MgNO3
NH2CONH3 + O2 = CO2 + H2O + NO2 =>
4 NH2CONH3 + 15 O2 = 4 CO2 + 10 H2O + 8 NO2
NiSO4 + Na3PO4 = NiNa3 + SO4PO4 =>
NiSO4 + Na3PO4 = NiNa3 + SO4PO4
Al(OH)3 + H2CO3 = Al2(CO3)3(s) + H2O(l) =>
2 Al(OH)3 + 3 H2CO3 = Al2(CO3)3(s) + 6 H2O(l)
NaCl + H2SO4 = Na2SO4 + HCl = =>
2 NaCl + H2SO4 = Na2SO4 + 2 HCl
Ln + Cl2 = LnCl2 =>
Ln + Cl2 = LnCl2
Na2SO4 + Ag = Na2SO4Ag =>
Na2SO4 + Ag = Na2SO4Ag
NO + H2O2 = NO2 + H2O =>
NO + H2O2 = NO2 + H2O
HBrO + Ca(OH)2 = Ca(BrO)2 + H2O =>
2 HBrO + Ca(OH)2 = Ca(BrO)2 + 2 H2O
Ba(NO2)2 + Al2S3 = BaS3 + Al2(NO2)2 =>
Ba(NO2)2 + Al2S3 = BaS3 + Al2(NO2)2
Sn(OH)3{-} + Bi(OH)3 + OH{-} = Sn(OH)6{-2} + Bi =>
3 Sn(OH)3{-} + 2 Bi(OH)3 + 3 OH{-} = 3 Sn(OH)6{-2} + 2 Bi
NH3 + PBO = PB + H2O + N2 =>
2 NH3 + 3 PBO = 3 PB + 3 H2O + N2
CaMg(CO3)2 + HCl = CaCl2 + MgCl2 + H2O + CO2 =>
CaMg(CO3)2 + 4 HCl = CaCl2 + MgCl2 + 2 H2O + 2 CO2
Cl + NH4OH = NH4Cl + OH =>
Cl + NH4OH = NH4Cl + OH
C4H9OH + CH2O2 = C5H10O2 + H2O =>
C4H9OH + CH2O2 = C5H10O2 + H2O
SCN + BrO3 = CN + Br + SO4 =>
3 SCN + 4 BrO3 = 3 CN + 4 Br + 3 SO4
Au2Cl6 + O2 = Au(ClO3)3 =>
Au2Cl6 + 9 O2 = 2 Au(ClO3)3
C12H22O11 + H2O = CO2C2H5OH =>
C12H22O11 + H2O = 4 CO2C2H5OH
H{+} + Au + Cl{-} + NO3{-} = AuCl4{-} + NO + H2O =>
4 H{+} + Au + 4 Cl{-} + NO3{-} = AuCl4{-} + NO + 2 H2O
C6H12O6 + H2 = C6H12 + H2O =>
C6H12O6 + 6 H2 = C6H12 + 6 H2O
H2CCH2 + H2SO4 = H2CCH3 + HSO4 =>
H2CCH2 + H2SO4 = H2CCH3 + HSO4
CuSO4*5H2O + K2C2O4 = K2[Cu(C2O4)2]*2H2O + H2O + K + SO4 =>
CuSO4*5H2O + 2 K2C2O4 = K2[Cu(C2O4)2]*2H2O + 3 H2O + 2 K + SO4
H(C2H3O2) + Ca(OH)2 = H2O + Ca(C2H3O2)2 =>
2 H(C2H3O2) + Ca(OH)2 = 2 H2O + Ca(C2H3O2)2
Fe + FeSO4 = Fe2SO4 =>
Fe + FeSO4 = Fe2SO4
Ba(OH)2 + H(C2H3O2) = Ba(C2H3O2)2 + H2O =>
Ba(OH)2 + 2 H(C2H3O2) = Ba(C2H3O2)2 + 2 H2O
Al(OH)3 + H(C2H3O2) = Al(C2H3O2)3 + H2O =>
Al(OH)3 + 3 H(C2H3O2) = Al(C2H3O2)3 + 3 H2O
| 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 |
| Am Vortag ausgeglichene Gleichungen | Am nächsten Tag ausgeglichene Gleichungen |
Gleichungen ausgeglichen auf12/12/24
Gleichungen ausgeglichen auf01/11/24
Geben Sie uns Rückmeldungen zu Ihren Erfahrungen mit dem Programm zum Berechnen chemischer Reaktionsgleichungen.
