Am Vortag ausgeglichene Gleichungen |
2 Sr(OH)2 + 2 CuSO4 = 2 Sr(SO4) + 2 H2O + O2 + 2 Cu
Al + Hg(CH3COO)3 = Al(CH3COO)3 + Hg =>
Al + Hg(CH3COO)3 = Al(CH3COO)3 + Hg
CH3COCH3 + H2 = CH3CHOHCH3 =>
CH3COCH3 + H2 = CH3CHOHCH3
N2H4*H2SO4 + NaNO2 + NaHCO3 = NaN3 + Na2SO4 + H2O + CO2 =>
N2H4*H2SO4 + NaNO2 + 2 NaHCO3 = NaN3 + Na2SO4 + 4 H2O + 2 CO2
AgNO3 + C2H5NS = NSNO3 + AgC2H5 =>
AgNO3 + C2H5NS = NSNO3 + AgC2H5
Fe(ii)N(aq) + Cu(i)S(aq) = Fe(ii)S(s) + Cu(i)N(aq) =>
Fe(ii)N(aq) + Cu(i)S(aq) = Fe(ii)S(s) + Cu(i)N(aq)
MgCl2(aq) + NaOh(aq) = MgOh(aq) + NaCl2(s) =>
MgCl2(aq) + NaOh(aq) = MgOh(aq) + NaCl2(s)
I{-} + O2 + H2O = I2 + OH{-} =>
4 I{-} + O2 + 2 H2O = 2 I2 + 4 OH{-}
(NH4)2SO4 + H2S + CrOH3 = (NH4)2S + Cr2(SO4)3 + H2O =>
4(NH4)2SO4 + 3 H2S + 2 CrOH3 = 4(NH4)2S + Cr2(SO4)3 + 6 H2O
HNO3 + MgO*5H2O = Mg(NO3)2*6H2O =>
2 HNO3 + MgO*5H2O = Mg(NO3)2*6H2O
FeSO4 + PtCl4 = FeCl + Pt + SO4 =>
4 FeSO4 + PtCl4 = 4 FeCl + Pt + 4 SO4
K3[IrCl6] + H2O = KOH + H + IrCl6 =>
K3[IrCl6] + 3 H2O = 3 KOH + 3 H + IrCl6
Al + H2SO4 + O2 = Al2(SO4)3 + H2O =>
4 Al + 6 H2SO4 + 3 O2 = 2 Al2(SO4)3 + 6 H2O
Cu2(aq) + OH(aq) = Cu(OH)2(s) =>
Cu2(aq) + 4 OH(aq) = 2 Cu(OH)2(s)
C5H10O2(i) + O2 = CO2(g) + H2O(g) =>
2 C5H10O2(i) + 13 O2 = 10 CO2(g) + 10 H2O(g)
NH3(aq) + CoSO4(aq) + H2SO4(aq) + H2O2(aq) = [(NH3)5Co*(O2)*Co(NH3)5]2(SO4)5 + H2O =>
20 NH3(aq) + 4 CoSO4(aq) + H2SO4(aq) + 5 H2O2(aq) = [(NH3)5Co*(O2)*Co(NH3)5]2(SO4)5 + 6 H2O
AgNO3 + NH3 = AgNO3NH3 =>
AgNO3 + NH3 = AgNO3NH3
C4H10 + O2 = CO2 + OH =>
C4H10 + 9 O2 = 4 CO2 + 10 OH
CaO + C = CaC3 + CO2 =>
2 CaO + 7 C = 2 CaC3 + CO2
Mg(OH)2 + NaCl = MgCl + Na(OH)2 =>
Mg(OH)2 + NaCl = MgCl + Na(OH)2
HBr + MgF2 = MgBr2 + HF =>
2 HBr + MgF2 = MgBr2 + 2 HF
(Cr(CO(NH2)2)6)4(Cr(CN)6)3 + KMnO4 + HNO3 = K2Cr2O7 + CO2 + KNO3 + Mn(NO3)2 + H2O =>
10(Cr(CO(NH2)2)6)4(Cr(CN)6)3 + 1176 KMnO4 + 2798 HNO3 = 35 K2Cr2O7 + 420 CO2 + 1106 KNO3 + 1176 Mn(NO3)2 + 1879 H2O
Ca + HOH = Ca(OH)2 + H3 =>
3 Ca + 6 HOH = 3 Ca(OH)2 + 2 H3
C5H8Br4 + Zn = ZnBr2 + C5H8 =>
C5H8Br4 + 2 Zn = 2 ZnBr2 + C5H8
Y + NaOH = YNaOH =>
Y + NaOH = YNaOH
CuS + H2O + O = Cu(OH)2 + SO2 =>
CuS + H2O + 3 O = Cu(OH)2 + SO2
FeSO4 + K2Cr2O7 + H2SO4 = Fe2(SO4)3 + KCr(SO4)3 + H2O =>
2 FeSO4 + K2Cr2O7 + 7 H2SO4 = Fe2(SO4)3 + 2 KCr(SO4)3 + 7 H2O
Na2SO3 + HCl = S(O)2 + NaCl + H2O =>
Na2SO3 + 2 HCl = S(O)2 + 2 NaCl + H2O
Al + HCl = Al3Cl + H2 =>
6 Al + 2 HCl = 2 Al3Cl + H2
FeSO4 + HCl = FeCl3 + SO4 + H2 =>
2 FeSO4 + 6 HCl = 2 FeCl3 + 2 SO4 + 3 H2
PbS(s) = Pb(s) + S(s) =>
PbS(s) = Pb(s) + S(s)
Hg0 + HNO3 = Hg(NO3)2 + NO2 + H2O =>
Hg0 + 4 HNO3 = Hg(NO3)2 + 2 NO2 + 2 H2O
Fe2O3 + Ca(OH)2 + H2O = Ca[Fe(OH)4]2 =>
Fe2O3 + Ca(OH)2 + 3 H2O = Ca[Fe(OH)4]2
Cu2O + K2CrO4 + H2SO4 = CuSO4 + Cr2(SO4)3 + K2SO4 + H2O =>
3 Cu2O + 2 K2CrO4 + 11 H2SO4 = 6 CuSO4 + Cr2(SO4)3 + 2 K2SO4 + 11 H2O
SN + HNO3 = SNO2 + NO2 + H2O =>
SN + 4 HNO3 = SNO2 + 4 NO2 + 2 H2O
Fe + Cl = FeCl3 =>
Fe + 3 Cl = FeCl3
aceticacid + NaOH = H2O + NaC2H3O2 =>
C2H4O2 + NaOH = H2O + NaC2H3O2
NH2(CH2)4CHNH2COONa + HCl = NH2(CH2)4CHNH2COOH + NaCl =>
NH2(CH2)4CHNH2COONa + HCl = NH2(CH2)4CHNH2COOH + NaCl
KNO3 + Cu = KNO2 + CuO =>
KNO3 + Cu = KNO2 + CuO
Sb(OH)3 + H2S = Sb2S3 + H2O =>
2 Sb(OH)3 + 3 H2S = Sb2S3 + 6 H2O
Fe2(SO4)3(aq) + Sr(NO3)2(aq) = Fe(NO3)3(aq) + SrSO4(s) =>
Fe2(SO4)3(aq) + 3 Sr(NO3)2(aq) = 2 Fe(NO3)3(aq) + 3 SrSO4(s)
Fe + H2SO4 = FeSO4 + S2 + H2O =>
6 Fe + 8 H2SO4 = 6 FeSO4 + S2 + 8 H2O
AlN + NH4OH = Al(OH)3 + NH3 =>
AlN + 3 NH4OH = Al(OH)3 + 4 NH3
H2O + PB(NO2)2 = PBO + HNO2 =>
H2O + PB(NO2)2 = PBO + 2 HNO2
C10H15N + HCl = C10H15N*HCl =>
C10H15N + HCl = C10H15N*HCl
Pb + F2 = PbF4 =>
Pb + 2 F2 = PbF4
Mg + H2SO4 = MgSO4 + H2 =>
Mg + H2SO4 = MgSO4 + H2
SbCI5 + KI = KCI + SbI5 =>
SbCI5 + KI = KCI + SbI5
H2(SO4) + Na2CO3 = CO2 + H2O + Na2SO4 =>
H2(SO4) + Na2CO3 = CO2 + H2O + Na2SO4
CH202 + O2 = CO2 + H2O =>
2 CH202 + 103 O2 = 2 CO2 + 202 H2O
Gleichen Sie die Gleichung jeder chemischen Reaktion aus
Am Vortag ausgeglichene Gleichungen |
Gleichungen ausgeglichen auf11/23/24
Gleichungen ausgeglichen auf12/23/23
Geben Sie uns Rückmeldungen zu Ihren Erfahrungen mit dem Programm zum Berechnen chemischer Reaktionsgleichungen.