Equations balanced on the previous day | Equations balanced on the next day |
2 RSi(OCH3)3 + 7 C2H5OH + H2O = 2 RSiOH + 4 C2H6(OCH3)3
AuCl3 + NaOH = Au(OH)3 + NaCl =>
AuCl3 + 3 NaOH = Au(OH)3 + 3 NaCl
C3H8O + K2CrO4 + H2SO4 = C3H6O + K2SO4 + Cr2(SO4)3 + H2O =>
3 C3H8O + 2 K2CrO4 + 5 H2SO4 = 3 C3H6O + 2 K2SO4 + Cr2(SO4)3 + 8 H2O
Na3PO4 + Fe2O3 = Na2O + FePO4 =>
2 Na3PO4 + Fe2O3 = 3 Na2O + 2 FePO4
MnO4{-} + NO2{-} + H{+} = Mn{+} + NO3{-} + H2O =>
MnO4{-} + 3 NO2{-} + 2 H{+} = Mn{+} + 3 NO3{-} + H2O
KOH(aq) + Na2CO3 = K2CO3 + Na2(OH)2 =>
2 KOH(aq) + Na2CO3 = K2CO3 + Na2(OH)2
ZnO + HNO3 = HO + ZnNO3 =>
ZnO + HNO3 = HO + ZnNO3
Na2CO3 + CaCl2 = NaCl + Ca(CO3) =>
Na2CO3 + CaCl2 = 2 NaCl + Ca(CO3)
H2SO4 + Na2CO3 = CO2 + H2O + Na2SO4 =>
H2SO4 + Na2CO3 = CO2 + H2O + Na2SO4
Na3PO4 + Fe2O3 = Na2O + FePO4 =>
2 Na3PO4 + Fe2O3 = 3 Na2O + 2 FePO4
CH3CH2CH2OH + K2Cr2O7 + H2SO4 = Cr2(SO4)3 + K2SO4 + CO2 + H2O =>
CH3CH2CH2OH + 3 K2Cr2O7 + 12 H2SO4 = 3 Cr2(SO4)3 + 3 K2SO4 + 3 CO2 + 16 H2O
KHSO3 + HCl = KCl + SO2 + H2O =>
KHSO3 + HCl = KCl + SO2 + H2O
PBr3(l) + H2O(l) = H3PO3(aq) + HBr(g) =>
PBr3(l) + 3 H2O(l) = H3PO3(aq) + 3 HBr(g)
Cu(NO3)2 + Ca = Cu + Ca(NO3)2 =>
Cu(NO3)2 + Ca = Cu + Ca(NO3)2
Ag + H2SO4 = Ag2SO4 + H2 =>
2 Ag + H2SO4 = Ag2SO4 + H2
Mg + O2 = MgO =>
2 Mg + O2 = 2 MgO
(NH4)3PO4 + CaCl2 = Ca3(PO4)2 + Cl(NH4) =>
2(NH4)3PO4 + 3 CaCl2 = Ca3(PO4)2 + 6 Cl(NH4)
BaCl2 + CuSO4 = CuCl2 + Ba(SO4) =>
BaCl2 + CuSO4 = CuCl2 + Ba(SO4)
N2 + O2 = N2O4 =>
N2 + 2 O2 = N2O4
CH3CH2CH2CH2CH2CH2CH2CH2OH + CH3COOH = CH3COOCH2CH2CH2CH2CH2CH2CH2CH3 + H2O =>
CH3CH2CH2CH2CH2CH2CH2CH2OH + CH3COOH = CH3COOCH2CH2CH2CH2CH2CH2CH2CH3 + H2O
Au + KCN + O2 + H2O = KAuC2N2 + KOH =>
4 Au + 8 KCN + O2 + 2 H2O = 4 KAuC2N2 + 4 KOH
ClI + Cl2 + H2O = HIO3 + HCl =>
ClI + 2 Cl2 + 3 H2O = HIO3 + 5 HCl
CoS + NaOH = Na2S + Co(OH)2 =>
CoS + 2 NaOH = Na2S + Co(OH)2
HCl(aq) + Na2SO3 = H2SO3 + NaCl =>
2 HCl(aq) + Na2SO3 = H2SO3 + 2 NaCl
Cu2S(s) = Cu(s) + S(g) =>
Cu2S(s) = 2 Cu(s) + S(g)
F + Ga = GaF3 =>
3 F + Ga = GaF3
MnCl2 + O2 + KOH + H2O = Mn(OH)3 + KCl =>
4 MnCl2 + O2 + 8 KOH + 2 H2O = 4 Mn(OH)3 + 8 KCl
Bi + Te + Cu = Bi200Cu15Te285 =>
200 Bi + 285 Te + 15 Cu = Bi200Cu15Te285
SiO2 + HCl = H2[SiCl6] + H2O =>
SiO2 + 6 HCl = H2[SiCl6] + 2 H2O
C4H6O6 + NaOH = Na2C4H4O6 + H2O =>
C4H6O6 + 2 NaOH = Na2C4H4O6 + 2 H2O
C4 + F1 = CF4 =>
C4 + 16 F1 = 4 CF4
FeO + KMnO4 = Fe2O3 + MnO2 + K2O =>
6 FeO + 2 KMnO4 = 3 Fe2O3 + 2 MnO2 + K2O
Cu + H2SO4(st) = CuSO4 + SO2 + H2O =>
Cu + 2 H2SO4(st) = CuSO4 + SO2 + 2 H2O
Sb2S3 + HNO3 = Sb2O5 + H2SO4 + NO + H2O =>
3 Sb2S3 + 28 HNO3 = 3 Sb2O5 + 9 H2SO4 + 28 NO + 5 H2O
HNO3 + Ca3(PO4)2 = H3PO4 + Ca(NO3)2 =>
6 HNO3 + Ca3(PO4)2 = 2 H3PO4 + 3 Ca(NO3)2
MgCl2 + Fe2(SO4)3 = MgSO4 + FeCl3 =>
3 MgCl2 + Fe2(SO4)3 = 3 MgSO4 + 2 FeCl3
C6H10O + O2 = C4H6O4 + H{+} + e =>
2 C6H10O + 5 O2 = 3 C4H6O4 + 2 H{+} + 2e
SO4 + H + BaCl2 = BaSO4 + HCl =>
SO4 + 2 H + BaCl2 = BaSO4 + 2 HCl
HCO2Na + H2SO4 = HCO2H + Na2SO4 =>
2 HCO2Na + H2SO4 = 2 HCO2H + Na2SO4
CaCl + Na2CO3 = Na2Cl + CaCO3 =>
CaCl + Na2CO3 = Na2Cl + CaCO3
Ba + HCl = BaCl + H =>
Ba + HCl = BaCl + H
CaO(s) + SiO2(l) = CaSiO3(s) =>
CaO(s) + SiO2(l) = CaSiO3(s)
BaS + (NH4)2CO3 = BaCO3 + (NH4)2S =>
BaS + (NH4)2CO3 = BaCO3 + (NH4)2S
C2(s) + H2(g) + O2(g) = C2H5OH(l) =>
2 C2(s) + 6 H2(g) + O2(g) = 2 C2H5OH(l)
CU + HSO4 = CUSO4 + H2O + SO3 =>
CU + 2 HSO4 = CUSO4 + H2O + SO3
NaNO3 + FeSO4 + H2SO4 = NaSO4 + Fe2(SO4)3 + H2O + NO =>
NaNO3 + 2 FeSO4 + 2 H2SO4 = NaSO4 + Fe2(SO4)3 + 2 H2O + NO
C5H8O2 = C + H + O =>
C5H8O2 = 5 C + 8 H + 2 O
K2Cr2O7(s) = K2CrO4(s) + Cr2O4(s) + O2(g) =>
2 K2Cr2O7(s) = 2 K2CrO4(s) + Cr2O4(s) + O2(g)
Na2S(aq) + Cu(NO3)2(aq) = NaNO3(aw) + CuS(s) =>
Na2S(aq) + Cu(NO3)2(aq) = 2 NaNO3(aw) + CuS(s)
HBr(aq) + NaHCO3(aq) = CO2(aq) + H2O(aq) + NaBr(aq) =>
HBr(aq) + NaHCO3(aq) = CO2(aq) + H2O(aq) + NaBr(aq)
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 05/23/24
Equations balanced on 06/22/23
Geben Sie uns Rückmeldungen zu Ihren Erfahrungen mit dem Programm zum Berechnen chemischer Reaktionsgleichungen.