| Am Vortag ausgeglichene Gleichungen | Am nächsten Tag ausgeglichene Gleichungen |
C6H5NH3CNO + H2O = HC6H5NH3CNO + OH
BaSO3 + H2O = BaO + H2SO3 =>
BaSO3 + H2O = BaO + H2SO3
NaHCO3 + C6H8O7 = H2O + CO2 + NaCHO =>
9 NaHCO3 + 2 C6H8O7 = 8 H2O + 12 CO2 + 9 NaCHO
KCl(aq) + Br(l) = Cl(g) + KBr(aq) =>
KCl(aq) + Br(l) = Cl(g) + KBr(aq)
BaSO3 + H2O = BaO + H2SO3 =>
BaSO3 + H2O = BaO + H2SO3
C7H16 + O2 = CO2 + H2O2 =>
C7H16 + 15 O2 = 7 CO2 + 8 H2O2
K2C2O4 + H2O = K + H2C204 + OH =>
102 K2C2O4 + 410 H2O = 204 K + H2C204 + 818 OH
HCH3CO2 = H2 + CH3 + CO2 =>
2 HCH3CO2 = H2 + 2 CH3 + 2 CO2
K2C2O4 + H2O = K + H2C204 + OH =>
102 K2C2O4 + 410 H2O = 204 K + H2C204 + 818 OH
KMnO4 + HBr = Br2 + MnO2 + KBr + H2O =>
2 KMnO4 + 8 HBr = 3 Br2 + 2 MnO2 + 2 KBr + 4 H2O
K2Co3 + HCl = K2Co3HCl =>
K2Co3 + HCl = K2Co3HCl
CsIO3 = CsI + O2 =>
2 CsIO3 = 2 CsI + 3 O2
CH3CHCH2 + KMnO4 + H2O = MnO2 + CH3CHCOOH + KOH =>
3 CH3CHCH2 + 5 KMnO4 + H2O = 5 MnO2 + 3 CH3CHCOOH + 5 KOH
Fe2O2 + HCl = FeCl2 + H2O =>
Fe2O2 + 4 HCl = 2 FeCl2 + 2 H2O
NO2(g) + H2O(l) = HNO3(l) + NO(g) =>
3 NO2(g) + H2O(l) = 2 HNO3(l) + NO(g)
Ta + HF + HNO3 = H2TaF7 + NO + H2O =>
3 Ta + 21 HF + 5 HNO3 = 3 H2TaF7 + 5 NO + 10 H2O
NO2(g) + H2O(l) = HNO3(l) + NO(g) =>
3 NO2(g) + H2O(l) = 2 HNO3(l) + NO(g)
NaI(aq)Hg2(C4H6O4)(aq) = Hg2I(s)Na(C4H6O4)(aq) =>
NaI(aq)Hg2(C4H6O4)(aq) = Hg2I(s)Na(C4H6O4)(aq)
Ba(OH)2(aq) + HCl(aq) = Ba + Cl + H2O =>
Ba(OH)2(aq) + 2 HCl(aq) = Ba + 2 Cl + 2 H2O
Ag2SO4 + LiBr = Li2SO4 + AgBr =>
Ag2SO4 + 2 LiBr = Li2SO4 + 2 AgBr
Ag(NO3)(aq) + NaCl(aq) = AgCl(s) + NaNO3(aq) =>
Ag(NO3)(aq) + NaCl(aq) = AgCl(s) + NaNO3(aq)
NaHCO3 + CH3(CH2)6COOH = CH3(CH2)16COONa + H2O + CO2 =>
11 NaHCO3 + 26 CH3(CH2)6COOH = 11 CH3(CH2)16COONa + 21 H2O + 21 CO2
NO2(g) + H2O(l) = HNO3(aq) + NO(g) =>
3 NO2(g) + H2O(l) = 2 HNO3(aq) + NO(g)
Cu(OH)2 + KI = KOH + CuI2 =>
Cu(OH)2 + 2 KI = 2 KOH + CuI2
Ta + HF + HNO3 = H2TaF7 + NO + H2O =>
3 Ta + 21 HF + 5 HNO3 = 3 H2TaF7 + 5 NO + 10 H2O
NO2(g) + H2O(l) = HNO3(l) + NO(g) =>
3 NO2(g) + H2O(l) = 2 HNO3(l) + NO(g)
KOH + NiBr2 = Ni(OH)2 + KBr =>
2 KOH + NiBr2 = Ni(OH)2 + 2 KBr
(CH3COO)2Ca + (NH4)2C2O4 = CaC2O4 + CH3COONH4 =>
(CH3COO)2Ca + (NH4)2C2O4 = CaC2O4 + 2 CH3COONH4
Al2(S04)3 + Ba(NO3)2 = Al(NO3)3 + BaS04 =>
Al2(S04)3 + 3 Ba(NO3)2 = 2 Al(NO3)3 + 3 BaS04
SO2 + H2CrO4 = Cr2(SO4)3 + H2O =>
3 SO2 + 2 H2CrO4 = Cr2(SO4)3 + 2 H2O
Ta + HF + HNO3 = H2TaF7 + NO + H2O =>
3 Ta + 21 HF + 5 HNO3 = 3 H2TaF7 + 5 NO + 10 H2O
NO2(g) + H2O(l) = HNO3(aq) + NO(g) =>
3 NO2(g) + H2O(l) = 2 HNO3(aq) + NO(g)
NO2(g) + H2O(l) = HNO3(l) + NO(g) =>
3 NO2(g) + H2O(l) = 2 HNO3(l) + NO(g)
N2 + H2 = NH3 =>
N2 + 3 H2 = 2 NH3
NO2(g) + H2O(l) = HNO3(l) + NO(g) =>
3 NO2(g) + H2O(l) = 2 HNO3(l) + NO(g)
Ta + HF + HNO3 = H2TaF7 + NO + H2O =>
3 Ta + 21 HF + 5 HNO3 = 3 H2TaF7 + 5 NO + 10 H2O
CO + CuCl + H2O = COCuClH2O =>
CO + CuCl + H2O = COCuClH2O
NO2(g) + H2O(l) = HNO3(l) + NO(g) =>
3 NO2(g) + H2O(l) = 2 HNO3(l) + NO(g)
Ta + HF + HNO3 = H2TaF7 + NO + H2O =>
3 Ta + 21 HF + 5 HNO3 = 3 H2TaF7 + 5 NO + 10 H2O
NO2(g) + H2O(l) = HNO3(aq) + NO(g) =>
3 NO2(g) + H2O(l) = 2 HNO3(aq) + NO(g)
Ta + HF + HNO3 = H2TaF7 + NO + H2O =>
3 Ta + 21 HF + 5 HNO3 = 3 H2TaF7 + 5 NO + 10 H2O
KMnO4 + KOH + C6H12O6 = K2MnO4 + CO2 + H2O =>
24 KMnO4 + 24 KOH + C6H12O6 = 24 K2MnO4 + 6 CO2 + 18 H2O
Ta + HF + HNO3 = H3TaF8 + NO2 + H2O =>
Ta + 8 HF + 5 HNO3 = H3TaF8 + 5 NO2 + 5 H2O
Ta + HF + HNO3 = H2[TaF7] + NO + H2O =>
3 Ta + 21 HF + 5 HNO3 = 3 H2[TaF7] + 5 NO + 10 H2O
Ta + HNO3 + HF = H3[TaF7] + NO + H2O =>
3 Ta + 4 HNO3 + 21 HF = 3 H3[TaF7] + 4 NO + 8 H2O
NO2(g) + H2O(l) = HNO3(aq) + NO(g) =>
3 NO2(g) + H2O(l) = 2 HNO3(aq) + NO(g)
Ta + HNO3 + HF = H2(TaF7) + NO + H2O =>
3 Ta + 5 HNO3 + 21 HF = 3 H2(TaF7) + 5 NO + 10 H2O
Ta + HF + HNO3 = H2[TaF7] + NO + H2O =>
3 Ta + 21 HF + 5 HNO3 = 3 H2[TaF7] + 5 NO + 10 H2O
Ta + HF + HNO3 = H3TaF8 + NO2 + H2O =>
Ta + 8 HF + 5 HNO3 = H3TaF8 + 5 NO2 + 5 H2O
Ta + HNO3 + HF = H2(TaF7) + NO + H2O =>
3 Ta + 5 HNO3 + 21 HF = 3 H2(TaF7) + 5 NO + 10 H2O
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| Am Vortag ausgeglichene Gleichungen | Am nächsten Tag ausgeglichene Gleichungen |
Gleichungen ausgeglichen auf04/30/24
Gleichungen ausgeglichen auf05/30/23
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