Equations balanced on the previous day | Equations balanced on the next day |
2 CuSO4 + Fe2 = 2 FeSO4 + Cu2
FeC2O4*2H20 + O2 = CO2 + FeO(OH) + H2O =>
4 FeC2O4*2H20 + 43 O2 = 8 CO2 + 4 FeO(OH) + 78 H2O
I3Cl + NH4OH = I3OH + NH4Cl =>
I3Cl + NH4OH = I3OH + NH4Cl
Mn(NO3)2 + NaBiO3 = MnO3 + NaBi(NO3)2 =>
Mn(NO3)2 + NaBiO3 = MnO3 + NaBi(NO3)2
OHCl + HNO3 = NO3Cl + H2O =>
OHCl + HNO3 = NO3Cl + H2O
CH3NH2 + CH3COOH = CH3COONHCH3 + CH3OH =>
2 CH3NH2 + 3 CH3COOH = 2 CH3COONHCH3 + 2 CH3OH
CH2H5OH + O2 = H2O + CO2 =>
2 CH2H5OH + 5 O2 = 8 H2O + 2 CO2
KBrO3 + H3PO4 + KI = K3PO4 + Br2 + I2 + H2O =>
2 KBrO3 + 4 H3PO4 + 10 KI = 4 K3PO4 + Br2 + 5 I2 + 6 H2O
HNO3 + HCl = H(Cl4) + NO2 + H2O =>
3 HNO3 + 4 HCl = H(Cl4) + 3 NO2 + 3 H2O
BaSO4 + NaCl = BaS + NaClO =>
BaSO4 + 4 NaCl = BaS + 4 NaClO
K2Cr2O7 + C2H5OH + H2SO4 = CH3CHO + Cr2(SO4)3 + K2SO4 + H2O =>
K2Cr2O7 + 3 C2H5OH + 4 H2SO4 = 3 CH3CHO + Cr2(SO4)3 + K2SO4 + 7 H2O
H2O + CHCOONa = CHCOOH + NaOH =>
H2O + CHCOONa = CHCOOH + NaOH
Cl + NaOH = ClNa + NaClO + H2O =>
2 Cl + 2 NaOH = ClNa + NaClO + H2O
MnO4{3-} + e + H2O = MnO2 + OH{-} =>
MnO4{3-} + e + 2 H2O = MnO2 + 4 OH{-}
Li{2+}Na{+} + Ca{3+}Li{+}H{4+} = Li{5+}H{3+} + Ca{+}Na{2+} =>
2 Li{2+}Na{+} + 3 Ca{3+}Li{+}H{4+} = 2 Li{5+}H{3+} + 3 Ca{+}Na{2+}
Al(s) + Fe2O3(aq) = Al2O3 + Fe =>
2 Al(s) + Fe2O3(aq) = Al2O3 + 2 Fe
C5H12 + O2 = CO2 + H2O =>
C5H12 + 8 O2 = 5 CO2 + 6 H2O
LiBr2 + AgNO3 = AgBr2 + LiNO3 =>
LiBr2 + AgNO3 = AgBr2 + LiNO3
Cr(HCO3)3 = Cr2(CO3)3 + H2O + CO2 =>
2 Cr(HCO3)3 = Cr2(CO3)3 + 3 H2O + 3 CO2
Ca(OH)2 + H3PO4(aq) = Ca3(PO4)2 + H2O =>
3 Ca(OH)2 + 2 H3PO4(aq) = Ca3(PO4)2 + 6 H2O
ArOH = Ar2O + H2O =>
2 ArOH = Ar2O + H2O
Zn(OH)2 + FeS = ZnS + Fe(OH)2 =>
Zn(OH)2 + FeS = ZnS + Fe(OH)2
Cu(HCO3)2 + H2SO4 = CuSO4 + CO3 + H =>
Cu(HCO3)2 + H2SO4 = CuSO4 + 2 CO3 + 4 H
ZnSO4 + KBr = K2SO4 + ZnBr2 =>
ZnSO4 + 2 KBr = K2SO4 + ZnBr2
Ba3(PO4)2 + Li2SO4 = BaSO4 + Li3PO4 =>
Ba3(PO4)2 + 3 Li2SO4 = 3 BaSO4 + 2 Li3PO4
ZnO + C2 = Zn + CO =>
2 ZnO + C2 = 2 Zn + 2 CO
Ca(CO3)2 + MgSO4 = CaSO4 + Mg(CO3)2 =>
Ca(CO3)2 + MgSO4 = CaSO4 + Mg(CO3)2
Ba(OH)2 + Fe(NO3)3 = Fe(OH)3 + Ba(NO3)2 =>
3 Ba(OH)2 + 2 Fe(NO3)3 = 2 Fe(OH)3 + 3 Ba(NO3)2
NaVO3 + Zn + HCl = NaOH + VCl4 + ZnCl2 + H2O =>
2 NaVO3 + Zn + 10 HCl = 2 NaOH + 2 VCl4 + ZnCl2 + 4 H2O
MgNO2 + H2O = MgO + NH3 + O2 =>
4 MgNO2 + 6 H2O = 4 MgO + 4 NH3 + 5 O2
NH4NO3 + Na2SO4 = (NH4)2SO4 + NaNO3 =>
2 NH4NO3 + Na2SO4 = (NH4)2SO4 + 2 NaNO3
HBr(aq) + NiS(s) = H2S + NiBr2 =>
2 HBr(aq) + NiS(s) = H2S + NiBr2
Na + FeSO3 = Fe2 + Na2SO3 =>
4 Na + 2 FeSO3 = Fe2 + 2 Na2SO3
Na2CO3 + Ca(OH)2 = NaOH + CCaO3 =>
Na2CO3 + Ca(OH)2 = 2 NaOH + CCaO3
Al + HCl = AlCl3 + H2 =>
2 Al + 6 HCl = 2 AlCl3 + 3 H2
SnCl4 + (NH4)2SO3 = NH4Cl + Sn2(SO3)4 =>
2 SnCl4 + 4(NH4)2SO3 = 8 NH4Cl + Sn2(SO3)4
KMnO4 + H2C2O4 + H2SO4 = K2SO4 + MnSO4 + H2O + CO2 =>
2 KMnO4 + 5 H2C2O4 + 3 H2SO4 = K2SO4 + 2 MnSO4 + 8 H2O + 10 CO2
SrCl2 + NaNO3 = Sr(NO3)2 + NaCl =>
SrCl2 + 2 NaNO3 = Sr(NO3)2 + 2 NaCl
C6H + O2 = CO2 + H =>
C6H + 6 O2 = 6 CO2 + H
NaH2 + NaNO3 = NaN3 + NaOH + NH3 =>
24 NaH2 + 11 NaNO3 = 2 NaN3 + 33 NaOH + 5 NH3
C2H5N + O2 = CO + H2O + NO =>
4 C2H5N + 11 O2 = 8 CO + 10 H2O + 4 NO
C6H5NO2 + H2O = H3O{+} + C6H4NO2{-} =>
C6H5NO2 + H2O = H3O{+} + C6H4NO2{-}
Fe(NO3)4 + K2Cr2O7 = Fe(Cr2O7)2 + KNO3 =>
Fe(NO3)4 + 2 K2Cr2O7 = Fe(Cr2O7)2 + 4 KNO3
CoCl2*6H2O + NH2CH2CH2NH2*2HCl + NaOH + H2O2 = [Co(NH2CH2CH2NH2)3]Cl3*4H2O + NaCl + H2O =>
2 CoCl2*6H2O + 6 NH2CH2CH2NH2*2HCl + 10 NaOH + H2O2 = 2[Co(NH2CH2CH2NH2)3]Cl3*4H2O + 10 NaCl + 16 H2O
KNO3 + C7H6O = N2 + CO2 + H2O + K2CO3 =>
32 KNO3 + 5 C7H6O = 16 N2 + 19 CO2 + 15 H2O + 16 K2CO3
H3PO4 + (NH4)2MoO4 + HNO3 = (NH)4PO4Mo12O3 + NH4NO3 + H2O =>
8 H3PO4 + 96(NH4)2MoO4 + 50 HNO3 = 8(NH)4PO4Mo12O3 + 105 NH4NO3 + 195 H2O
NH4ClO4 + C = N2 + H2O + CO + Cl2 =>
2 NH4ClO4 + 4 C = N2 + 4 H2O + 4 CO + Cl2
NH3 = H2 + N2 =>
2 NH3 = 3 H2 + N2
A + B + C = ABC =>
A + B + C = ABC
Na(l) + KCl(l) = K(g) + NaCl(l) =>
Na(l) + KCl(l) = K(g) + NaCl(l)
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 01/19/24
Equations balanced on 02/18/23
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