Equations balanced on the previous day | Equations balanced on the next day |
3 Al(OH)3 + 9 H2SO4 = Al3 + 9 H2O + 9 HSO4
Mg3(PO4)2 + Cu(OH)2 = Cu3(PO4)2 + Mg(OH)2 =>
Mg3(PO4)2 + 3 Cu(OH)2 = Cu3(PO4)2 + 3 Mg(OH)2
Pt[NH3]4Cl2 + Ag2[HPO4] = Pt[NH3]4HPO4 + AgCl =>
Pt[NH3]4Cl2 + Ag2[HPO4] = Pt[NH3]4HPO4 + 2 AgCl
BF = B + F =>
BF = B + F
CaI + Na2CO3 = CaCO3 + Na2I =>
CaI + Na2CO3 = CaCO3 + Na2I
CuF2 + O2 = CuO2 + F2 =>
CuF2 + O2 = CuO2 + F2
CuSO4*H2O = CuSO4H2O =>
CuSO4*H2O = CuSO4H2O
CH3(CH2)6CH3 + O2 = CO2 + H2O =>
2 CH3(CH2)6CH3 + 25 O2 = 16 CO2 + 18 H2O
O2(g) + H2O(I) = H2O2(I) =>
O2(g) + 2 H2O(I) = 2 H2O2(I)
KCl + Na(NO3)2 = NaCl2 + KNO3 =>
2 KCl + Na(NO3)2 = NaCl2 + 2 KNO3
Pt[NH3]4Cl2 + Ag2[HPO4] = Pt[NH3]4HPO4 + AgCl =>
Pt[NH3]4Cl2 + Ag2[HPO4] = Pt[NH3]4HPO4 + 2 AgCl
NH4Cl + AgF = AgCl + NH4F =>
NH4Cl + AgF = AgCl + NH4F
NaHCO3 + Ca(ClO4)2 = NaClO4 + Ca(HCO3)2 =>
2 NaHCO3 + Ca(ClO4)2 = 2 NaClO4 + Ca(HCO3)2
Fe2 + (SO4)3 + K(OH) = Fe(OH)3 + K2(SO4) =>
Fe2 + (SO4)3 + 6 K(OH) = 2 Fe(OH)3 + 3 K2(SO4)
C5H90 + O2 = CO2 + H2O =>
2 C5H90 + 55 O2 = 10 CO2 + 90 H2O
Na2SO4(s) + C(s) = Na2S(s) + CO2(g) =>
Na2SO4(s) + 2 C(s) = Na2S(s) + 2 CO2(g)
C7H8O2 + O2 = CO2 + H2O =>
C7H8O2 + 8 O2 = 7 CO2 + 4 H2O
CuOH + HC2H3O2 = CuC2H3O2 + H2O =>
CuOH + HC2H3O2 = CuC2H3O2 + H2O
C8H18 + O2 = CO2 + H2O =>
2 C8H18 + 25 O2 = 16 CO2 + 18 H2O
N2H4 + OH = N + H2O =>
N2H4 + 4 OH = 2 N + 4 H2O
CH4 + O2 = CO2 + H2O =>
CH4 + 2 O2 = CO2 + 2 H2O
C7H6O2S + O2 = CO2 + H2O + S03 =>
6 C7H6O2S + 45 O2 = 42 CO2 + 18 H2O + 2 S03
CaMg(CO3)2 + SiO2 + H2O + FeO = Ca2Mg5Si8O22(OH)2 + Ca2Fe5Si8O22(OH)2CaCO3 + CO2 =>
5 CaMg(CO3)2 + 16 SiO2 + 2 H2O + 5 FeO = Ca2Mg5Si8O22(OH)2 + Ca2Fe5Si8O22(OH)2CaCO3 + 9 CO2
C3H4O + H2O = C29H59O + CO2 =>
173 C3H4O + 67 H2O = 14 C29H59O + 113 CO2
C8H9NO2 + KMnO4 + H2SO4 = MnSO4 + H2O + K2SO4 + C7H5NO4 + CO2 =>
5 C8H9NO2 + 12 KMnO4 + 18 H2SO4 = 12 MnSO4 + 28 H2O + 6 K2SO4 + 5 C7H5NO4 + 5 CO2
CH3COOH + Al = AlCH3COO + H2 =>
2 CH3COOH + 2 Al = 2 AlCH3COO + H2
HBrO3 + Mn2(CrO4)7 + Mn2(CO2)7 + Sc(BrO3)3 = Sc2(CO3)3 + H2O + Cr(BrO3)3 + Mn(BrO3)7 =>
70 HBrO3 + 2 Mn2(CrO4)7 + 3 Mn2(CO2)7 + 14 Sc(BrO3)3 = 7 Sc2(CO3)3 + 35 H2O + 14 Cr(BrO3)3 + 10 Mn(BrO3)7
Sb + Cl{2} = SbCl{2} =>
Sb + Cl{2} = SbCl{2}
NaNO3(s) = NaNO2(s) + O2(q) =>
2 NaNO3(s) = 2 NaNO2(s) + O2(q)
Sr + HCl = H2 + SrCl2 =>
Sr + 2 HCl = H2 + SrCl2
NO2 + H2O = HNO3 + NO =>
3 NO2 + H2O = 2 HNO3 + NO
Fe2(SO4)3 + KOH = K2SO4 + Fe(OH)3 =>
Fe2(SO4)3 + 6 KOH = 3 K2SO4 + 2 Fe(OH)3
HNO3 + Ni(OH)3 = Ni(NO3)3 + H2O =>
3 HNO3 + Ni(OH)3 = Ni(NO3)3 + 3 H2O
NO3{-} + H2S8H{+} = NO + S + H2O + H{+} =>
2 NO3{-} + 3 H2S8H{+} = 2 NO + 24 S + 4 H2O + H{+}
KClO4 + KI + HCl = KCl + I2 + H2O =>
KClO4 + 8 KI + 8 HCl = 9 KCl + 4 I2 + 4 H2O
CH3(CH2)5CH3 + O2 = CO2 + H2O =>
CH3(CH2)5CH3 + 11 O2 = 7 CO2 + 8 H2O
MgSO4 + Na2CO3 + H2O = Mg(OH)2 + Na2SO4 + CO2 =>
MgSO4 + Na2CO3 + H2O = Mg(OH)2 + Na2SO4 + CO2
CO(NH2)2 + H2C2O4 = CN + H2 + O2 =>
2 CO(NH2)2 + H2C2O4 = 4 CN + 5 H2 + 3 O2
FeCr2O7 + K2CO3 + O2 = Fe2O3 + K2CrO4 + CO2 =>
4 FeCr2O7 + 8 K2CO3 + O2 = 2 Fe2O3 + 8 K2CrO4 + 8 CO2
C2H6 + O2 = CO2 + H2O =>
2 C2H6 + 7 O2 = 4 CO2 + 6 H2O
Na2CO3(aq) + HC2H3O2(aq) = H2CO3 + NaC2H3O2 =>
Na2CO3(aq) + 2 HC2H3O2(aq) = H2CO3 + 2 NaC2H3O2
FeCr2O7 + K2CO3 + O2 = Fe2O3 + K2CrO4 + CO2 =>
4 FeCr2O7 + 8 K2CO3 + O2 = 2 Fe2O3 + 8 K2CrO4 + 8 CO2
MgSO4 + Fe(NO3)3 = Fe(SO4)3 + Mg(NO3) =>
3 MgSO4 + Fe(NO3)3 = Fe(SO4)3 + 3 Mg(NO3)
Pb(OH4) + H3PO4 = Pb3PO4 + HOH4 =>
3 Pb(OH4) + H3PO4 = Pb3PO4 + 3 HOH4
NO3{-} + Zn = NO2{-} + ZnO =>
NO3{-} + Zn = NO2{-} + ZnO
H2CO3 + K2O = H2O + K2CO3 =>
H2CO3 + K2O = H2O + K2CO3
P + O2 = P2O5 =>
4 P + 5 O2 = 2 P2O5
NaBH4 + (HAuCl4*3H2O) = B2H6 + NaCl + H2 + Au + H2O =>
8 NaBH4 + 2(HAuCl4*3H2O) = 4 B2H6 + 8 NaCl + 5 H2 + 2 Au + 6 H2O
NaBH4 + (HAuCl4*3H2O) = B2H6 + NaCl + H2 + Au + H2O =>
8 NaBH4 + 2(HAuCl4*3H2O) = 4 B2H6 + 8 NaCl + 5 H2 + 2 Au + 6 H2O
NaOH + H2SO4 = Na2SO4 + H2O =>
2 NaOH + H2SO4 = Na2SO4 + 2 H2O
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 01/07/24
Equations balanced on 02/06/23
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