Equations balanced on the previous day | Equations balanced on the next day |
2 H9999O9999 + 2 C9999O9999 = 2 C9999O9999H9999 + 9999 O2
Mn3O4 + H2O = Mn{+2} + MnO4{-} + OH{-} =>
5 Mn3O4 + 12 H2O = 13 Mn{+2} + 2 MnO4{-} + 24 OH{-}
C5H10N2O3 + O2 = CO2 + H2O + CH4N2O =>
2 C5H10N2O3 + 9 O2 = 8 CO2 + 6 H2O + 2 CH4N2O
NaOH + H3PO4 = Na3PO4 + H2O =>
3 NaOH + H3PO4 = Na3PO4 + 3 H2O
KMnO4 + H2SO4 + FeSO4 = Fe(SO4)3 + MnSO4 + K2SO4 + H2O =>
4 KMnO4 + 16 H2SO4 + 5 FeSO4 = 5 Fe(SO4)3 + 4 MnSO4 + 2 K2SO4 + 16 H2O
HNO3 + H2O + As2S3 = H3AsO3 + S + NO =>
2 HNO3 + 2 H2O + As2S3 = 2 H3AsO3 + 3 S + 2 NO
HNO3 + H2O + As2S3 = H3AsO3 + S + NO =>
2 HNO3 + 2 H2O + As2S3 = 2 H3AsO3 + 3 S + 2 NO
HNO3 + Na2HPO4 + (NH4)2MoO4 = (NH4)3(PMo12O40) + NH4NO3 + NaNO3 + H2O =>
23 HNO3 + Na2HPO4 + 12(NH4)2MoO4 = (NH4)3(PMo12O40) + 21 NH4NO3 + 2 NaNO3 + 12 H2O
Na2B4O7(s) + H2O(l) = NaB(OH)4(aq) + H3BO3(aq) =>
Na2B4O7(s) + 7 H2O(l) = 2 NaB(OH)4(aq) + 2 H3BO3(aq)
NiCl2 + NaBH4 = BNi + HCl + NaH2 =>
NiCl2 + NaBH4 = BNi + 2 HCl + NaH2
BaNO3 + HPO4 = BaPO4 + HNO3 =>
BaNO3 + HPO4 = BaPO4 + HNO3
Ca(OH)2 + H3PO4 = Ca2P2O7 + H2O =>
2 Ca(OH)2 + 2 H3PO4 = Ca2P2O7 + 5 H2O
P{4+} + O{2+} = P{2+} + O{5+} =>
3 P{4+} + 2 O{2+} = 3 P{2+} + 2 O{5+}
CH3CH2(OH)CH3 + Fe = CH3CH2(OH)Fe + CH3 =>
CH3CH2(OH)CH3 + Fe = CH3CH2(OH)Fe + CH3
NiCl2 + NaBH4 = BNi + HCl + NaH2 =>
NiCl2 + NaBH4 = BNi + 2 HCl + NaH2
AgNO3(aq) + NaCl(aq) = AgCl + Na + NO3(aq) =>
AgNO3(aq) + NaCl(aq) = AgCl + Na + NO3(aq)
HNO3 + H2O + As2S3 = H3AsO3 + S + NO =>
2 HNO3 + 2 H2O + As2S3 = 2 H3AsO3 + 3 S + 2 NO
CaO + HCl = CaCl + H + O =>
CaO + HCl = CaCl + H + O
CoCl2 + FeCl2 = CoCl3 + Fe =>
2 CoCl2 + FeCl2 = 2 CoCl3 + Fe
HNO3 + H2O + As2S3 = H3AsO3 + S + NO =>
2 HNO3 + 2 H2O + As2S3 = 2 H3AsO3 + 3 S + 2 NO
NiCl2 + NaBH4 = BNi + HCl + NaH2 =>
NiCl2 + NaBH4 = BNi + 2 HCl + NaH2
NiCl2 + NaBH4 = BNi + HCl + NaH2 =>
NiCl2 + NaBH4 = BNi + 2 HCl + NaH2
CH3CH2(OH)CH3 + Fe = CH3CH2(OH)Fe + CH3 =>
CH3CH2(OH)CH3 + Fe = CH3CH2(OH)Fe + CH3
NaOH + K2S = KOH + Na2S =>
2 NaOH + K2S = 2 KOH + Na2S
C4H10 + O2 = CO2 + H2O =>
2 C4H10 + 13 O2 = 8 CO2 + 10 H2O
HCl + RbCO3 = H2O + Cl2 + Rb + CO2 =>
2 HCl + RbCO3 = H2O + Cl2 + Rb + CO2
Mg + Fe(SO4)3 = Fe + MgSO4 =>
3 Mg + Fe(SO4)3 = Fe + 3 MgSO4
F2 + (NH4)2O = NH4F + O2 =>
2 F2 + 2(NH4)2O = 4 NH4F + O2
HNO3 + H2O + As2S3 = H3AsO3 + S + NO =>
2 HNO3 + 2 H2O + As2S3 = 2 H3AsO3 + 3 S + 2 NO
Zn + H2SO = ZnSO4 + H2S + H2O =>
Zn + 5 H2SO = ZnSO4 + 4 H2S + H2O
ZnSO3 + H2CO3 = ZnCO3 + H2SO3 =>
ZnSO3 + H2CO3 = ZnCO3 + H2SO3
H2O2 + NaOCl = HCl + Na2O + O2 =>
2 H2O2 + 4 NaOCl = 4 HCl + 2 Na2O + 3 O2
BaO + SO2 = BaSO4 + BaS =>
4 BaO + 4 SO2 = 3 BaSO4 + BaS
NaClO3 + H2SO4 + SO2 = NaHSO4 + ClO2 =>
2 NaClO3 + H2SO4 + SO2 = 2 NaHSO4 + 2 ClO2
MnCl2 + Al2(SO4)3 = MnSO4 + AlCl3 =>
3 MnCl2 + Al2(SO4)3 = 3 MnSO4 + 2 AlCl3
OH{-} + MnO4{-} + HSO3 = MnO4{2-} + SO4{2-} + H2O =>
3 OH{-} + MnO4{-} + HSO3 = MnO4{2-} + SO4{2-} + 2 H2O
Cu(s) + HCl = H + CuCl =>
Cu(s) + HCl = H + CuCl
K2Cr2O7 + NaOH + Na2SO3 = Na2CrO4 + Na2S + K2SO4 + H2O =>
3 K2Cr2O7 + 6 NaOH + 4 Na2SO3 = 6 Na2CrO4 + Na2S + 3 K2SO4 + 3 H2O
[Co(H2O)6]Cl2 + [H3NCH2CH2NH3]Cl2 = [Co(H2NCH2CH2NH2)3]Cl2 + H2O + HCl =>
[Co(H2O)6]Cl2 + 3[H3NCH2CH2NH3]Cl2 = [Co(H2NCH2CH2NH2)3]Cl2 + 6 H2O + 6 HCl
SO3 + BaCl2 = BaSO4 + Cl + SO2 =>
2 SO3 + BaCl2 = BaSO4 + 2 Cl + SO2
Na4[Fe(CN)6] + Na2CO3 + H2O = FeCO3 + HCN + NaOH =>
Na4[Fe(CN)6] + Na2CO3 + 6 H2O = FeCO3 + 6 HCN + 6 NaOH
Ca(NO3)2 + Na(CO3) = Na(NO3)2 + CaCO3 =>
Ca(NO3)2 + Na(CO3) = Na(NO3)2 + CaCO3
H2SO3 + KI + H2O2 = I2 + H2O + KSO3 =>
2 H2SO3 + 2 KI + 2 H2O2 = I2 + 4 H2O + 2 KSO3
Na3CO3 + CH3COOH = H2O + CO2 + Na =>
4 Na3CO3 + CH3COOH = 2 H2O + 6 CO2 + 12 Na
CH3CH2(OH)CH3 + Fe = CH3CH2(OH)Fe + CH3 =>
CH3CH2(OH)CH3 + Fe = CH3CH2(OH)Fe + CH3
Mg(s) + AgNO3(aq) = Ag + Mg(NO3)2(aq) =>
Mg(s) + 2 AgNO3(aq) = 2 Ag + Mg(NO3)2(aq)
C7H8(l) + O2(g) = CO2 + H20(l) =>
5 C7H8(l) + 35 O2(g) = 35 CO2 + 2 H20(l)
HNO3 + H2O + As2S3 = H3AsO3 + S + NO =>
2 HNO3 + 2 H2O + As2S3 = 2 H3AsO3 + 3 S + 2 NO
CH3CH(OH)COOH + Na = CH3CH(ONa)COONa + H2 =>
CH3CH(OH)COOH + 2 Na = CH3CH(ONa)COONa + H2
Cr(OH)4({-}2) + O2({-}2) = CrO4({-}2) + OH({-}1) + H2O =>
3 Cr(OH)4({-}2) + 4 O2({-}2) = 3 CrO4({-}2) + 4 OH({-}1) + 4 H2O
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Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 01/04/24
Equations balanced on 02/03/23
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