Equations balanced on the previous day | Equations balanced on the next day |
K2Cr2O7 + 3 Ti2(SO4)3 + H2SO4 = Cr2(SO4)3 + 6 TiO(SO4) + H2O + K2SO4
AlBr3(s) + Cl2(g) = AlCl3(g) + Br2(g) =>
2 AlBr3(s) + 3 Cl2(g) = 2 AlCl3(g) + 3 Br2(g)
NaClO4 + Pb(NO3)2 = NaPb + (NO3)2ClO4 =>
NaClO4 + Pb(NO3)2 = NaPb + (NO3)2ClO4
NH2Cl(aq) + NaOH(aq) = NaOCl + NH3 =>
NH2Cl(aq) + NaOH(aq) = NaOCl + NH3
NH3 + Co(H2O)6 = Co(NH3)6 + H2O =>
6 NH3 + Co(H2O)6 = Co(NH3)6 + 6 H2O
FeCl3 + KSCN = Fe(SCN)3 + KCl =>
FeCl3 + 3 KSCN = Fe(SCN)3 + 3 KCl
(NH4)2CO3 + Ti3(PO4)4 = (NH4)3PO4 + Ti(CO3)2 =>
6(NH4)2CO3 + Ti3(PO4)4 = 4(NH4)3PO4 + 3 Ti(CO3)2
FeCl3(aq) + KSCN(aq) = Fe(SCN)3(aq) + KCl(aq) =>
FeCl3(aq) + 3 KSCN(aq) = Fe(SCN)3(aq) + 3 KCl(aq)
C7H16 + O2 = CO2 + H2O =>
C7H16 + 11 O2 = 7 CO2 + 8 H2O
CH2CHCH3 + KMnO4 + HCl + H2O = CH2OHCHOHCH3 + MnCl2 + KCl =>
5 CH2CHCH3 + 2 KMnO4 + 6 HCl + 2 H2O = 5 CH2OHCHOHCH3 + 2 MnCl2 + 2 KCl
NaClO4 + Pb(NO3)2 = Na(NO3) + Pb(ClO4)2 =>
2 NaClO4 + Pb(NO3)2 = 2 Na(NO3) + Pb(ClO4)2
Na2CO3 + CH3COOH = H2CO3 + CH3COONa =>
Na2CO3 + 2 CH3COOH = H2CO3 + 2 CH3COONa
NaClO4 + Pb(NO3)2 = Na(NO3)2 + PbClO4 =>
NaClO4 + Pb(NO3)2 = Na(NO3)2 + PbClO4
C + H2SO4 = CO2 + SO2 + H2O =>
C + 2 H2SO4 = CO2 + 2 SO2 + 2 H2O
N2(g) + O2 = N2O5(g) =>
2 N2(g) + 5 O2 = 2 N2O5(g)
Ca2(OH)2 + HF = CaFH2O =>
Ca2(OH)2 + 2 HF = 2 CaFH2O
Cu{2+} + H2PO2{-} + OH{-} = CuH2 + PO4{-} + H2O =>
3 Cu{2+} + 2 H2PO2{-} + 6 OH{-} = 3 CuH2 + 2 PO4{-} + 2 H2O
C6H6 + oxygen = CO + H2O =>
2 C6H6 + 9 O2 = 12 CO + 6 H2O
NaOH + C21H42O5 + H2O = C3H8O3 + C18H35O2Na =>
9 NaOH + 10 C21H42O5 + 7 H2O = 16 C3H8O3 + 9 C18H35O2Na
CO2(g) + H2O(g) = C6H12O6(s) + O2 =>
6 CO2(g) + 6 H2O(g) = C6H12O6(s) + 6 O2
Zn2 + Fe3(NO3)2 = Zn(NO3)2 + Fe3 =>
Zn2 + 2 Fe3(NO3)2 = 2 Zn(NO3)2 + 2 Fe3
FeCl3 + K2C2O4*H2O = K3Fe(C2O4)3*3H2O + KCl =>
FeCl3 + 3 K2C2O4*H2O = K3Fe(C2O4)3*3H2O + 3 KCl
C10H22 + O = CO2 + H2 =>
C10H22 + 20 O = 10 CO2 + 11 H2
HNO3(aq) + NaCl(aq) = NaNO3 + HCl =>
HNO3(aq) + NaCl(aq) = NaNO3 + HCl
AgNo3 + Na2S2O3 = AgS2O3 + Na2No3 =>
AgNo3 + Na2S2O3 = AgS2O3 + Na2No3
KMnO3 + Fe + HCl = MnCl2 + FeCl3 + KCl + H2O =>
KMnO3 + Fe + 6 HCl = MnCl2 + FeCl3 + KCl + 3 H2O
I2 + KCIO3 + H2O = KIO3 + HIO2 + HCI =>
2 I2 + 3 KCIO3 + 2 H2O = 3 KIO3 + HIO2 + 3 HCI
Ca(OH)2 + H2SO4 = CaSO4 + H2O =>
Ca(OH)2 + H2SO4 = CaSO4 + 2 H2O
HgS + HNO3 + HCl = H2HgCl4 + NO + H2O + S =>
3 HgS + 2 HNO3 + 12 HCl = 3 H2HgCl4 + 2 NO + 4 H2O + 3 S
Na3PO4 + AgNO3 = Na2NO3 + Ag3(PO4)2 =>
2 Na3PO4 + 3 AgNO3 = 3 Na2NO3 + Ag3(PO4)2
Mg(OH)2 + N2O5 = Mg(NO3)2 + H2O =>
Mg(OH)2 + N2O5 = Mg(NO3)2 + H2O
Na2SO4 + C2 = CO2 + Na2S =>
Na2SO4 + C2 = 2 CO2 + Na2S
Se + Na = Na2Se =>
Se + 2 Na = Na2Se
K + Na3(Co(NO2)6)6 = Na + K3(Co(NO2)6) =>
18 K + Na3(Co(NO2)6)6 = 3 Na + 6 K3(Co(NO2)6)
HNO3 + HI = NO2 + HIO3 + H2O =>
6 HNO3 + HI = 6 NO2 + HIO3 + 3 H2O
MoS2 = Mo + S8 =>
4 MoS2 = 4 Mo + S8
HBrO4 + H2SO4 + Tb(OH)3 = Tb(BrO4)(SO4) + H2O =>
HBrO4 + H2SO4 + Tb(OH)3 = Tb(BrO4)(SO4) + 3 H2O
MnO2 + HCl + NaBiO3 = H2O + HMnO4 + BiCl3 + NaCl =>
2 MnO2 + 12 HCl + 3 NaBiO3 = 5 H2O + 2 HMnO4 + 3 BiCl3 + 3 NaCl
NH2OH + I2 = HI + N2 + H2O =>
2 NH2OH + I2 = 2 HI + N2 + 2 H2O
C10H22 + O2 = CO2 + H2O =>
2 C10H22 + 31 O2 = 20 CO2 + 22 H2O
Ba(OH)2 + FeCl2 = Fe(OH)2 + BaCl2 =>
Ba(OH)2 + FeCl2 = Fe(OH)2 + BaCl2
MnO2 + HBr = Br2 + MnBr2 + H2O =>
MnO2 + 4 HBr = Br2 + MnBr2 + 2 H2O
MnO2 + HCl(aq) = MnCl2 + Cl2 + H2O =>
MnO2 + 4 HCl(aq) = MnCl2 + Cl2 + 2 H2O
HCl(aq) + Sr(s) = H2(g) + SrCl2(aw) =>
2 HCl(aq) + Sr(s) = H2(g) + SrCl2(aw)
H2SO4(aq) + FeCl2 = FeSO4 + HCl =>
H2SO4(aq) + FeCl2 = FeSO4 + 2 HCl
BaCl2Na2SO4 = BaSO4 + NaCl =>
BaCl2Na2SO4 = BaSO4 + 2 NaCl
HC2H3O2 + O2 = CO2 + H2O =>
HC2H3O2 + 2 O2 = 2 CO2 + 2 H2O
Zn + H3AsO3 = AsH3 + ZnO =>
3 Zn + H3AsO3 = AsH3 + 3 ZnO
Fe3O4 + Sb(OH)6{-} + H{+} = Fe2O3 + Sb + H2O =>
10 Fe3O4 + 2 Sb(OH)6{-} + 2 H{+} = 15 Fe2O3 + 2 Sb + 7 H2O
CoCl2 + NH4 + H2O2 + HCl = (Co(NH3)5Cl)Cl2 + H2O =>
CoCl2 + 5 NH4 + 3 H2O2 + HCl = (Co(NH3)5Cl)Cl2 + 6 H2O
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 12/18/23
Equations balanced on 01/17/23
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