Equations balanced on the previous day | Equations balanced on the next day |
4 H2C2HO3 + 5 O2 = 8 CO2 + 6 H2O
CH3OH(l) + PBr3(l) = CH3Br(l) + H3PO3(l) =>
3 CH3OH(l) + PBr3(l) = 3 CH3Br(l) + H3PO3(l)
Pb(NO3)2(aq) + AgNO3(aq) = PbNO3(aq) + Ag(NO3)2(aq) =>
Pb(NO3)2(aq) + AgNO3(aq) = PbNO3(aq) + Ag(NO3)2(aq)
P4 + NaOH + H2O = NaH2PO3 + P2H4 =>
5 P4 + 8 NaOH + 16 H2O = 8 NaH2PO3 + 6 P2H4
C2H5ONa + HCl = C2H5OH + NaCl =>
C2H5ONa + HCl = C2H5OH + NaCl
FeSO4 + NaHCO3 = FeCO3 + Na2SO4 + CO2 + H2O =>
FeSO4 + 2 NaHCO3 = FeCO3 + Na2SO4 + CO2 + H2O
Ca = Ca{2+} + e =>
Ca = Ca{2+} + 2e
Co(NO3)2H2O + P(OPh)3 + BH4 = CoH[P(OPh)3]4 + BH3 + NO3 + H2O =>
Co(NO3)2H2O + 4 P(OPh)3 + BH4 = CoH[P(OPh)3]4 + BH3 + 2 NO3 + H2O
AsH3 + H2O = H3AsO4 + H =>
AsH3 + 4 H2O = H3AsO4 + 8 H
NaC2H2O2 + H2O = NaOH + C2H3O2 =>
NaC2H2O2 + H2O = NaOH + C2H3O2
Sr(s) + NiCl2(aq) = Ni(s) + SrCl2(aq) =>
Sr(s) + NiCl2(aq) = Ni(s) + SrCl2(aq)
KBr + KMnO4 + H2O = Br2 + MnO2 + KOH =>
6 KBr + 2 KMnO4 + 4 H2O = 3 Br2 + 2 MnO2 + 8 KOH
NaClO + H2O = NaCl + H2O2 =>
NaClO + H2O = NaCl + H2O2
NH3 + O2 = NO6 + H2O =>
4 NH3 + 15 O2 = 4 NO6 + 6 H2O
Cd3(PO4)2 + NH3 = Cd3(NH3)2 + PO4 =>
Cd3(PO4)2 + 2 NH3 = Cd3(NH3)2 + 2 PO4
NaHCO3 + FeSO4 = FeCO3 + NaHSO4 =>
NaHCO3 + FeSO4 = FeCO3 + NaHSO4
C4H9OH + O2 = H2O + C =>
C4H9OH + 2 O2 = 5 H2O + 4 C
CuCO + HClO = CuCl2 + CO2 + H2O =>
CuCO + 2 HClO = CuCl2 + CO2 + H2O
Li2S + Cl2 = Li + ClS =>
2 Li2S + Cl2 = 4 Li + 2 ClS
Al + HBr = HBrAl =>
Al + HBr = HBrAl
CuNO3 + (NH3)2CO3 = Cu2CO3 + NH3NO3 =>
2 CuNO3 + (NH3)2CO3 = Cu2CO3 + 2 NH3NO3
NaMnO4 + MgI2 + H2SO4 = I2 + MnSO4 + MgSO4 + NaSO4 + H2O =>
NaMnO4 + 2 MgI2 + 4 H2SO4 = 2 I2 + MnSO4 + 2 MgSO4 + NaSO4 + 4 H2O
KBr + KMnO4 + H2O = Br2 + MnO2 + KOH =>
6 KBr + 2 KMnO4 + 4 H2O = 3 Br2 + 2 MnO2 + 8 KOH
KBr + KMnO4 + H2O = Br2 + MnO2 + KOH =>
6 KBr + 2 KMnO4 + 4 H2O = 3 Br2 + 2 MnO2 + 8 KOH
IO3{-} + SO3{2-}{+}{+} = I{-} + SO4{2-} =>
IO3{-} + 3 SO3{2-}{+}{+} = I{-} + 3 SO4{2-}
LiOH + FeCl2 + H3PO4 = LiFePO4 + HCl + H2O =>
LiOH + FeCl2 + H3PO4 = LiFePO4 + 2 HCl + H2O
Ca(OH)2 + H3PO4 = Ca3(PO4)2 + H2O =>
3 Ca(OH)2 + 2 H3PO4 = Ca3(PO4)2 + 6 H2O
C2H4O2 + NaCO3 = CO2 + H2O + NaC2H3O2 =>
9 C2H4O2 + 8 NaCO3 = 10 CO2 + 6 H2O + 8 NaC2H3O2
Fe(OH)3 + KI + H2SO4 = Fe(OH)2 + I2 + K2SO4 + H2O =>
2 Fe(OH)3 + 2 KI + H2SO4 = 2 Fe(OH)2 + I2 + K2SO4 + 2 H2O
Al2O3 + N2H4 = Al + N2 + H2O =>
2 Al2O3 + 3 N2H4 = 4 Al + 3 N2 + 6 H2O
C2H5OH(l) + O2 = CO2(g) + H2O(l) =>
C2H5OH(l) + 3 O2 = 2 CO2(g) + 3 H2O(l)
MgSO4 + Cl2 + H2O = Mg(OH) + ClSO4 + HCl =>
MgSO4 + Cl2 + H2O = Mg(OH) + ClSO4 + HCl
C8H18O8 + O2 = CO2 + H2O =>
2 C8H18O8 + 17 O2 = 16 CO2 + 18 H2O
Fe + CuCl = FeCl + Cu =>
Fe + CuCl = FeCl + Cu
HOOCCOOH + Fe(OH)3 = Fe2(OOCCOO)3 + H2O =>
3 HOOCCOOH + 2 Fe(OH)3 = Fe2(OOCCOO)3 + 6 H2O
Pd + H2SO4 = PdSO4 + H2O + SO2 =>
Pd + 2 H2SO4 = PdSO4 + 2 H2O + SO2
HC2H3OO + NaOH = NaC2H3O2 + H2O =>
HC2H3OO + NaOH = NaC2H3O2 + H2O
SodiumHydroxide + CarbonDioxide = SodiumCarbonate + H2O =>
2 NaOH + CO2 = Na2CO3 + H2O
FeCl2 + NH4C2H3O2 = Fe(C2H3O2)2 + NH4Cl =>
FeCl2 + 2 NH4C2H3O2 = Fe(C2H3O2)2 + 2 NH4Cl
C4H8O2(l) + O2(g) = H2O(l) + C2O(g) =>
C4H8O2(l) + 2 O2(g) = 4 H2O(l) + 2 C2O(g)
(Pb)2 + (CrO4)2 = PbCrO4 =>
(Pb)2 + (CrO4)2 = 2 PbCrO4
K + CO2 + H2 = KHCO3 + CO =>
2 K + 4 CO2 + H2 = 2 KHCO3 + 2 CO
CaCo3 + H2SO4 = CaCo3SO4 + H2 =>
CaCo3 + H2SO4 = CaCo3SO4 + H2
SrBr + KSO = SrSO + KBr =>
SrBr + KSO = SrSO + KBr
CHO(CH2)7COOH + K2Cr2O7 + H2SO4 = COOH(CH2)7COOH + Cr2(SO4)2 + K2SO4 + H2O =>
4 CHO(CH2)7COOH + K2Cr2O7 + 3 H2SO4 = 4 COOH(CH2)7COOH + Cr2(SO4)2 + K2SO4 + 3 H2O
Fe(NH4)2(SO4)2 = Fe + NH4 + SO4 =>
Fe(NH4)2(SO4)2 = Fe + 2 NH4 + 2 SO4
HCHO2 = H2O + CO =>
HCHO2 = H2O + CO
H2 + ClO = HCl + H2O =>
3 H2 + 2 ClO = 2 HCl + 2 H2O
Li + MgBr2 = LiBr + Mg =>
2 Li + MgBr2 = 2 LiBr + Mg
octane + O2 = H2O + CO2 =>
2 C8H18 + 25 O2 = 18 H2O + 16 CO2
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 12/05/23
Equations balanced on 01/04/23
Geben Sie uns Rückmeldungen zu Ihren Erfahrungen mit dem Programm zum Berechnen chemischer Reaktionsgleichungen.