Equations balanced on the previous day | Equations balanced on the next day |
NaClO + H2O = HOCl + NaOH
Zn(NO3)2*6H2O + Na3PO4*12H2O = Zn3(PO4)2*4H2O + NaNO3 + H2O =>
3 Zn(NO3)2*6H2O + 2 Na3PO4*12H2O = Zn3(PO4)2*4H2O + 6 NaNO3 + 38 H2O
KMnO4 + SnOCl2 + HCl = KCl + MnCl2 + SnOCl4 + H2O =>
2 KMnO4 + 5 SnOCl2 + 16 HCl = 2 KCl + 2 MnCl2 + 5 SnOCl4 + 8 H2O
Ag + HNO3 = AgNO3 + NO + H2O =>
3 Ag + 4 HNO3 = 3 AgNO3 + NO + 2 H2O
CHCl3 + H2 + O2 = HCl + CO2 =>
CHCl3 + H2 + O2 = 3 HCl + CO2
HC2H3O2(aq) + K2CO3(aq) = H2O(l) + CO2(g) + KC3H3O2(aq) =>
3 HC2H3O2(aq) + K2CO3(aq) = 3 H2O(l) + CO2(g) + 2 KC3H3O2(aq)
C4H8O + O2 = CO2H2O =>
2 C4H8O + 11 O2 = 8 CO2H2O
I3{-} + SO4{2-} = I{-} + S2O8{2-} =>
I3{-} + 2 SO4{2-} = 3 I{-} + S2O8{2-}
Au(OH)3 + H{+} + {-} = Au + H2O =>
Au(OH)3 + 3 H{+} + 3e = Au + 3 H2O
NaOH + H3PO4 = NaO + H4PO4 =>
NaOH + H3PO4 = NaO + H4PO4
KMnO4 + H2O = KOH + H2MnO3 + O2 =>
4 KMnO4 + 6 H2O = 4 KOH + 4 H2MnO3 + 3 O2
Cu(s) + O2(s) = Cu2O(s) =>
4 Cu(s) + O2(s) = 2 Cu2O(s)
C14H28 + O2 = CO + H2O =>
C14H28 + 14 O2 = 14 CO + 14 H2O
C4HO04COOH + O2 = CO2 + H2O =>
2 C4HO04COOH + 5 O2 = 10 CO2 + 2 H2O
Pb + K2CrO4 = PbO + K2O + Cr2O =>
5 Pb + 2 K2CrO4 = 5 PbO + 2 K2O + Cr2O
CH2C(X)2 + KMnO4 + H2SO4 = XC(O)X + CO2 + MnSO4 + K2SO4 + H2O =>
5 CH2C(X)2 + 8 KMnO4 + 12 H2SO4 = 5 XC(O)X + 5 CO2 + 8 MnSO4 + 4 K2SO4 + 17 H2O
As + ClO3 + H2O = H3AsO3 + HClO =>
5 As + 3 ClO3 + 9 H2O = 5 H3AsO3 + 3 HClO
BaCl2 + AgNO3 = Ba(NO3) + Ag(Cl2) =>
BaCl2 + AgNO3 = Ba(NO3) + Ag(Cl2)
C + H2O = CO + H2 =>
C + H2O = CO + H2
Ni + CO = Ni(CO)4 =>
Ni + 4 CO = Ni(CO)4
NaBr(aq) + Pb(NO3)2(aq) = NaNO3 + PbBr2(aq) =>
2 NaBr(aq) + Pb(NO3)2(aq) = 2 NaNO3 + PbBr2(aq)
P4 + H2O = P2O10 + H2 =>
P4 + 20 H2O = 2 P2O10 + 20 H2
Cd(OH)2 + Na2S2O4 = CdO + H2S + Na2O + H2O2 =>
7 Cd(OH)2 + Na2S2O4 = 7 CdO + 2 H2S + Na2O + 5 H2O2
FeCl3 + KOH = Fe(OH)3 + Cl3K3 =>
FeCl3 + 3 KOH = Fe(OH)3 + Cl3K3
K2O + H2SO3 = K2SO3 + H2O =>
K2O + H2SO3 = K2SO3 + H2O
(NH3)4 + H2SO4 = (NH4)2SO4 =>
(NH3)4 + 2 H2SO4 = 2(NH4)2SO4
NaOH{-} = OH{-} + Na =>
NaOH{-} = OH{-} + Na
As + O2 = As2O3 =>
4 As + 3 O2 = 2 As2O3
X2 + H2O = HXO + H{-} + X{+} =>
X2 + H2O = HXO + H{-} + X{+}
FeCl3 + NH4HCO3 = FeHCO3 + Cl3NH4 =>
FeCl3 + NH4HCO3 = FeHCO3 + Cl3NH4
IO2 + H2 = H2O + I =>
IO2 + 2 H2 = 2 H2O + I
Sb2S3 + HNO3 = H2SbO4 + SO2 + NO + H2O =>
Sb2S3 + 8 HNO3 = 2 H2SbO4 + 3 SO2 + 8 NO + 2 H2O
H3PO4 + (Ca(OH)2) = (Ca3(PO4)2) + H2O =>
2 H3PO4 + 3(Ca(OH)2) = (Ca3(PO4)2) + 6 H2O
KMnO4 + FeCl2 + HCl = KCl + MnCl3 + FeCl3 + H2O =>
KMnO4 + 4 FeCl2 + 8 HCl = KCl + MnCl3 + 4 FeCl3 + 4 H2O
C2H6 + O = CO2 + H2O =>
C2H6 + 7 O = 2 CO2 + 3 H2O
H2 + NF3 = N2 + H2F =>
6 H2 + 2 NF3 = N2 + 6 H2F
C12H22O2 + O2 = CO2 + H2O =>
2 C12H22O2 + 33 O2 = 24 CO2 + 22 H2O
Ca(s) + H2O(l) = CaO(aq) + H2(s) =>
Ca(s) + H2O(l) = CaO(aq) + H2(s)
NaOH + FrCl = NaCl + FrOH =>
NaOH + FrCl = NaCl + FrOH
KAl3Si3O10(OH)2 + SiO2 + C = KAlSi3O8 + Al2SiO5 + CH4 + CO2 =>
2 KAl3Si3O10(OH)2 + 2 SiO2 + 2 C = 2 KAlSi3O8 + 2 Al2SiO5 + CH4 + CO2
Fe6O8 + PuO2(H2O)5{+} = Fe4PuO8 + Fe(H2O)6{+3} + Fe(H2O)6{+2} + OH{-} =>
35 Fe6O8 + 44 PuO2(H2O)5{+} = 44 Fe4PuO8 + 8 Fe(H2O)6{+3} + 26 Fe(H2O)6{+2} + 32 OH{-}
CH3CH2{+} + SO4{-} = CH3CH2SO4 =>
CH3CH2{+} + SO4{-} = CH3CH2SO4
O2{-} + H2O = OH{-} + O2 =>
4 O2{-} + 2 H2O = 4 OH{-} + 3 O2
C8H8 + H2 = C9H20 =>
9 C8H8 + 44 H2 = 8 C9H20
Cr + Na2S = CrS + Na =>
Cr + Na2S = CrS + 2 Na
KBr + Ca(CH3CO2)2 = K(CH3CO2)2 + CaBr =>
KBr + Ca(CH3CO2)2 = K(CH3CO2)2 + CaBr
LiBr + Co(SO4)2 = Li(SO4)2 + CoBr =>
LiBr + Co(SO4)2 = Li(SO4)2 + CoBr
Rb(s) + Br2(g) = Rb2Br =>
4 Rb(s) + Br2(g) = 2 Rb2Br
HAuCl4 + Na2SO3 + NaOH = Na2SO4 + NaCl + Na3Au(SO3)2 + H2O =>
HAuCl4 + 3 Na2SO3 + 3 NaOH = Na2SO4 + 4 NaCl + Na3Au(SO3)2 + 2 H2O
K2CrO7 + KI + H2SO4 = K2SO4 + Cr2(SO4)3 + H2O + I1 =>
2 K2CrO7 + 18 KI + 14 H2SO4 = 11 K2SO4 + Cr2(SO4)3 + 14 H2O + 18 I1
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 11/30/23
Equations balanced on 12/30/22
Geben Sie uns Rückmeldungen zu Ihren Erfahrungen mit dem Programm zum Berechnen chemischer Reaktionsgleichungen.