Equations balanced on the previous day | Equations balanced on the next day |
C9H13N + CH2O = C10H13N + H2O
SrCl2 + Na3PO4 = Sr(PO4)2 + Na3Cl =>
SrCl2 + 2 Na3PO4 = Sr(PO4)2 + 2 Na3Cl
(d)NaHCO3(s) + HCl(aq) = NaCl(aq) + H2O(l) + CO2(g) =>
(d)NaHCO3(s) + HCl(aq) = NaCl(aq) + H2O(l) + CO2(g)
CO2 + H2O = H2CO3 = HCO3{-} + H{ =>
CO2 + H2O = H2CO3
CH4 + O2 = CO2 + H2O =>
CH4 + 2 O2 = CO2 + 2 H2O
NH3 + SO2 = NO + S + H2O =>
4 NH3 + 5 SO2 = 4 NO + 5 S + 6 H2O
Mg2N2(s) = Mg(s) + N2(g) =>
Mg2N2(s) = 2 Mg(s) + N2(g)
MnO2 + NaCl + H2O = MnCl2 + O2 + NaOH =>
2 MnO2 + 4 NaCl + 2 H2O = 2 MnCl2 + O2 + 4 NaOH
Ba(NO3)2 + (Li)2SO4 = BaSO4 + LiNO3 =>
Ba(NO3)2 + (Li)2SO4 = BaSO4 + 2 LiNO3
Ba(NO3)2 + (Li)2SO4 = BaSO4 + LiNO3 =>
Ba(NO3)2 + (Li)2SO4 = BaSO4 + 2 LiNO3
Al(OH)3 + Na2CO3 + H2O = Na[Al(OH)4] + CO2 =>
2 Al(OH)3 + Na2CO3 + H2O = 2 Na[Al(OH)4] + CO2
MnO2 + NaCl + H2O = MnCl2 + O2 + NaOH =>
2 MnO2 + 4 NaCl + 2 H2O = 2 MnCl2 + O2 + 4 NaOH
MnO2 + NaCl + H2O = MnCl2 + O2 + NaOH =>
2 MnO2 + 4 NaCl + 2 H2O = 2 MnCl2 + O2 + 4 NaOH
Al(OH)3 + Na2CO3 + H2O = Na[Al(OH)4] + CO2 =>
2 Al(OH)3 + Na2CO3 + H2O = 2 Na[Al(OH)4] + CO2
HgCl2 + KI = Hg2Cl2 + I2 + KCl =>
2 HgCl2 + 2 KI = Hg2Cl2 + I2 + 2 KCl
HgCl2 + KI = Hg2Cl2 + I2 + KCl =>
2 HgCl2 + 2 KI = Hg2Cl2 + I2 + 2 KCl
HgCl2 + KI = Hg2Cl2 + I2 + KCl =>
2 HgCl2 + 2 KI = Hg2Cl2 + I2 + 2 KCl
Al(OH)3 + Na2CO3 + H2O = Na[Al(OH)4] + CO2 =>
2 Al(OH)3 + Na2CO3 + H2O = 2 Na[Al(OH)4] + CO2
HgCl2 + KI = Hg2Cl2 + I2 + KCl =>
2 HgCl2 + 2 KI = Hg2Cl2 + I2 + 2 KCl
Ba(NO3)2 + (Li)2SO4 = BaSO4 + LiNO3 =>
Ba(NO3)2 + (Li)2SO4 = BaSO4 + 2 LiNO3
Al(OH)3 + Na2CO3 + H2O = Na[Al(OH)4] + CO2 =>
2 Al(OH)3 + Na2CO3 + H2O = 2 Na[Al(OH)4] + CO2
MnO2 + NaCl + H2O = MnCl2 + O2 + NaOH =>
2 MnO2 + 4 NaCl + 2 H2O = 2 MnCl2 + O2 + 4 NaOH
Bi(NO3)3 + Ti(NO3)2 + C2H6N4O2 = Bi4Ti3O12 + N2 + CO2 + H2O =>
20 Bi(NO3)3 + 15 Ti(NO3)2 + 42 C2H6N4O2 = 5 Bi4Ti3O12 + 129 N2 + 84 CO2 + 126 H2O
Ba(NO3)2 + (Li)2SO4 = BaSO4 + LiNO3 =>
Ba(NO3)2 + (Li)2SO4 = BaSO4 + 2 LiNO3
MnO2 + Sn(OH)4 = Mn(OH)2 + Sn(O2)2 =>
2 MnO2 + Sn(OH)4 = 2 Mn(OH)2 + Sn(O2)2
HgCl2 + KI = KCl + K2HgI4 =>
HgCl2 + 4 KI = 2 KCl + K2HgI4
Mg(NO3)2*6H2O + C6H15NO3 = Mg(OC2H5)2 + N2 + CO2 + H2O =>
33 Mg(NO3)2*6H2O + 34 C6H15NO3 = 33 Mg(OC2H5)2 + 50 N2 + 72 CO2 + 288 H2O
C6H5FeO7H2O + NaC2H3O2*3H2O + C5H8O2 = Fe(C5H7O2)3 + NaC6H5O7 + HC2H3O2 =>
16 C6H5FeO7H2O + 5 NaC2H3O2*3H2O + 62 C5H8O2 = 16 Fe(C5H7O2)3 + 5 NaC6H5O7 + 73 HC2H3O2
MnO2 + NaCl + H2O = MnCl2 + O2 + NaOH =>
2 MnO2 + 4 NaCl + 2 H2O = 2 MnCl2 + O2 + 4 NaOH
Al(OH)3 + Na2CO3 + H2O = Na[Al(OH)4] + CO2 =>
2 Al(OH)3 + Na2CO3 + H2O = 2 Na[Al(OH)4] + CO2
Al(OH)3 + Na2CO3 + H2O = Na[Al(OH)4] + CO2 =>
2 Al(OH)3 + Na2CO3 + H2O = 2 Na[Al(OH)4] + CO2
MnCl2 + Na2S = MnS + ClNa =>
MnCl2 + Na2S = MnS + 2 ClNa
MnO2 + NaCl + H2O = MnCl2 + O2 + NaOH =>
2 MnO2 + 4 NaCl + 2 H2O = 2 MnCl2 + O2 + 4 NaOH
NaSO4 + ZnNO2 = NaNO2 + SO4Zn =>
NaSO4 + ZnNO2 = NaNO2 + SO4Zn
MnO2 + NaCl + H2O = MnCl2 + O2 + NaOH =>
2 MnO2 + 4 NaCl + 2 H2O = 2 MnCl2 + O2 + 4 NaOH
Ba(NO3)2 + (Li)2SO4 = BaSO4 + LiNO3 =>
Ba(NO3)2 + (Li)2SO4 = BaSO4 + 2 LiNO3
HgCl2 + KI = Hg2Cl2 + I2 + KCl =>
2 HgCl2 + 2 KI = Hg2Cl2 + I2 + 2 KCl
NH3 + O2 = NO + H2O =>
4 NH3 + 5 O2 = 4 NO + 6 H2O
NH3 + SO2 = NO + S + H2O =>
4 NH3 + 5 SO2 = 4 NO + 5 S + 6 H2O
Ba(NO3)2 + (Li)2SO4 = BaSO4 + LiNO3 =>
Ba(NO3)2 + (Li)2SO4 = BaSO4 + 2 LiNO3
H3PO4 + PbCH3CO2 = H3CH3CO2 + PbPO4 =>
H3PO4 + PbCH3CO2 = H3CH3CO2 + PbPO4
Pb(NO3)2 + LiCl = PbCl2 + LiNO3 =>
Pb(NO3)2 + 2 LiCl = PbCl2 + 2 LiNO3
NH2OH + MnO2 = N2O + Mn(OH)2 + H2O =>
2 NH2OH + 2 MnO2 = N2O + 2 Mn(OH)2 + H2O
CaCO3 + CH3COOH = H2O + CO2 + CaC =>
4 CaCO3 + 3 CH3COOH = 6 H2O + 6 CO2 + 4 CaC
Al(OH)3 + Na2CO3 + H2O = Na[Al(OH)4] + CO2 =>
2 Al(OH)3 + Na2CO3 + H2O = 2 Na[Al(OH)4] + CO2
HgCl2 + KI = Hg2Cl2 + I2 + KCl =>
2 HgCl2 + 2 KI = Hg2Cl2 + I2 + 2 KCl
OH + C6H8O7 = C6H6O7 + H2O =>
2 OH + C6H8O7 = C6H6O7 + 2 H2O
Al(OH)3 + Na2CO3 + H2O = Na[Al(OH)4] + CO2 =>
2 Al(OH)3 + Na2CO3 + H2O = 2 Na[Al(OH)4] + CO2
Ba(NO3)2 + (Li)2SO4 = BaSO4 + LiNO3 =>
Ba(NO3)2 + (Li)2SO4 = BaSO4 + 2 LiNO3
MnO2 + NaCl + H2O = MnCl2 + O2 + NaOH =>
2 MnO2 + 4 NaCl + 2 H2O = 2 MnCl2 + O2 + 4 NaOH
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 11/20/23
Equations balanced on 12/20/22
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