Printed from https://www.webqc.org

Chemische Gleichungen im Gleichgewicht auf10/15/19

 Am Vortag ausgeglichene Gleichungen Am nächsten Tag ausgeglichene Gleichungen
Gleichen Sie die Gleichung jeder chemischen Reaktion aus
Fe2O3 + CO = Fe + CO2 =>
Fe2O3 + 3 CO = 2 Fe + 3 CO2

C5H10O2 + O2 = CO2 + H2O =>
2 C5H10O2 + 13 O2 = 10 CO2 + 10 H2O

Cr(s) + Cl2(g) = CrCl3(s) =>
2 Cr(s) + 3 Cl2(g) = 2 CrCl3(s)

(NH4)3PO3 + Fe(NO3)2 = NH4NO3 + Fe3(PO3)2 =>
2(NH4)3PO3 + 3 Fe(NO3)2 = 6 NH4NO3 + Fe3(PO3)2

Mg + HCe = MgCe + H =>
Mg + HCe = MgCe + H

CACO3 + HCl = CACl2 + H2CO3 =>
CACO3 + 2 HCl = CACl2 + H2CO3

Cr(s) + Cl2(g) = CrCl3(s) =>
2 Cr(s) + 3 Cl2(g) = 2 CrCl3(s)

NH2CONH2 + H2O = CO2 + NH3 =>
NH2CONH2 + H2O = CO2 + 2 NH3

Pb(NO3)2 = PbO + NO2 + O2 =>
2 Pb(NO3)2 = 2 PbO + 4 NO2 + O2

Cr(s) + Cl2(g) = CrCl3(s) =>
2 Cr(s) + 3 Cl2(g) = 2 CrCl3(s)

CH4 + O2 = CO2 + H2O =>
CH4 + 2 O2 = CO2 + 2 H2O

O3 = O2 =>
2 O3 = 3 O2

H2SO4(aq) + Al(OH)3(aq) = Al2(SO4)3(aq) + H2O(l) =>
3 H2SO4(aq) + 2 Al(OH)3(aq) = Al2(SO4)3(aq) + 6 H2O(l)

Na2CO3 + HCl = NaCl + CO2 + H2O =>
Na2CO3 + 2 HCl = 2 NaCl + CO2 + H2O

KMnO4 + HCl = MnCl2 + Cl2 + KCl + H2O =>
2 KMnO4 + 16 HCl = 2 MnCl2 + 5 Cl2 + 2 KCl + 8 H2O

Ca(OH)2 + HCl = CaCl2 + H2O =>
Ca(OH)2 + 2 HCl = CaCl2 + 2 H2O

HNO3 + NaHCO3 = NaNO3 + H2O + CO2 =>
HNO3 + NaHCO3 = NaNO3 + H2O + CO2

NaBr + Cl2 = NaCl2 + Br2 =>
2 NaBr + 2 Cl2 = 2 NaCl2 + Br2

C3H7OH + O2 = CO2 + H2O =>
2 C3H7OH + 9 O2 = 6 CO2 + 8 H2O

CH3COOH + NaCO3 = CH3COONa + CO2 + H2O =>
9 CH3COOH + 8 NaCO3 = 8 CH3COONa + 10 CO2 + 6 H2O

O2 + CH3COH = H2O + CO2 =>
5 O2 + 2 CH3COH = 4 H2O + 4 CO2

NaNo3 + H2So4 = Na2So4 + HNo3 =>
2 NaNo3 + H2So4 = Na2So4 + 2 HNo3

H2S + KOH = H2O + K2S =>
H2S + 2 KOH = 2 H2O + K2S

KMnO4 + HCl = MnCl2 + KCl + Cl2 + H2O =>
2 KMnO4 + 16 HCl = 2 MnCl2 + 2 KCl + 5 Cl2 + 8 H2O

NH4Br + NaCl = NaBr + NH4Cl =>
NH4Br + NaCl = NaBr + NH4Cl

NaClO4 + NH4Cl = NaCl + NH4ClO4 =>
NaClO4 + NH4Cl = NaCl + NH4ClO4

H2SO4 + KOH = K2SO4 + H2O =>
H2SO4 + 2 KOH = K2SO4 + 2 H2O

Br2 + Ca(OH)2 = CaBr2 + Ca(BrO3)2 + H2O =>
6 Br2 + 6 Ca(OH)2 = 5 CaBr2 + Ca(BrO3)2 + 6 H2O

C4H8 + Br2 = C4H8Br2 =>
C4H8 + Br2 = C4H8Br2

Al(OH)3 + H2CO3 = Al2(CO3)3 + H2O =>
2 Al(OH)3 + 3 H2CO3 = Al2(CO3)3 + 6 H2O

CH3COOK + H2SO4 = CH3COOH + K2SO4 =>
2 CH3COOK + H2SO4 = 2 CH3COOH + K2SO4

HCl + C2H2 = C2H4Cl2 =>
2 HCl + C2H2 = C2H4Cl2

HClO4 + P4O10 = H3PO4 + Cl2O7 =>
12 HClO4 + P4O10 = 4 H3PO4 + 6 Cl2O7

Zn(NO3)2 + LiCl = ZnCl2 + Li(NO3) =>
Zn(NO3)2 + 2 LiCl = ZnCl2 + 2 Li(NO3)

FeBr3(aq) + NaOH(aq) = FeOH(s) + NaBr3(aq) =>
FeBr3(aq) + NaOH(aq) = FeOH(s) + NaBr3(aq)

[NH4]2Fe[SO4]2 + NaOH = [NH4]2Fe(OH)2 + NaSO4 =>
[NH4]2Fe[SO4]2 + 2 NaOH = [NH4]2Fe(OH)2 + 2 NaSO4

Na2 + O2 = Na2O =>
2 Na2 + O2 = 2 Na2O

C4H6O3 + H2O = C2H4O2 =>
C4H6O3 + H2O = 2 C2H4O2

NH3 + O2 = NO2 + H2O =>
4 NH3 + 7 O2 = 4 NO2 + 6 H2O

P4O10 + H2O = H3PO4 =>
P4O10 + 6 H2O = 4 H3PO4

H + F = HF =>
H + F = HF

[Cu(NH3)4](OH)2 + Na2S + H2O = CuS + NaOH + NH4OH =>
[Cu(NH3)4](OH)2 + Na2S + 4 H2O = CuS + 2 NaOH + 4 NH4OH

CuO + C = Cu + CO2 =>
2 CuO + C = 2 Cu + CO2

P4O10 + H2O = H3PO4 =>
P4O10 + 6 H2O = 4 H3PO4

CAC2 + H2O = C2H2 + CA(OH)2 =>
CAC2 + 2 H2O = C2H2 + CA(OH)2

Ni + AgNo3 = NiNo3 + Ag =>
Ni + AgNo3 = NiNo3 + Ag

CH2C(CH3)CHCH3 + KMNO4 + H2O = CH2OHCHOHCH3 + MNO2 + KOH =>
9 CH2C(CH3)CHCH3 + 7 KMNO4 + 23 H2O = 15 CH2OHCHOHCH3 + 7 MNO2 + 7 KOH

Cu + AgNO3 = Cu(NO3)2 + Ag =>
Cu + 2 AgNO3 = Cu(NO3)2 + 2 Ag

Na + H2O = NaOH + H2 =>
2 Na + 2 H2O = 2 NaOH + H2

C3H7OH + O2 = CO2 + H2O =>
2 C3H7OH + 9 O2 = 6 CO2 + 8 H2O

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16
Gleichen Sie die Gleichung jeder chemischen Reaktion aus
 Am Vortag ausgeglichene Gleichungen Am nächsten Tag ausgeglichene Gleichungen
Gleichungen ausgeglichen auf10/08/19
Gleichungen ausgeglichen auf09/15/19
Gleichungen ausgeglichen auf10/15/18
Geben Sie uns Rückmeldungen zu Ihren Erfahrungen mit dem Programm zum Berechnen chemischer Reaktionsgleichungen.
Menü Ausgleichen Molare Masse Gasgesetze Einheiten Chemie Werkzeuge Periodensystem der Elemente Chemisches Forum Symmetrie Konstanten Autor Kontaktieren Sie uns
Wie zitieren?