Printed from https://www.webqc.org

Chemische Gleichungen im Gleichgewicht auf03/04/19

 Am Vortag ausgeglichene Gleichungen Am nächsten Tag ausgeglichene Gleichungen
Gleichen Sie die Gleichung jeder chemischen Reaktion aus
NH3 + O3 = NO + H2O =>
6 NH3 + 5 O3 = 6 NO + 9 H2O

Cu + HNO3 + H2SO4 + H2O = CuSO4*5H2O + NO =>
3 Cu + 2 HNO3 + 3 H2SO4 + 11 H2O = 3 CuSO4*5H2O + 2 NO

FeCl3 + NaOH = Fe(OH)3 + NaCl =>
FeCl3 + 3 NaOH = Fe(OH)3 + 3 NaCl

CuS + HNO3 = Cu(NO3)2 + NO2 + S8 + H2O =>
8 CuS + 32 HNO3 = 8 Cu(NO3)2 + 16 NO2 + S8 + 16 H2O

NH3 + HNO3 = NH4NO3 =>
NH3 + HNO3 = NH4NO3

NaCl + Pb(NO3)2 = PbCl2 + Na(NO3) =>
2 NaCl + Pb(NO3)2 = PbCl2 + 2 Na(NO3)

CA(HCO3)2 = CACO3 + CO2 + H2O =>
CA(HCO3)2 = CACO3 + CO2 + H2O

RB + H2O = RBOH + H2 =>
2 RB + 2 H2O = 2 RBOH + H2

CA(HCO3)2 = CACO3 + CO2 + H2O =>
CA(HCO3)2 = CACO3 + CO2 + H2O

Na + H2O = NaOH + H2 =>
2 Na + 2 H2O = 2 NaOH + H2

NaCl + Pb(NO3)2 = PbCl2 + Na(NO3) =>
2 NaCl + Pb(NO3)2 = PbCl2 + 2 Na(NO3)

NO2 + H2O = HNO3 + NO =>
3 NO2 + H2O = 2 HNO3 + NO

Mn2N + ReO3 + Fe2O3 + KClO4 = Mn2FeReO5N + KCl =>
8 Mn2N + 8 ReO3 + 4 Fe2O3 + KClO4 = 8 Mn2FeReO5N + KCl

CO2 + H2O = C16H12O6 + O2 =>
16 CO2 + 6 H2O = C16H12O6 + 16 O2

Mg + O2 = MgO =>
2 Mg + O2 = 2 MgO

CO2 + H2O = C16H12O6 + O2 =>
16 CO2 + 6 H2O = C16H12O6 + 16 O2

HCOOH + NAOH = HCOONA + H2O =>
HCOOH + NAOH = HCOONA + H2O

CS2 + Cl3 = CCl4 + S2Cl2 =>
CS2 + 2 Cl3 = CCl4 + S2Cl2

As2O3 + C = As + CO =>
As2O3 + 3 C = 2 As + 3 CO

HfNO3 + NH3 + H2O = Hf(OH)4 + NH4(NO)3 =>
14 HfNO3 + 6 NH3 + 29 H2O = 14 Hf(OH)4 + 5 NH4(NO)3

P2O5 + H2O = H3PO4 =>
P2O5 + 3 H2O = 2 H3PO4

Ca + O2 = CaO2 =>
Ca + O2 = CaO2

Cu + AGNO3 = Cu(NO3)2 + AG =>
Cu + 2 AGNO3 = Cu(NO3)2 + 2 AG

BaCO3(s) + HCl(aq) = BaCl2(aq) + H2O(l) + CO2(g) =>
BaCO3(s) + 2 HCl(aq) = BaCl2(aq) + H2O(l) + CO2(g)

Cu + AgNO3 = Cu(NO3)2 + Ag =>
Cu + 2 AgNO3 = Cu(NO3)2 + 2 Ag

Cu + O2 = CuO =>
2 Cu + O2 = 2 CuO

Na3PO4 + HCl = NaCl + H3PO4 =>
Na3PO4 + 3 HCl = 3 NaCl + H3PO4

Cs + H2O = CsOH + H2 =>
2 Cs + 2 H2O = 2 CsOH + H2

H2S + SO2 = S8 + H2O =>
16 H2S + 8 SO2 = 3 S8 + 16 H2O

Li2CO3 + MgCO3 + SiO2 = Li2MgSiO4 + CO2 =>
Li2CO3 + MgCO3 + SiO2 = Li2MgSiO4 + 2 CO2

CU(OH)2 = CUO + H2O =>
CU(OH)2 = CUO + H2O

NH3 + O2 = HNO3 + H2O =>
NH3 + 2 O2 = HNO3 + H2O

H2SO4 + KNO3 = HNO3 + K2SO4 =>
H2SO4 + 2 KNO3 = 2 HNO3 + K2SO4

NCl3 + H2O = NH3 + HOCl =>
NCl3 + 3 H2O = NH3 + 3 HOCl

Mg + H2O = Mg(OH)2 + H2 =>
Mg + 2 H2O = Mg(OH)2 + H2

AL + HCl = ALCl3 + H2 =>
2 AL + 6 HCl = 2 ALCl3 + 3 H2

K2Cr2O7 + HCl = KCl + CrCl3 + H2O + Cl2 =>
K2Cr2O7 + 14 HCl = 2 KCl + 2 CrCl3 + 7 H2O + 3 Cl2

C2H5COOH + NAOH = NAC2H5COO + H2O =>
C2H5COOH + NAOH = NAC2H5COO + H2O

HNO3 + Na2CO3 = H2CO3 + NaNO3 =>
2 HNO3 + Na2CO3 = H2CO3 + 2 NaNO3

NH3 + O2 = HNO3 + H2O =>
NH3 + 2 O2 = HNO3 + H2O

HgCl2 + Fe = Hg + FeCl3 =>
3 HgCl2 + 2 Fe = 3 Hg + 2 FeCl3

NH3 + O2 = NO + H2O =>
4 NH3 + 5 O2 = 4 NO + 6 H2O

Fe(OH)3 = Fe2O3 + H2O =>
2 Fe(OH)3 = Fe2O3 + 3 H2O

C3H7OH + O2 = CO2 + H2O =>
2 C3H7OH + 9 O2 = 6 CO2 + 8 H2O

Fe2O3 + H2SO4 = Fe2(SO4)3 + H2O =>
Fe2O3 + 3 H2SO4 = Fe2(SO4)3 + 3 H2O

Ammonia + Oxygen = nitrogenmonoxide + water =>
4 NH3 + 5 O2 = 4 NO + 6 H2O

Co(NO3)2*6H2O + NH3 + NaNO3 = [(NH3)5Co(O2)Co(NH3)5](NO3)5*2H2O + NaOH + H2O =>
16 Co(NO3)2*6H2O + 75 NH3 + 13 NaNO3 = 8[(NH3)5Co(O2)Co(NH3)5](NO3)5*2H2O + 13 NaOH + 66 H2O

Ag + H2S + O2 = Ag2S + H2O =>
4 Ag + 2 H2S + O2 = 2 Ag2S + 2 H2O

C3H8 + O2 = CO2 + H2O =>
C3H8 + 5 O2 = 3 CO2 + 4 H2O

Ca(OH)2 + H3PO4 = Ca3(PO4)2 + H2O =>
3 Ca(OH)2 + 2 H3PO4 = Ca3(PO4)2 + 6 H2O

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22
Gleichen Sie die Gleichung jeder chemischen Reaktion aus
 Am Vortag ausgeglichene Gleichungen Am nächsten Tag ausgeglichene Gleichungen
Gleichungen ausgeglichen auf02/25/19
Gleichungen ausgeglichen auf02/02/19
Gleichungen ausgeglichen auf03/04/18
Geben Sie uns Rückmeldungen zu Ihren Erfahrungen mit dem Programm zum Berechnen chemischer Reaktionsgleichungen.
Menü Ausgleichen Molare Masse Gasgesetze Einheiten Chemie Werkzeuge Periodensystem der Elemente Chemisches Forum Symmetrie Konstanten Autor Kontaktieren Sie uns
Wie zitieren?