Am Vortag ausgeglichene Gleichungen | Am nächsten Tag ausgeglichene Gleichungen |
CuS + 10 HNO3 = Cu(NO3)2 + H2SO4 + 4 H2O + 8 NO2
CoCl2 + NH4OH = [Co(NH3)6]Cl2 + H2O =>
CoCl2 + 6 NH4OH = [Co(NH3)6]Cl2 + 6 H2O
K2Cr2O7 + H2SO4 + C2H5OH = Cr2(SO4)3 + K2SO4 + CH3COOH + H2O =>
2 K2Cr2O7 + 8 H2SO4 + 3 C2H5OH = 2 Cr2(SO4)3 + 2 K2SO4 + 3 CH3COOH + 11 H2O
Fe(NO3)2 + (NH4)3PO4 = Fe3(PO4)2 + NH4NO3 =>
3 Fe(NO3)2 + 2(NH4)3PO4 = Fe3(PO4)2 + 6 NH4NO3
Pb3O4 = PbO + O2 =>
2 Pb3O4 = 6 PbO + O2
NH3 + O2 + CH4 = HCN + H2O =>
2 NH3 + 3 O2 + 2 CH4 = 2 HCN + 6 H2O
Cu + NaNO3 + H2SO4 = Na2SO4 + NO2 + H2O + Cu(NO3)2 =>
Cu + 4 NaNO3 + 2 H2SO4 = 2 Na2SO4 + 2 NO2 + 2 H2O + Cu(NO3)2
P4O10 + H2O = H3PO4 =>
P4O10 + 6 H2O = 4 H3PO4
Fe + H2SO4 = FeSO4 + H2 =>
Fe + H2SO4 = FeSO4 + H2
MnCl2 + NH3 + (NH4)2HPO4 = Mn3(PO4)2 + NH4Cl =>
3 MnCl2 + 2 NH3 + 2(NH4)2HPO4 = Mn3(PO4)2 + 6 NH4Cl
Pb(NO3)2 = PbO + NO2 + O2 =>
2 Pb(NO3)2 = 2 PbO + 4 NO2 + O2
C3H8 + O2 = CO2 + H2O =>
C3H8 + 5 O2 = 3 CO2 + 4 H2O
Mg(CH3COO)2*4H2O = MgO + C2H6 + H2O + CO2 =>
7 Mg(CH3COO)2*4H2O = 7 MgO + 8 C2H6 + 25 H2O + 12 CO2
NH4OH + H2SO4 = (NH4)2SO4 + H2O =>
2 NH4OH + H2SO4 = (NH4)2SO4 + 2 H2O
K + H2SO4 = K2SO4 + SO2 + H2O =>
2 K + 2 H2SO4 = K2SO4 + SO2 + 2 H2O
O2 + SnCl2 + NaOH = Na2SnO3 + NaCl + H2O =>
O2 + 2 SnCl2 + 8 NaOH = 2 Na2SnO3 + 4 NaCl + 4 H2O
FePO4 + HCl = FeCl3 + H3PO4 =>
FePO4 + 3 HCl = FeCl3 + H3PO4
H2(g) + O2(g) = H2O =>
2 H2(g) + O2(g) = 2 H2O
K2Cr2O7 + H2SO4 = K2SO4 + Cr2(SO4)3 + H20 + O2 =>
10 K2Cr2O7 + 40 H2SO4 = 10 K2SO4 + 10 Cr2(SO4)3 + 4 H20 + 35 O2
[Ca(NH3)4](HO)2 + H2SO4 = CaSO4 + (NH4)2SO4 + H2O =>
[Ca(NH3)4](HO)2 + 3 H2SO4 = CaSO4 + 2(NH4)2SO4 + 2 H2O
CAC2 + H20 + CO2 = CA(OH)2 + CH2CHCO2H =>
10 CAC2 + 4 H20 + 25 CO2 = 10 CA(OH)2 + 15 CH2CHCO2H
PCl5 + H2O = HCl + H3PO4 =>
PCl5 + 4 H2O = 5 HCl + H3PO4
NaOH + FeBr3 = Fe(OH)3 + NaBr =>
3 NaOH + FeBr3 = Fe(OH)3 + 3 NaBr
H2 + O2 = H2O =>
2 H2 + O2 = 2 H2O
K2Cr2O7 + CH3CH2OH + H2SO4 = Cr2(SO4)3 + K2SO4 + CH3COOH + H2 =>
K2Cr2O7 + 7 CH3CH2OH + 4 H2SO4 = Cr2(SO4)3 + K2SO4 + 7 CH3COOH + 11 H2
H2SO4 + MgCO3 = H2CO3 + MgSO4 =>
H2SO4 + MgCO3 = H2CO3 + MgSO4
Ca3(PO4)2 + H2SO4 = CaSO4 + H3PO4 =>
Ca3(PO4)2 + 3 H2SO4 = 3 CaSO4 + 2 H3PO4
CrCl2 + HCl + O2 = CrCl3 + H2O =>
4 CrCl2 + 4 HCl + O2 = 4 CrCl3 + 2 H2O
NaOH + Cu(ClO3)2 = Cu(OH)2 + NaClO3 =>
2 NaOH + Cu(ClO3)2 = Cu(OH)2 + 2 NaClO3
H2SO4 + Fe(OH)3 = Fe2(SO4)3 + H2O =>
3 H2SO4 + 2 Fe(OH)3 = Fe2(SO4)3 + 6 H2O
Na + Cl2 = NaCl(s) =>
2 Na + Cl2 = 2 NaCl(s)
Bi2O3 + Fe2O3 = BiFeO3 =>
Bi2O3 + Fe2O3 = 2 BiFeO3
HNO3 + Ca = N2O + Ca(NO3)2 + H2O =>
10 HNO3 + 4 Ca = N2O + 4 Ca(NO3)2 + 5 H2O
[Ca(NH3)4](HO)2 + H2SO4 = CaSO4 + (NH4)2SO4 + H2O =>
[Ca(NH3)4](HO)2 + 3 H2SO4 = CaSO4 + 2(NH4)2SO4 + 2 H2O
Al(OH)3 + H2SO4 = Al2(SO4)3 + H2O =>
2 Al(OH)3 + 3 H2SO4 = Al2(SO4)3 + 6 H2O
Pb + AgNO3 = Ag + Pb(NO3)2 =>
Pb + 2 AgNO3 = 2 Ag + Pb(NO3)2
FeC2O4*2H2O + H2O2 + K2C2O4*H2O + H2C2O4*H2O = K3[Fe(C2O4)3]*3H2O + H2O =>
2 FeC2O4*2H2O + H2O2 + 3 K2C2O4*H2O + H2C2O4*H2O = 2 K3[Fe(C2O4)3]*3H2O + 4 H2O
K2Cr2O7 + HCl = Cl2 + CrCl3 + KCl + H2O =>
K2Cr2O7 + 14 HCl = 3 Cl2 + 2 CrCl3 + 2 KCl + 7 H2O
HNO3 + NaOH = NaNO3 + H2O =>
HNO3 + NaOH = NaNO3 + H2O
CaCO3(s) + HCl(aq) = CaCl2(aq) + CO2(g) + H2O(l) =>
CaCO3(s) + 2 HCl(aq) = CaCl2(aq) + CO2(g) + H2O(l)
KMnO4 + H2S = MnO2 + S + KOH + H2O =>
2 KMnO4 + 3 H2S = 2 MnO2 + 3 S + 2 KOH + 2 H2O
H2SO4 + Al = Al2(SO4)3 + H2 =>
3 H2SO4 + 2 Al = Al2(SO4)3 + 3 H2
Cr + Cl2 = CrCl3(s) =>
2 Cr + 3 Cl2 = 2 CrCl3(s)
Os + KNO3 + KOH = K2OsO4 + KNO2 + H2O =>
Os + 3 KNO3 + 2 KOH = K2OsO4 + 3 KNO2 + H2O
SiCl4 + H2O = H4SiO4 + HCl =>
SiCl4 + 4 H2O = H4SiO4 + 4 HCl
HIO3 + HI = I2 + H2O =>
HIO3 + 5 HI = 3 I2 + 3 H2O
Na + H2SO4 = Na2SO4 + H2S + H2O =>
8 Na + 5 H2SO4 = 4 Na2SO4 + H2S + 4 H2O
K2Cr2O7 + HCl = KCl + CrCl3 + Cl2 + H2O =>
K2Cr2O7 + 14 HCl = 2 KCl + 2 CrCl3 + 3 Cl2 + 7 H2O
Cr + Cl2 = CrCl3(s) =>
2 Cr + 3 Cl2 = 2 CrCl3(s)
C24H38O4 + H2SO4 = C10H8O4 + C8H18O + S =>
127 C24H38O4 + 59 H2SO4 = 132 C10H8O4 + 216 C8H18O + 59 S
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Am Vortag ausgeglichene Gleichungen | Am nächsten Tag ausgeglichene Gleichungen |
Gleichungen ausgeglichen auf11/03/14
Gleichungen ausgeglichen auf12/03/13
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