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Chemical Equations Balanced on 05/04/13

 Equations balanced on the previous day Equations balanced on the next day
Balance equation of any chemical reaction online for free
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C2H2 + O2 = CO2 + H2O =>
2 C2H2 + 5 O2 = 4 CO2 + 2 H2O

K2Cr2O7 + H2SO4 = K2SO4 + Cr2(SO4)3 + H2O + O =>
K2Cr2O7 + 4 H2SO4 = K2SO4 + Cr2(SO4)3 + 4 H2O + 3 O

K2Cr2O7 + KI + H2SO4 = I2 + H2O + Cr2(SO4)3 + K2SO4 =>
K2Cr2O7 + 6 KI + 7 H2SO4 = 3 I2 + 7 H2O + Cr2(SO4)3 + 4 K2SO4

Na3PO4 + AgNO3 = NaNO3 + Ag3PO4 =>
Na3PO4 + 3 AgNO3 = 3 NaNO3 + Ag3PO4

K4[Fe(CN)6] + FeCl3 = K[FeFe(CN)6] + K{+} + Cl{-} =>
K4[Fe(CN)6] + FeCl3 = K[FeFe(CN)6] + 3 K{+} + 3 Cl{-}

K4[Fe(CN)6] + FeCl3 = K[FeFe(CN)6] + KCl =>
K4[Fe(CN)6] + FeCl3 = K[FeFe(CN)6] + 3 KCl

NH3 + O2 = NO + H2O =>
4 NH3 + 5 O2 = 4 NO + 6 H2O

Li(s) + O2(g) = Li2O(s) =>
4 Li(s) + O2(g) = 2 Li2O(s)

N2 + H2 = NH3 =>
N2 + 3 H2 = 2 NH3

HCl + Zn = ZnCl2 + H2 =>
2 HCl + Zn = ZnCl2 + H2

Cu(s) + O2(g) = CuO(s) =>
2 Cu(s) + O2(g) = 2 CuO(s)

CaCl2 + KOH = Ca(OH)2 + KCl =>
CaCl2 + 2 KOH = Ca(OH)2 + 2 KCl

KMnO4 + HCl = KCl + MnCl2 + H2O + Cl2 =>
2 KMnO4 + 16 HCl = 2 KCl + 2 MnCl2 + 8 H2O + 5 Cl2

KMnO4 + HCl = KCl + MnCl2 + H2O + Cl2 =>
2 KMnO4 + 16 HCl = 2 KCl + 2 MnCl2 + 8 H2O + 5 Cl2

Fe2O3 + CO = Fe + CO2 =>
Fe2O3 + 3 CO = 2 Fe + 3 CO2

NiSO4 + NaOH = Ni(OH)2 + Na2SO4 =>
NiSO4 + 2 NaOH = Ni(OH)2 + Na2SO4

Na2SO3 + H3PO4 = NaH2PO4 + H2O + SO2 =>
Na2SO3 + 2 H3PO4 = 2 NaH2PO4 + H2O + SO2

H2SO4 + LiOH = Li2SO4 + H2O =>
H2SO4 + 2 LiOH = Li2SO4 + 2 H2O

C2H2 + Na = C2HNa + H2 =>
2 C2H2 + 2 Na = 2 C2HNa + H2

P2O5 + H2SO4 = HPO3 + SO3 =>
P2O5 + H2SO4 = 2 HPO3 + SO3

PbBr + Cu(NO3)2 = Pb(NO3) + CuBr2 =>
2 PbBr + Cu(NO3)2 = 2 Pb(NO3) + CuBr2

(NH2)2CO + HNO2 = N2 + CO2 + H2O =>
(NH2)2CO + 2 HNO2 = 2 N2 + CO2 + 3 H2O

P2O5 + H2SO4 = H3PO4 + SO3 =>
P2O5 + 3 H2SO4 = 2 H3PO4 + 3 SO3

Cl2 + NH4I = NH4Cl + I =>
Cl2 + 2 NH4I = 2 NH4Cl + 2 I

CO2 + H2O + BaCl2 = BaCO3 + HCl =>
CO2 + H2O + BaCl2 = BaCO3 + 2 HCl

Mg(OH)2 = Mg + OH =>
Mg(OH)2 = Mg + 2 OH

KMnO4 + Na2C2O4 + H2SO4 = K2SO4 + MnSO4 + Na2SO4 + H2O + CO2 =>
2 KMnO4 + 5 Na2C2O4 + 8 H2SO4 = K2SO4 + 2 MnSO4 + 5 Na2SO4 + 8 H2O + 10 CO2

Br2 + H2SO3 + H2O = H2SO4 + HBr =>
Br2 + H2SO3 + H2O = H2SO4 + 2 HBr

Pb(NO3)2 = PbO + NO2 + O2 =>
2 Pb(NO3)2 = 2 PbO + 4 NO2 + O2

HNO3 + NaClO3 = NaNO3 + HClO3 =>
HNO3 + NaClO3 = NaNO3 + HClO3

C2H2 + KMnO4 + H2SO4 = C2H2O4 + K2SO4 + MnSO4 + H20 =>
20 C2H2 + 20 KMnO4 + 30 H2SO4 = 20 C2H2O4 + 10 K2SO4 + 20 MnSO4 + 3 H20

C2H2 + KMnO4 + H2SO4 = C2H2O4 + K2SO4 + MnSO4 + H2O =>
5 C2H2 + 8 KMnO4 + 12 H2SO4 = 5 C2H2O4 + 4 K2SO4 + 8 MnSO4 + 12 H2O

C2H6 + O2 = CO2 + H2O =>
2 C2H6 + 7 O2 = 4 CO2 + 6 H2O

C2H6 + O2 = CO2 + H2O =>
2 C2H6 + 7 O2 = 4 CO2 + 6 H2O

Ca(OH)2 + HBr = CaBr2 + H2O =>
Ca(OH)2 + 2 HBr = CaBr2 + 2 H2O

S + H2SO4 = SO2 + H2O =>
S + 2 H2SO4 = 3 SO2 + 2 H2O

PbBr2 + Cu(NO3)2 = Pb(NO3)2 + CuBr2 =>
PbBr2 + Cu(NO3)2 = Pb(NO3)2 + CuBr2

C3H8 + O2 = CO2 + H2O =>
C3H8 + 5 O2 = 3 CO2 + 4 H2O

KMnO4 + H2SO3 = K2SO4 + MnSO4 + H2SO4 + H2O =>
2 KMnO4 + 5 H2SO3 = K2SO4 + 2 MnSO4 + 2 H2SO4 + 3 H2O

CrCl3 + KOH + KClO = KCl + K2CrO4 + H2O =>
2 CrCl3 + 10 KOH + 3 KClO = 9 KCl + 2 K2CrO4 + 5 H2O

KMnO4 + SO2 + H2O = MnSO4 + KHSO4 + H2SO4 =>
2 KMnO4 + 5 SO2 + 2 H2O = 2 MnSO4 + 2 KHSO4 + H2SO4

Fe2CO3 + CO = Fe + CO2 =>
Fe2CO3 + CO = 2 Fe + 2 CO2

BeF2 + KOH = Be(OH)2 + KF =>
BeF2 + 2 KOH = Be(OH)2 + 2 KF

KMnO4 + HCl + Hg = HgCl2 + MnO2 + KCl + H2O =>
2 KMnO4 + 8 HCl + 3 Hg = 3 HgCl2 + 2 MnO2 + 2 KCl + 4 H2O

MnO2 + HBr = MnBr2 + Br2 + H2O =>
MnO2 + 4 HBr = MnBr2 + Br2 + 2 H2O

C2H4 + O2 = CO2 + H2O =>
C2H4 + 3 O2 = 2 CO2 + 2 H2O

P + AgNO3 = Ag + P2O5 + N2O5 =>
2 P + 10 AgNO3 = 10 Ag + P2O5 + 5 N2O5

HAt + Fe2O3 = FeAt3 + H2O =>
6 HAt + Fe2O3 = 2 FeAt3 + 3 H2O

KMnO4 + HCl + Hg = HgCl2 + MnO2 + KCl + H2O =>
2 KMnO4 + 8 HCl + 3 Hg = 3 HgCl2 + 2 MnO2 + 2 KCl + 4 H2O

MnO2 + HCl = MnCl2 + H2O + Cl2 =>
MnO2 + 4 HCl = MnCl2 + 2 H2O + Cl2

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Balance equation of any chemical reaction online for free
 Equations balanced on the previous day Equations balanced on the next day
Equations balanced on 04/27/13
Equations balanced on 04/04/13
Equations balanced on 05/04/12
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