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Chemical Equations Balanced on 08/12/11

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Balance equation of any chemical reaction online for free
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H2O + SO2 = HSO4{-} + e + H{+} =>
2 H2O + SO2 = HSO4{-} + 2e + 3 H{+}

H2O + SO2 = HSO4{-} + e + H{+} =>
2 H2O + SO2 = HSO4{-} + 2e + 3 H{+}

H2O + SO2 = HSO4{-} + e + H{+} =>
2 H2O + SO2 = HSO4{-} + 2e + 3 H{+}

MnO4{-} + Fe{2+} + H3O{+} = Mn{2+} + Fe{3+} + H2O =>
MnO4{-} + 5 Fe{2+} + 8 H3O{+} = Mn{2+} + 5 Fe{3+} + 12 H2O

Ba(NO3)2 + V(NO3)3 + C6H8O7 = Ba3O8V2 + NO2 + H20 + CO2 =>
75 Ba(NO3)2 + 50 V(NO3)3 + 20 C6H8O7 = 25 Ba3O8V2 + 300 NO2 + 8 H20 + 120 CO2

Ba(NO3)2 + V(NO3)3 + C6H8O7 = Ba3O8V2 + N + H2O + CO2 =>
27 Ba(NO3)2 + 18 V(NO3)3 + 28 C6H8O7 = 9 Ba3O8V2 + 108 N + 112 H2O + 168 CO2

Fe2O3 + CO = Fe + CO2 =>
Fe2O3 + 3 CO = 2 Fe + 3 CO2

Ba(NO3)2 + V(NO3)3 + C6H8O7 = Ba3O8V2 + N2 + H2O + CO2 =>
27 Ba(NO3)2 + 18 V(NO3)3 + 28 C6H8O7 = 9 Ba3O8V2 + 54 N2 + 112 H2O + 168 CO2

Ba(NO3)2 + V(NO3)3 + C6H8O7 = Ba3O8V2 + N2 + H + CO2 =>
15 Ba(NO3)2 + 10 V(NO3)3 + 28 C6H8O7 = 5 Ba3O8V2 + 30 N2 + 224 H + 168 CO2

Ba(NO3)2 + V(NO3)3 + C6H8O7 = Ba3O8V2 + N2 + H + CO2 =>
15 Ba(NO3)2 + 10 V(NO3)3 + 28 C6H8O7 = 5 Ba3O8V2 + 30 N2 + 224 H + 168 CO2

Ba(NO3)2 + V(NO3)3 + C6H8O7 = Ba3O8V2 + N2 + H2O + CO2 =>
27 Ba(NO3)2 + 18 V(NO3)3 + 28 C6H8O7 = 9 Ba3O8V2 + 54 N2 + 112 H2O + 168 CO2

Li2O + Sb2O3 = LiSbO2 =>
Li2O + Sb2O3 = 2 LiSbO2

C3H8 + O2 = CO2 + H2O =>
C3H8 + 5 O2 = 3 CO2 + 4 H2O

P + HNO3 + H2O = H3PO4 + NO =>
3 P + 5 HNO3 + 2 H2O = 3 H3PO4 + 5 NO

K + H2O = KOH + H2 =>
2 K + 2 H2O = 2 KOH + H2

Al + O = AlO =>
Al + O = AlO

Ba(NO3)2 + V2N + C6H8O7 = Ba3O8V2 + N2 + H2O + CO2 =>
54 Ba(NO3)2 + 18 V2N + 20 C6H8O7 = 18 Ba3O8V2 + 63 N2 + 80 H2O + 120 CO2

(NH4)2CO3 + (CuSO4) = (NH4)2(SO4) + CuCO3 =>
(NH4)2CO3 + (CuSO4) = (NH4)2(SO4) + CuCO3

Fe + Cl2 = FeCl3 =>
2 Fe + 3 Cl2 = 2 FeCl3

Ba(NO3)2 + V2N + C6H8O7 = Ba3O8V2 + N2 + H2O + CO2 =>
54 Ba(NO3)2 + 18 V2N + 20 C6H8O7 = 18 Ba3O8V2 + 63 N2 + 80 H2O + 120 CO2

Ba(NO3)2 + VN + C6H8O7 = Ba3O8V2 + N2 + H2O + CO2 =>
27 Ba(NO3)2 + 18 VN + 10 C6H8O7 = 9 Ba3O8V2 + 36 N2 + 40 H2O + 60 CO2

H3BO3 + KOH = H2O + KH2BO3 =>
H3BO3 + KOH = H2O + KH2BO3

C2H6 + O2 = CO2 + H2O =>
2 C2H6 + 7 O2 = 4 CO2 + 6 H2O

Ba(NO3)2 + V2N + C6H8O7 = Ba3O8V2 + N2 + H2O + CO2 =>
54 Ba(NO3)2 + 18 V2N + 20 C6H8O7 = 18 Ba3O8V2 + 63 N2 + 80 H2O + 120 CO2

BaCl2 + CuSO4 = BaSO4 + CuCl2 =>
BaCl2 + CuSO4 = BaSO4 + CuCl2

Ba(NO3)2 + VN + C6H8O7 = Ba3O8V2 + N2 + H2O + CO2 =>
27 Ba(NO3)2 + 18 VN + 10 C6H8O7 = 9 Ba3O8V2 + 36 N2 + 40 H2O + 60 CO2

Ba(NO3)2 + V2N + C6H8O7 = Ba3O8V2 + N2 + H2O + CO2 =>
54 Ba(NO3)2 + 18 V2N + 20 C6H8O7 = 18 Ba3O8V2 + 63 N2 + 80 H2O + 120 CO2

NaOH + HCl = H2O + NaCl =>
NaOH + HCl = H2O + NaCl

BaCl2 + Pb(NO3)2 = Ba(NO3)2 + PbCl2 =>
BaCl2 + Pb(NO3)2 = Ba(NO3)2 + PbCl2

BaCl2 + KI = BaI2 + KCl =>
BaCl2 + 2 KI = BaI2 + 2 KCl

CaO + H2O = Ca(OH)2 =>
CaO + H2O = Ca(OH)2

CaO + H2O = Ca(OH)2 =>
CaO + H2O = Ca(OH)2

CaO + H2O = Ca(OH)2 =>
CaO + H2O = Ca(OH)2

NaOH + HCL = NaCL + H2O =>
NaOH + HCL = NaCL + H2O

NaOH + HCl = NaCl + H2O =>
NaOH + HCl = NaCl + H2O

CuSO4 + Pb(NO3)2 = Cu(NO3)2 + Pb(SO4) =>
CuSO4 + Pb(NO3)2 = Cu(NO3)2 + Pb(SO4)

V2N + Fe(NO3)3*9H2O + C6H8O7 = Fe3O8V2 + N2 + H2O + CO2 =>
9 V2N + 27 Fe(NO3)3*9H2O + 19 C6H8O7 = 9 Fe3O8V2 + 45 N2 + 319 H2O + 114 CO2

CaO + H2O = CaOH + O =>
2 CaO + H2O = 2 CaOH + O

V2N + Fe(NO3)3*9H2O + C6H8O7 = Fe3O8V2 + N2 + H2O + CO2 =>
9 V2N + 27 Fe(NO3)3*9H2O + 19 C6H8O7 = 9 Fe3O8V2 + 45 N2 + 319 H2O + 114 CO2

Zn + Pb(NO3)2 = Zn(NO3)2 + Pb =>
Zn + Pb(NO3)2 = Zn(NO3)2 + Pb

C2H4O2 + LiOH = H2O + LiC2H3O2 =>
C2H4O2 + LiOH = H2O + LiC2H3O2

CuSO4 + KI = CuI2 + K2SO4 =>
CuSO4 + 2 KI = CuI2 + K2SO4

AlBr3 + Cl2 = Al2Cl3 + Br2 =>
4 AlBr3 + 3 Cl2 = 2 Al2Cl3 + 6 Br2

HC3H5O3 + NaOH = NaC3H5O3 + H2O =>
HC3H5O3 + NaOH = NaC3H5O3 + H2O

N + H = NH3 =>
N + 3 H = NH3

Mg + O2 = MgO =>
2 Mg + O2 = 2 MgO

Na3H + Cl2O2 + S = S2O + H2 + NaCl =>
2 Na3H + 3 Cl2O2 + 12 S = 6 S2O + H2 + 6 NaCl

Fe2O3 + C = Fe + CO2 =>
2 Fe2O3 + 3 C = 4 Fe + 3 CO2

NaCl + H2O = NaClO + H2 =>
NaCl + H2O = NaClO + H2

CuSO4 + NaOH = Cu(OH)2 + Na2(SO4) =>
CuSO4 + 2 NaOH = Cu(OH)2 + Na2(SO4)

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Balance equation of any chemical reaction online for free
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Equations balanced on 08/05/11
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