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Chemical Equations Balanced on 07/19/09

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Balance equation of any chemical reaction online for free
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NH3 + O2 = NO + H2O =>
4 NH3 + 5 O2 = 4 NO + 6 H2O

C4H10O + O2 = CO2 + H2O =>
C4H10O + 6 O2 = 4 CO2 + 5 H2O

NaClO3 = NaCl + O2 =>
2 NaClO3 = 2 NaCl + 3 O2

NaClO3 = NaCl + O2 =>
2 NaClO3 = 2 NaCl + 3 O2

HC2H3O2 + Ba(OH)2 = H2O + Ba(C2H3O2)2 =>
2 HC2H3O2 + Ba(OH)2 = 2 H2O + Ba(C2H3O2)2

C3H6 + O2 = CO2 + H2O =>
2 C3H6 + 9 O2 = 6 CO2 + 6 H2O

BaCl2 + Na2SO4 = BaSO4 + NaCl =>
BaCl2 + Na2SO4 = BaSO4 + 2 NaCl

Fe + AgC2H3O2 = Fe(CH3CO2)2 + Ag =>
Fe + 2 AgC2H3O2 = Fe(CH3CO2)2 + 2 Ag

Fe + Cl2 = FeCl3 =>
2 Fe + 3 Cl2 = 2 FeCl3

(NH4)2CO3 + Al(NO3)3 = NH4NO3 + Al2(CO3)3 =>
3(NH4)2CO3 + 2 Al(NO3)3 = 6 NH4NO3 + Al2(CO3)3

C2H5OH + Na(OCl) = CHCl3 + Na(O[CO]H) + NaCl + H2O =>
2 C2H5OH + 8 Na(OCl) = CHCl3 + 3 Na(O[CO]H) + 5 NaCl + 4 H2O

C2H5OH + Na(OCl) = CHCl3 + Na(O[CO]H) + NaCl + H2O =>
2 C2H5OH + 8 Na(OCl) = CHCl3 + 3 Na(O[CO]H) + 5 NaCl + 4 H2O

Zn + HCl = ZnCl2 + H2 =>
Zn + 2 HCl = ZnCl2 + H2

K4Fe(CN)6 + H2SO4 + H2O = K2SO4 + FeSO4 + (NH4)2SO4 + CO =>
K4Fe(CN)6 + 6 H2SO4 + 6 H2O = 2 K2SO4 + FeSO4 + 3(NH4)2SO4 + 6 CO

H2 + O2 = H2O =>
2 H2 + O2 = 2 H2O

CuSO4*5H2O = CuSO4 + H2O =>
CuSO4*5H2O = CuSO4 + 5 H2O

CH3OH + I2 + P4 = CH3I + H3PO4 + H2O =>
20 CH3OH + 10 I2 + P4 = 20 CH3I + 4 H3PO4 + 4 H2O

C6H5COOH + O2 = CO2 + H2O =>
2 C6H5COOH + 15 O2 = 14 CO2 + 6 H2O

CaCl2 + Na3PO4 = Ca3(PO4)2 + NaCl =>
3 CaCl2 + 2 Na3PO4 = Ca3(PO4)2 + 6 NaCl

(CH3)3Al + H2O = CH4 + Al(OH)3 =>
(CH3)3Al + 3 H2O = 3 CH4 + Al(OH)3

FeCl3 + KSCN = Fe(SCN)3 + KCl =>
FeCl3 + 3 KSCN = Fe(SCN)3 + 3 KCl

(NH4)3PO4 + Ba(OH)2 = NH4OH + Ba3(PO4)2 =>
2(NH4)3PO4 + 3 Ba(OH)2 = 6 NH4OH + Ba3(PO4)2

K2Cr2O7 + H2SO4 + CH3CH2OH = Cr2(SO4)3 + K2S02 + CH3COOH + H2O =>
K2Cr2O7 + 5 H2SO4 + 5 CH3CH2OH = Cr2(SO4)3 + K2S02 + 5 CH3COOH + 10 H2O

Cu + FeCl3 = FeCu + Cl3 =>
Cu + FeCl3 = FeCu + Cl3

Sb + Cl2 = SbCl3 =>
2 Sb + 3 Cl2 = 2 SbCl3

C8H18 + O2 = CO2 + H2O =>
2 C8H18 + 25 O2 = 16 CO2 + 18 H2O

CH3COCH3 + NaOCl = CHCl3 + NaCl + Na(CH3COO) + H2O =>
7 CH3COCH3 + 17 NaOCl = 3 CHCl3 + 8 NaCl + 9 Na(CH3COO) + 6 H2O

PbHAsO4 + HNO3 = H3AsO4 + Pb(NO3)2 =>
PbHAsO4 + 2 HNO3 = H3AsO4 + Pb(NO3)2

H2CO3 + CO3{2-} = HCO3{-} =>
H2CO3 + CO3{2-} = 2 HCO3{-}

Mg + O2 = MgO =>
2 Mg + O2 = 2 MgO

Na2S2O3 + KMnO4 + H2O = Na2SO4 + K2SO4 + MnO2 + KOH =>
3 Na2S2O3 + 8 KMnO4 + H2O = 3 Na2SO4 + 3 K2SO4 + 8 MnO2 + 2 KOH

Br + Cl = BrCl =>
Br + Cl = BrCl

Br2 + Cl2 = BrCl =>
Br2 + Cl2 = 2 BrCl

Mg + H2O = H2 + Mg(OH)2 =>
Mg + 2 H2O = H2 + Mg(OH)2

HNO3(aq) + Na2SO3(aq) = NaNO3(aq) + SO2(g) + H2O(l) =>
2 HNO3(aq) + Na2SO3(aq) = 2 NaNO3(aq) + SO2(g) + H2O(l)

C4H10 + O2 = CO2 + H2O =>
2 C4H10 + 13 O2 = 8 CO2 + 10 H2O

Fe + Cl2 = FeCl3 =>
2 Fe + 3 Cl2 = 2 FeCl3

NaClO2 + Cl2 = ClO2 + NaCl =>
2 NaClO2 + Cl2 = 2 ClO2 + 2 NaCl

C2O4{2-} + MnO4{-} + H{+} = Mn{2+} + CO2 + H2O =>
5 C2O4{2-} + 2 MnO4{-} + 16 H{+} = 2 Mn{2+} + 10 CO2 + 8 H2O

CH4 + O2 = CO2 + H2O =>
CH4 + 2 O2 = CO2 + 2 H2O

CoCO3 + NH3 = Co(NH3)6 + CO3 =>
CoCO3 + 6 NH3 = Co(NH3)6 + CO3

Na2C + O3 + HCl = CO2 + H2O + NaCl =>
Na2C + O3 + 2 HCl = CO2 + H2O + 2 NaCl

(NH4)2SO4(aq) + Ca(OH)2(aq) = CaSO4 + NH3(g) + H2O(l) =>
(NH4)2SO4(aq) + Ca(OH)2(aq) = CaSO4 + 2 NH3(g) + 2 H2O(l)

Na2CO3 + HCl = CO2 + H2O + NaCl =>
Na2CO3 + 2 HCl = CO2 + H2O + 2 NaCl

K3PO4 + Ca(NO3)2 = KNO3 + Ca3(PO4)2 =>
2 K3PO4 + 3 Ca(NO3)2 = 6 KNO3 + Ca3(PO4)2

C2H5OH + Na(OCl) = CHCl3 + Na(O[CO]H) + NaCl + H2O =>
2 C2H5OH + 8 Na(OCl) = CHCl3 + 3 Na(O[CO]H) + 5 NaCl + 4 H2O

CH3OH + I2 + P4 = CH3I + H3PO4 + H2O =>
20 CH3OH + 10 I2 + P4 = 20 CH3I + 4 H3PO4 + 4 H2O

C2H6O + O2 = CO2 + H2O =>
C2H6O + 3 O2 = 2 CO2 + 3 H2O

C8H18 + O2 = CO2 + H2O =>
2 C8H18 + 25 O2 = 16 CO2 + 18 H2O

CH3OH + I2 + P4 = CH3I + H3PO4 + H2O =>
20 CH3OH + 10 I2 + P4 = 20 CH3I + 4 H3PO4 + 4 H2O

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Balance equation of any chemical reaction online for free
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Equations balanced on 07/12/09
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