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Chemical Equations Balanced on 05/16/09

 Equations balanced on the previous day Equations balanced on the next day
Balance equation of any chemical reaction online for free
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K2O + CO2 = K2CO3 =>
K2O + CO2 = K2CO3

NaOH + H2SO4 = Na2SO4 + H2O =>
2 NaOH + H2SO4 = Na2SO4 + 2 H2O

C2H2O4 + Fe2O3 = FeO2 + C02 + H2O =>
C2H2O4 + 3 Fe2O3 = 6 FeO2 + C02 + H2O

C2H2O4 + Fe2O3 = FeO2 + C02 + H2O =>
C2H2O4 + 3 Fe2O3 = 6 FeO2 + C02 + H2O

NaHCO3 + H2SO4 = Na2SO4 + H2O + CO2 =>
2 NaHCO3 + H2SO4 = Na2SO4 + 2 H2O + 2 CO2

Fe + CuCl2 = FeCl2 + Cu =>
Fe + CuCl2 = FeCl2 + Cu

Na + H2O = NaOH + H2 =>
2 Na + 2 H2O = 2 NaOH + H2

Fe(NH4)2(SO4)2*6H2O + H2C2O4 + H2O2 + K2C2O4 = KFe(C2O4)2*2H2O + NH4{+} + SO4{2-} + H2O + H{+} =>
2 Fe(NH4)2(SO4)2*6H2O + 3 H2C2O4 + H2O2 + K2C2O4 = 2 KFe(C2O4)2*2H2O + 4 NH4{+} + 4 SO4{2-} + 10 H2O + 4 H{+}

C2H5OH + O2 = CO2 + H2O =>
C2H5OH + 3 O2 = 2 CO2 + 3 H2O

Fe(NH4)2(SO4)2*6H2O + H2C2O4 + K2C2O4 + H2O2 = K3Fe(C2O4)3*3H2O + NH4{+} + SO4{2-} + H2O + H{+} =>
2 Fe(NH4)2(SO4)2*6H2O + 3 H2C2O4 + 3 K2C2O4 + H2O2 = 2 K3Fe(C2O4)3*3H2O + 4 NH4{+} + 4 SO4{2-} + 8 H2O + 4 H{+}

CH4 + O2 = CO2 + H2O =>
CH4 + 2 O2 = CO2 + 2 H2O

K2Cr2O7 + SnCl2 + HCl = KCl + CrCl3 + SnCl4 + H2O =>
K2Cr2O7 + 3 SnCl2 + 14 HCl = 2 KCl + 2 CrCl3 + 3 SnCl4 + 7 H2O

CO2 + H2O = C6H12O6 + O2 =>
6 CO2 + 6 H2O = C6H12O6 + 6 O2

B(OCH3)3 + O2 = H2O + B2O3 + CO2 =>
2 B(OCH3)3 + 9 O2 = 9 H2O + B2O3 + 6 CO2

NaHCO3 + HCl = NaCl + H2O + CO2 =>
NaHCO3 + HCl = NaCl + H2O + CO2

KI + Pb(OH)2 = PbI2 + KOH =>
2 KI + Pb(OH)2 = PbI2 + 2 KOH

Cr2(SO4)3 + H2O = CrSO4 + H2SO4 + O2 =>
2 Cr2(SO4)3 + 2 H2O = 4 CrSO4 + 2 H2SO4 + O2

KMnO4 + H2C2O4 + H2SO4 = K2SO4 + MnSO4 + H2O + CO2 =>
2 KMnO4 + 5 H2C2O4 + 3 H2SO4 = K2SO4 + 2 MnSO4 + 8 H2O + 10 CO2

H2 + I2 = HI =>
H2 + I2 = 2 HI

K3PO4 + HBr = H3PO4 + KBr =>
K3PO4 + 3 HBr = H3PO4 + 3 KBr

KClO3 = KCl + O2 =>
2 KClO3 = 2 KCl + 3 O2

F2 + AlCl3 = AlF3 + Cl2 =>
3 F2 + 2 AlCl3 = 2 AlF3 + 3 Cl2

Mo24O37 + K2Cr2O7 + H2SO4 = MoO3 + K2SO4 + Cr2(SO4)3 + H2O =>
3 Mo24O37 + 35 K2Cr2O7 + 140 H2SO4 = 72 MoO3 + 35 K2SO4 + 35 Cr2(SO4)3 + 140 H2O

KNO3 + BaCl2 = KCl + Ba(NO3)2 =>
2 KNO3 + BaCl2 = 2 KCl + Ba(NO3)2

C6H14 + O2 = CO2 + H2O =>
2 C6H14 + 19 O2 = 12 CO2 + 14 H2O

CH4 + H2O + N2 = NH3 + CO2 =>
3 CH4 + 6 H2O + 4 N2 = 8 NH3 + 3 CO2

CH4 + H2O + N2 = NH3 + CO2 =>
3 CH4 + 6 H2O + 4 N2 = 8 NH3 + 3 CO2

CH4 + H2O + N2 = NH3 + CO2 =>
3 CH4 + 6 H2O + 4 N2 = 8 NH3 + 3 CO2

Fe2O3 + CO = Fe + CO2 =>
Fe2O3 + 3 CO = 2 Fe + 3 CO2

CH4 + O2 = CO + H2O =>
2 CH4 + 3 O2 = 2 CO + 4 H2O

Ca3(PO4)2 + H2SO4 = Ca(H2PO4)2 + CaSO4 =>
Ca3(PO4)2 + 2 H2SO4 = Ca(H2PO4)2 + 2 CaSO4

MnO4{-} + H2C2O4 + H{+} = Mn{2+} + CO2 + H2O =>
2 MnO4{-} + 5 H2C2O4 + 6 H{+} = 2 Mn{2+} + 10 CO2 + 8 H2O

CO2 + H2O = C6H12O6 + O2 =>
6 CO2 + 6 H2O = C6H12O6 + 6 O2

Fe + Cl2 = FeCl3 =>
2 Fe + 3 Cl2 = 2 FeCl3

C6H6 + O2 = H20 + CO2 =>
10 C6H6 + 60 O2 = 3 H20 + 60 CO2

C6H6 + O2 = H2O + CO2 =>
2 C6H6 + 15 O2 = 6 H2O + 12 CO2

H + O = H2O =>
2 H + O = H2O

CO2 + NH3 = NH2CONH2 + H2O =>
CO2 + 2 NH3 = NH2CONH2 + H2O

Fe(OH)3 = Fe2O3 + H2O =>
2 Fe(OH)3 = Fe2O3 + 3 H2O

NH3 + O2 = HNO3 + H2O =>
NH3 + 2 O2 = HNO3 + H2O

K4Fe(CN)6 + KMnO4 + H2SO4 = KHSO4 + Fe2(SO4)3 + MnSO4 + HNO3 + CO2 + H2O =>
10 K4Fe(CN)6 + 122 KMnO4 + 299 H2SO4 = 162 KHSO4 + 5 Fe2(SO4)3 + 122 MnSO4 + 60 HNO3 + 60 CO2 + 188 H2O

HNO3 + Mg(OH)2 = H2O + Mg(NO3)2 =>
2 HNO3 + Mg(OH)2 = 2 H2O + Mg(NO3)2

C2H6 + O2 = CO2 + H2O =>
2 C2H6 + 7 O2 = 4 CO2 + 6 H2O

H3PO4 + NaBr = HBr + Na3PO4 =>
H3PO4 + 3 NaBr = 3 HBr + Na3PO4

Fe2O3 + H2O = Fe(OH)3 =>
Fe2O3 + 3 H2O = 2 Fe(OH)3

C2H2 + H2 = C2H6 =>
C2H2 + 2 H2 = C2H6

VF5 + HL = V2L10 + HF =>
2 VF5 + 10 HL = V2L10 + 10 HF

CF4 + Br2 = CBr4 + F2 =>
CF4 + 2 Br2 = CBr4 + 2 F2

Bi(NO3)3 + H2S = HNO3 + Bi2S3 =>
2 Bi(NO3)3 + 3 H2S = 6 HNO3 + Bi2S3

Hg2L2 + O2 = Hg2O + L2 =>
2 Hg2L2 + O2 = 2 Hg2O + 2 L2

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Balance equation of any chemical reaction online for free
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