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Chemical Equations Balanced on 06/07/13

 Equations balanced on the previous day Equations balanced on the next day
Balance equation of any chemical reaction online for free
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NaClO3 + MnO2 + NaOH = NaCl + Na2MnO4 + H2O =>
NaClO3 + 3 MnO2 + 6 NaOH = NaCl + 3 Na2MnO4 + 3 H2O

PH3 + KMnO4 + H2SO4 = MnSO4 + H3PO4 + K2SO4 + H2O =>
5 PH3 + 8 KMnO4 + 12 H2SO4 = 8 MnSO4 + 5 H3PO4 + 4 K2SO4 + 12 H2O

C3H8O2 + K2Cr2O7 + H2SO4 = C3H6O2 + Cr2(SO4)3 + K2SO4 + H2O =>
3 C3H8O2 + K2Cr2O7 + 4 H2SO4 = 3 C3H6O2 + Cr2(SO4)3 + K2SO4 + 7 H2O

HCl + NH4OH = NH4Cl + H2O =>
HCl + NH4OH = NH4Cl + H2O

KMnO4 + K2SO3 + H2O = MnO2 + K2SO4 + KOH =>
2 KMnO4 + 3 K2SO3 + H2O = 2 MnO2 + 3 K2SO4 + 2 KOH

Ca + O2 = CaO =>
2 Ca + O2 = 2 CaO

C3H6O + K2Cr2O7 + H2SO4 = C3H6O2 + Cr2(SO4)3 + K2SO4 + H2O =>
3 C3H6O + K2Cr2O7 + 4 H2SO4 = 3 C3H6O2 + Cr2(SO4)3 + K2SO4 + 4 H2O

Na2O + H2O = NaOH =>
Na2O + H2O = 2 NaOH

Al2 + O2 = Al2O3 =>
2 Al2 + 3 O2 = 2 Al2O3

Na + Cl2 = NaCl =>
2 Na + Cl2 = 2 NaCl

AgNo3 + Cu = Cu9(No3)2 + Ag =>
2 AgNo3 + 9 Cu = Cu9(No3)2 + 2 Ag

NaCrO2 + PbO2 + NaOH = Na2CrO4 + Na2PbO2 + H2O =>
2 NaCrO2 + 3 PbO2 + 8 NaOH = 2 Na2CrO4 + 3 Na2PbO2 + 4 H2O

AgNo3 + Cu = Cu(No3)2 + Ag =>
2 AgNo3 + Cu = Cu(No3)2 + 2 Ag

PCl3 + H2O = HCl + H3PO3 =>
PCl3 + 3 H2O = 3 HCl + H3PO3

Na2CO3 = Na2O + CO2 =>
Na2CO3 = Na2O + CO2

H2 + O2 = H2O =>
2 H2 + O2 = 2 H2O

FeSO4 + K2Cr2O7 + H2SO4 = Fe2(SO4)3 + Cr2(SO4)3 + K2SO4 + H2O =>
6 FeSO4 + K2Cr2O7 + 7 H2SO4 = 3 Fe2(SO4)3 + Cr2(SO4)3 + K2SO4 + 7 H2O

K + O2 = K2O =>
4 K + O2 = 2 K2O

C4H8 + O2 = CO2 + H2O =>
C4H8 + 6 O2 = 4 CO2 + 4 H2O

Fe2O3 + HCl = FeCl3 + H2O =>
Fe2O3 + 6 HCl = 2 FeCl3 + 3 H2O

NH3 + O2 = NO + H2O =>
4 NH3 + 5 O2 = 4 NO + 6 H2O

CrCl3 + Cl2 + KOH = K2CrO4 + KCl + H2O =>
2 CrCl3 + 3 Cl2 + 16 KOH = 2 K2CrO4 + 12 KCl + 8 H2O

F2 + KBr = KF + Br2 =>
F2 + 2 KBr = 2 KF + Br2

(NH4)3PO4 = H3PO4 + NH3 =>
(NH4)3PO4 = H3PO4 + 3 NH3

Cl2 + S2O3{2-} + HOH = SO4{2-} + H{2} + Cl{-} =>
9 Cl2 + S2O3{2-} + 5 HOH = 2 SO4{2-} + 10 H{2} + 18 Cl{-}

C5H12 + O2 = CO2 + H2O =>
C5H12 + 8 O2 = 5 CO2 + 6 H2O

Cl2 + S2O3{2-} + HOH = SO4{2-} + H{+} + Cl{-} =>
4 Cl2 + S2O3{2-} + 5 HOH = 2 SO4{2-} + 10 H{+} + 8 Cl{-}

NH3 + O2 = NO + H2O =>
4 NH3 + 5 O2 = 4 NO + 6 H2O

HNO3 = NO2 + H2O + O2 =>
4 HNO3 = 4 NO2 + 2 H2O + O2

Cr(OH)2 + NaOH = Na[Cr(OH)3] =>
Cr(OH)2 + NaOH = Na[Cr(OH)3]

Cr2O3 + NaNO3 + NaOH = Na2CrO4 + NaNO2 + H2O =>
Cr2O3 + 3 NaNO3 + 4 NaOH = 2 Na2CrO4 + 3 NaNO2 + 2 H2O

CaCO3(s) + HC(aq) = CaC2(aq) + H2O(l) + CO2(g) =>
CaCO3(s) + 2 HC(aq) = CaC2(aq) + H2O(l) + CO2(g)

As2O3 + HNO3 + H2O = H3AsO4 + NO2 =>
As2O3 + 4 HNO3 + H2O = 2 H3AsO4 + 4 NO2

NaBrO3 + F2 + NaOH = NaBrO4 + NaF + H2O =>
NaBrO3 + F2 + 2 NaOH = NaBrO4 + 2 NaF + H2O

V2O5 + Mn = VO + MnO2 =>
2 V2O5 + 3 Mn = 4 VO + 3 MnO2

NaBrO3 + F2 + NaOH = NaBrO4 + NaF + H2O =>
NaBrO3 + F2 + 2 NaOH = NaBrO4 + 2 NaF + H2O

CaCO3(s) + HCl = CaCl2 + H2O + CO2 =>
CaCO3(s) + 2 HCl = CaCl2 + H2O + CO2

CaCO3 + HCl = CaCl2 + H2O + CO2 =>
CaCO3 + 2 HCl = CaCl2 + H2O + CO2

CrCl3 + KOH + Cl2 = KCl + K2CrO4 + H2O =>
2 CrCl3 + 16 KOH + 3 Cl2 = 12 KCl + 2 K2CrO4 + 8 H2O

CrCl3 + H2O2 + KOH = K2CrO4 + KCl + H2O =>
2 CrCl3 + 3 H2O2 + 10 KOH = 2 K2CrO4 + 6 KCl + 8 H2O

C5H12O + O2 = CO2 + H2O =>
2 C5H12O + 15 O2 = 10 CO2 + 12 H2O

CrCl2(s) + KOH(aq) + Cl2(g) = K2CrO4(aq) + KCl(aq) + H2O(ell) =>
CrCl2(s) + 8 KOH(aq) + 2 Cl2(g) = K2CrO4(aq) + 6 KCl(aq) + 4 H2O(ell)

Na2CrO4 + H2SO4 = Na2Cr2O7 + Na2SO4 + H2O =>
2 Na2CrO4 + H2SO4 = Na2Cr2O7 + Na2SO4 + H2O

CrCl3(s) + KOH(aq) + Cl2(g) = K2CrO4(aq) + KCl(aq) + H2O(ell) =>
2 CrCl3(s) + 16 KOH(aq) + 3 Cl2(g) = 2 K2CrO4(aq) + 12 KCl(aq) + 8 H2O(ell)

Cr(NO3)2 + H2O2 + NaOH = HNO3 + H2O + Na2CrO4 =>
Cr(NO3)2 + 2 H2O2 + 2 NaOH = 2 HNO3 + 2 H2O + Na2CrO4

FeCl3 + NaOH = Fe(OH)3 + NaCl =>
FeCl3 + 3 NaOH = Fe(OH)3 + 3 NaCl

CrCl3 + Cl2 + KOH = K2CrO4 + KCl + H2O =>
2 CrCl3 + 3 Cl2 + 16 KOH = 2 K2CrO4 + 12 KCl + 8 H2O

KI + H2SO4 = H2S + I2 + K2SO4 + H2O =>
8 KI + 5 H2SO4 = H2S + 4 I2 + 4 K2SO4 + 4 H2O

NH4NO3 + KOH = KNO3 + NH3 + H2O =>
NH4NO3 + KOH = KNO3 + NH3 + H2O

Fe + Cl2 = FeCl3 =>
2 Fe + 3 Cl2 = 2 FeCl3

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Balance equation of any chemical reaction online for free
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Equations balanced on 06/07/12
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