Am Vortag ausgeglichene Gleichungen

Am nächsten Tag ausgeglichene Gleichungen

Gleichen Sie die Gleichung jeder chemischen Reaktion ausC₁₂H₂₈O₄Ti + AgNO₃ + C₂H₅OH = AgTiO₂ + O₂ + C₅H₁₁NO₃ + C₄H₉OH =>
4 C₁₂H₂₈O₄Ti + 4 AgNO₃ + 2 C₂H₅OH = 4 AgTiO₂ + O₂ + 4 C₅H₁₁NO₃ + 8 C₄H₉OH

(NH₄)₂CO₃ + AgNO₃ = (NH₄)₂NO₃ + Ag₂CO₃ + CO₂ + H₂O =>
17(NH₄)₂CO₃ + 14 AgNO₃ = 16(NH₄)₂NO₃ + 7 Ag₂CO₃ + 10 CO₂ + 4 H₂O

Cr(CO)₆ + HNO₃ = HCrO₄ + CO₂ + NO + H₂O =>
3 Cr(CO)₆ + 19 HNO₃ = 3 HCrO₄ + 18 CO₂ + 19 NO + 8 H₂O

KClO₃ = KCl + O₂ =>
2 KClO₃ = 2 KCl + 3 O₂

Cl₂(g) + NaOH(aq) = NaCl(aq) + NaClO₃(aq) + H₂O(l) =>
3 Cl₂(g) + 6 NaOH(aq) = 5 NaCl(aq) + NaClO₃(aq) + 3 H₂O(l)

K₂O₂ + H₂SO₄ = K₂SO₄ + H₂O + O₂ =>
2 K₂O₂ + 2 H₂SO₄ = 2 K₂SO₄ + 2 H₂O + O₂

KNO₂ + Zn + KOH + H₂O = NH₃ + K₂[Zn(OH)₄] =>
KNO₂ + 3 Zn + 5 KOH + 5 H₂O = NH₃ + 3 K₂[Zn(OH)₄]

Mg + Cu(SO₄)₂ = Mg(SO₄) + Cu =>
2 Mg + Cu(SO₄)₂ = 2 Mg(SO₄) + Cu

NaNO₃ + PbO = Pb(NO₃)₂ + Na₂O =>
2 NaNO₃ + PbO = Pb(NO₃)₂ + Na₂O

H₃C₆H₅O + NaHCO₃ = Na₃C₆H₅O₇ + H₂O + O₂ =>
2 H₃C₆H₅O + 12 NaHCO₃ = 4 Na₃C₆H₅O₇ + 4 H₂O + 3 O₂

HI(aq) + Li₂S(aq) = LiI(aq) + H₂S(g) =>
2 HI(aq) + Li₂S(aq) = 2 LiI(aq) + H₂S(g)

Cs + Mg = CsMg =>
Cs + Mg = CsMg

HCNO + HBrO = HBrO₃ + HCN =>
2 HCNO + HBrO = HBrO₃ + 2 HCN

BrO₃{-} + H₃O{+} + Zn = Br{-} + H₂O + Zn{2+} =>
BrO₃{-} + 6 H₃O{+} + 3 Zn = Br{-} + 9 H₂O + 3 Zn{2+}

Bi(NO₃)₃ + Na₂(SnO₂) + H₂O = Bi + Na₂(SnO₃) + HNO₃ =>
2 Bi(NO₃)₃ + 3 Na₂(SnO₂) + 3 H₂O = 2 Bi + 3 Na₂(SnO₃) + 6 HNO₃

Pb + ClO₂ = ClPbO₂ =>
Pb + ClO₂ = ClPbO₂

H₂SO₄ + Na₂S₂O₃*5H₂₀ = Na₂S₂O₃ + H₂O + SO₂ =>
50 H₂SO₄ + Na₂S₂O₃*5H₂₀ = Na₂S₂O₃ + 100 H₂O + 50 SO₂

Au₂(CO₃)₃ = Au + CO₃ =>
Au₂(CO₃)₃ = 2 Au + 3 CO₃

CH₄ + NaNH₂ = C₂H₂ + NaNH₃ =>
2 CH₄ + 6 NaNH₂ = C₂H₂ + 6 NaNH₃

KNO₂(aq) + H₂O(l) = KOH(aq) + HNO₂(aq) =>
KNO₂(aq) + H₂O(l) = KOH(aq) + HNO₂(aq)

NaAs + O₂ = NaAsO₂ =>
NaAs + O₂ = NaAsO₂

NaOH + K₂SO₄ = NaSO₄ + K₂OH =>
NaOH + K₂SO₄ = NaSO₄ + K₂OH

AgCl + Ba₃(PO₄)₂ = Ag(PO₄)₂ + ClBa₃ =>
AgCl + Ba₃(PO₄)₂ = Ag(PO₄)₂ + ClBa₃

Na₂CO₃(aq) + (NH₄)₂SO₄(aq) = Na₂SO₄(aq) + (NH₄)₂CO₃(aq) =>
Na₂CO₃(aq) + (NH₄)₂SO₄(aq) = Na₂SO₄(aq) + (NH₄)₂CO₃(aq)

MnO₄{-} + SO₃{2-} + H₂O = Mn{2-} + SO₄{2-} + H{+} =>
2 MnO₄{-} + 9 SO₃{2-} + H₂O = 2 Mn{2-} + 9 SO₄{2-} + 2 H{+}

K₂CO₃ + FeCl₃ + H₂O = KCl + Fe(OH)₃ + CO₂ =>
3 K₂CO₃ + 2 FeCl₃ + 3 H₂O = 6 KCl + 2 Fe(OH)₃ + 3 CO₂

NaJ + NaJO₃ + H₂SO₄ = J₂ + Na₂SO₄ + H₂O =>
5 NaJ + NaJO₃ + 3 H₂SO₄ = 3 J₂ + 3 Na₂SO₄ + 3 H₂O

Mg₃N₂(s) + H₂O(l) = Mg(OH)₂(aq) + NH₃ =>
Mg₃N₂(s) + 6 H₂O(l) = 3 Mg(OH)₂(aq) + 2 NH₃

CaSO₄ + MgCl₂ = MgSO₄ + CaCl₂ =>
CaSO₄ + MgCl₂ = MgSO₄ + CaCl₂

Cl₂(aq) + NaOH(aq) = NaClO₃(aq) + NaCl(aq) + H₂O(l) =>
3 Cl₂(aq) + 6 NaOH(aq) = NaClO₃(aq) + 5 NaCl(aq) + 3 H₂O(l)

FeS(s) + HCl(aq) = FeCl₂(aq) + H₂S(g) =>
FeS(s) + 2 HCl(aq) = FeCl₂(aq) + H₂S(g)

C₃H₄ + NaNH₂ = C₃H₂ + NaNH₃ =>
C₃H₄ + 2 NaNH₂ = C₃H₂ + 2 NaNH₃

NaOH + HNO₃ = NaH + OHNO₃ =>
NaOH + HNO₃ = NaH + OHNO₃

NaH₂PO₂ + Br₂ + H₂O = NaH₂PO₄ + HBr =>
NaH₂PO₂ + 2 Br₂ + 2 H₂O = NaH₂PO₄ + 4 HBr

PlO + NaOH = Na₂PlO₂ + H₂O =>
PlO + 2 NaOH = Na₂PlO₂ + H₂O

NO₂(g) + O₂ + H₂O = HNO₃ =>
4 NO₂(g) + O₂ + 2 H₂O = 4 HNO₃

Zn + HNO₃ = Zn(NO₃)₂ + NH₄NO₃ + H₂O =>
4 Zn + 10 HNO₃ = 4 Zn(NO₃)₂ + NH₄NO₃ + 3 H₂O

Pb(C₂H₃O₂)₂ + Na₂S + CaCl₂ = PbCl₂ + Na(C₂H₃O₂) + SCa =>
Pb(C₂H₃O₂)₂ + Na₂S + CaCl₂ = PbCl₂ + 2 Na(C₂H₃O₂) + SCa

CH₃OH + K₂CrO₇ + H₂SO₄ = HCOOH + Cr₂(SO₄)₃ + K₂SO₄ + H₂O =>
9 CH₃OH + 4 K₂CrO₇ + 10 H₂SO₄ = 9 HCOOH + 2 Cr₂(SO₄)₃ + 4 K₂SO₄ + 19 H₂O

Cr₂O₇₂{-} + SO₃₂{-} + H{+} = Cr₃ + SO₄₂{-} + H₂O =>
60 Cr₂O₇₂{-} + 429 SO₃₂{-} + 60 H{+} = 40 Cr₃ + 429 SO₄₂{-} + 30 H₂O

K₂SO₄(aq) + Ba(OH)₂ = BaSO₄(s) + KOH(aq) =>
K₂SO₄(aq) + Ba(OH)₂ = BaSO₄(s) + 2 KOH(aq)

F + NaBr = FBr + Na =>
F + NaBr = FBr + Na

KHSO₄ + BaOH = KOH + BaHSO₄ =>
KHSO₄ + BaOH = KOH + BaHSO₄

HCl + N₂O₅ = NCl₅ + H₂O =>
10 HCl + N₂O₅ = 2 NCl₅ + 5 H₂O

Cr₂O₃ + Na = NaO + CrO =>
Cr₂O₃ + Na = NaO + 2 CrO

Cr₂₀₇ = Cr₂ =>
2 Cr₂₀₇ = 207 Cr₂

CH₃C₆H₄SO₂Cl + O₂ = SO₂ + Cl₂ + H₂O + CO₂ =>
4 CH₃C₆H₄SO₂Cl + 35 O₂ = 4 SO₂ + 2 Cl₂ + 14 H₂O + 28 CO₂

C₂O₄H₂*H₂O + NaOH = Na + C₂O₄H₂OH + H₂O =>
C₂O₄H₂*H₂O + NaOH = Na + C₂O₄H₂OH + H₂O

S + H₂O = H₃SO₃ + H =>
S + 3 H₂O = H₃SO₃ + 3 H

NH₃ + Br₂ = NH₄Br + NBr₃ =>
4 NH₃ + 3 Br₂ = 3 NH₄Br + NBr₃

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Am Vortag ausgeglichene Gleichungen

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